Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 589 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.Find the compound interest on ₹7600 at 25% per year for 2 years, compounded every year (in ₹).
2. 2.What amount will ₹27000 grow to in 1 year at 8% per year compound interest (in ₹)?
3. 3.What is the difference between the compound interest and the simple interest on ₹18200 at 20% per year for 2 years (in ₹)?
4. 4.A town has 26800 people. The population grows by 15% every year. What will the population be after 1 year?
5. 5.What amount will ₹52900 grow to in 1 year at 12% per year compound interest (in ₹)?
6. 6.What amount will ₹4000 grow to in 3 years at 10% per year compound interest (in ₹)?
7. 7.What amount will ₹2500 grow to in 2 years at 8% per year compound interest (in ₹)?
8. 8.Find the compound interest on ₹19000 at 10% per year for 3 years, compounded every year (in ₹).
9. 9.Find the compound interest on ₹25600 at 25% per year for 2 years, compounded every year (in ₹).
10. 10.Find the compound interest on ₹53300 at 25% per year for 1 year, compounded every year (in ₹).
11. 11.A town has 29000 people. The population grows by 5% every year. What will the population be after 1 year?
12. 12.Find the compound interest on ₹3800 at 4% per year for 1 year, compounded every year (in ₹).
13. 13.What is the difference between the compound interest and the simple interest on ₹57200 at 5% per year for 2 years (in ₹)?
14. 14.What is the difference between the compound interest and the simple interest on ₹2800 at 10% per year for 2 years (in ₹)?
15. 15.Find the compound interest on ₹60000 at 10% per year for 3 years, compounded every year (in ₹).
16. 16.Find the compound interest on ₹41600 at 25% per year for 3 years, compounded every year (in ₹).
17. 17.What amount will ₹30000 grow to in 2 years at 12% per year compound interest (in ₹)?
18. 18.Find the compound interest on ₹31700 at 10% per year for 1 year, compounded every year (in ₹).
19. 19.A scooter is worth ₹22800. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
20. 20.Find the compound interest on ₹31000 at 20% per year for 3 years, compounded every year (in ₹).
21. 21.What is the difference between the compound interest and the simple interest on ₹38600 at 10% per year for 2 years (in ₹)?
22. 22.What amount will ₹37500 grow to in 2 years at 4% per year compound interest (in ₹)?
23. 23.A town has 53200 people. The population grows by 25% every year. What will the population be after 2 years?
24. 24.What is the difference between the compound interest and the simple interest on ₹27500 at 8% per year for 2 years (in ₹)?
25. 25.Find the compound interest on ₹55100 at 20% per year for 2 years, compounded every year (in ₹).
26. 26.A town has 24000 people. The population grows by 5% every year. What will the population be after 1 year?
27. 27.Find the compound interest on ₹53200 at 20% per year for 2 years, compounded every year (in ₹).
28. 28.What is the difference between the compound interest and the simple interest on ₹32800 at 15% per year for 2 years (in ₹)?
29. 29.What is the difference between the compound interest and the simple interest on ₹55000 at 8% per year for 2 years (in ₹)?
30. 30.Find the compound interest on ₹6800 at 5% per year for 1 year, compounded every year (in ₹).
31. 31.What amount will ₹13600 grow to in 2 years at 20% per year compound interest (in ₹)?
32. 32.Find the compound interest on ₹6500 at 20% per year for 3 years, compounded every year (in ₹).
33. 33.A town has 42400 people. The population grows by 25% every year. What will the population be after 2 years?
34. 34.Find the compound interest on ₹17300 at 25% per year for 1 year, compounded every year (in ₹).
35. 35.A scooter is worth ₹41900. Its value falls by 12% every year. What will it be worth after 1 year (in ₹)?
36. 36.What amount will ₹3100 grow to in 1 year at 4% per year compound interest (in ₹)?
37. 37.Find the compound interest on ₹52000 at 20% per year for 2 years, compounded every year (in ₹).
38. 38.What amount will ₹53700 grow to in 1 year at 5% per year compound interest (in ₹)?
39. 39.A town has 26100 people. The population grows by 5% every year. What will the population be after 1 year?
40. 40.A town has 33900 people. The population grows by 20% every year. What will the population be after 1 year?

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