Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 590 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.What amount will ₹11800 grow to in 2 years at 20% per year compound interest (in ₹)?
2. 2.Find the compound interest on ₹17500 at 20% per year for 3 years, compounded every year (in ₹).
3. 3.A town has 3200 people. The population grows by 25% every year. What will the population be after 3 years?
4. 4.Find the compound interest on ₹40000 at 5% per year for 3 years, compounded every year (in ₹).
5. 5.What is the difference between the compound interest and the simple interest on ₹49600 at 20% per year for 2 years (in ₹)?
6. 6.A scooter is worth ₹30000. Its value falls by 4% every year. What will it be worth after 2 years (in ₹)?
7. 7.A scooter is worth ₹28400. Its value falls by 25% every year. What will it be worth after 2 years (in ₹)?
8. 8.What amount will ₹4800 grow to in 1 year at 8% per year compound interest (in ₹)?
9. 9.What amount will ₹53200 grow to in 2 years at 15% per year compound interest (in ₹)?
10. 10.What is the difference between the compound interest and the simple interest on ₹16900 at 10% per year for 2 years (in ₹)?
11. 11.Find the compound interest on ₹41200 at 5% per year for 2 years, compounded every year (in ₹).
12. 12.A town has 48000 people. The population grows by 25% every year. What will the population be after 3 years?
13. 13.Find the compound interest on ₹16000 at 5% per year for 3 years, compounded every year (in ₹).
14. 14.Find the compound interest on ₹57500 at 4% per year for 2 years, compounded every year (in ₹).
15. 15.Find the compound interest on ₹14300 at 10% per year for 2 years, compounded every year (in ₹).
16. 16.A scooter is worth ₹56000. Its value falls by 15% every year. What will it be worth after 3 years (in ₹)?
17. 17.What is the difference between the compound interest and the simple interest on ₹55700 at 10% per year for 2 years (in ₹)?
18. 18.A scooter is worth ₹55000. Its value falls by 8% every year. What will it be worth after 2 years (in ₹)?
19. 19.Find the compound interest on ₹51000 at 20% per year for 3 years, compounded every year (in ₹).
20. 20.A town has 38500 people. The population grows by 10% every year. What will the population be after 2 years?
21. 21.A town has 40800 people. The population grows by 4% every year. What will the population be after 1 year?
22. 22.Find the compound interest on ₹19600 at 15% per year for 2 years, compounded every year (in ₹).
23. 23.What is the difference between the compound interest and the simple interest on ₹26000 at 25% per year for 2 years (in ₹)?
24. 24.What amount will ₹28400 grow to in 1 year at 5% per year compound interest (in ₹)?
25. 25.A scooter is worth ₹53400. Its value falls by 8% every year. What will it be worth after 1 year (in ₹)?
26. 26.A town has 14400 people. The population grows by 25% every year. What will the population be after 3 years?
27. 27.What amount will ₹52200 grow to in 2 years at 20% per year compound interest (in ₹)?
28. 28.Find the compound interest on ₹40000 at 12% per year for 2 years, compounded every year (in ₹).
29. 29.Find the compound interest on ₹30000 at 12% per year for 2 years, compounded every year (in ₹).
30. 30.What amount will ₹20300 grow to in 1 year at 12% per year compound interest (in ₹)?
31. 31.What is the difference between the compound interest and the simple interest on ₹10000 at 8% per year for 2 years (in ₹)?
32. 32.What is the difference between the compound interest and the simple interest on ₹5200 at 10% per year for 2 years (in ₹)?
33. 33.What is the difference between the compound interest and the simple interest on ₹50400 at 5% per year for 2 years (in ₹)?
34. 34.Find the compound interest on ₹48000 at 25% per year for 1 year, compounded every year (in ₹).
35. 35.Find the compound interest on ₹55600 at 15% per year for 2 years, compounded every year (in ₹).
36. 36.A scooter is worth ₹15600. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
37. 37.What amount will ₹36800 grow to in 3 years at 25% per year compound interest (in ₹)?
38. 38.What amount will ₹23700 grow to in 1 year at 10% per year compound interest (in ₹)?
39. 39.What is the difference between the compound interest and the simple interest on ₹10900 at 10% per year for 2 years (in ₹)?
40. 40.Find the compound interest on ₹2100 at 10% per year for 2 years, compounded every year (in ₹).

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