Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 604 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.What amount will ₹1600 grow to in 3 years at 25% per year compound interest (in ₹)?
2. 2.What amount will ₹57000 grow to in 3 years at 10% per year compound interest (in ₹)?
3. 3.What is the difference between the compound interest and the simple interest on ₹3800 at 20% per year for 2 years (in ₹)?
4. 4.A scooter is worth ₹41800. Its value falls by 20% every year. What will it be worth after 2 years (in ₹)?
5. 5.A scooter is worth ₹40000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
6. 6.A town has 21500 people. The population grows by 4% every year. What will the population be after 1 year?
7. 7.Find the compound interest on ₹42800 at 25% per year for 2 years, compounded every year (in ₹).
8. 8.What is the difference between the compound interest and the simple interest on ₹20900 at 20% per year for 2 years (in ₹)?
9. 9.Find the compound interest on ₹34000 at 15% per year for 1 year, compounded every year (in ₹).
10. 10.What amount will ₹2000 grow to in 3 years at 20% per year compound interest (in ₹)?
11. 11.What amount will ₹4000 grow to in 2 years at 25% per year compound interest (in ₹)?
12. 12.What is the difference between the compound interest and the simple interest on ₹24800 at 15% per year for 2 years (in ₹)?
13. 13.What is the difference between the compound interest and the simple interest on ₹8000 at 15% per year for 2 years (in ₹)?
14. 14.A scooter is worth ₹32000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
15. 15.What is the difference between the compound interest and the simple interest on ₹15000 at 4% per year for 2 years (in ₹)?
16. 16.A scooter is worth ₹10000. Its value falls by 10% every year. What will it be worth after 3 years (in ₹)?
17. 17.A town has 10000 people. The population grows by 4% every year. What will the population be after 2 years?
18. 18.Find the compound interest on ₹9500 at 10% per year for 1 year, compounded every year (in ₹).
19. 19.What is the difference between the compound interest and the simple interest on ₹57600 at 20% per year for 2 years (in ₹)?
20. 20.What is the difference between the compound interest and the simple interest on ₹33400 at 10% per year for 2 years (in ₹)?
21. 21.Find the compound interest on ₹57500 at 8% per year for 2 years, compounded every year (in ₹).
22. 22.What amount will ₹6100 grow to in 1 year at 10% per year compound interest (in ₹)?
23. 23.What amount will ₹53900 grow to in 1 year at 5% per year compound interest (in ₹)?
24. 24.What amount will ₹26000 grow to in 3 years at 10% per year compound interest (in ₹)?
25. 25.Find the compound interest on ₹34700 at 10% per year for 1 year, compounded every year (in ₹).
26. 26.Find the compound interest on ₹30000 at 10% per year for 3 years, compounded every year (in ₹).
27. 27.Find the compound interest on ₹10900 at 10% per year for 2 years, compounded every year (in ₹).
28. 28.A town has 33700 people. The population grows by 12% every year. What will the population be after 1 year?
29. 29.What is the difference between the compound interest and the simple interest on ₹10000 at 4% per year for 2 years (in ₹)?
30. 30.What amount will ₹14000 grow to in 2 years at 15% per year compound interest (in ₹)?
31. 31.What is the difference between the compound interest and the simple interest on ₹5200 at 25% per year for 2 years (in ₹)?
32. 32.What amount will ₹35000 grow to in 2 years at 12% per year compound interest (in ₹)?
33. 33.Find the compound interest on ₹52800 at 25% per year for 1 year, compounded every year (in ₹).
34. 34.A town has 26000 people. The population grows by 5% every year. What will the population be after 1 year?
35. 35.What amount will ₹43500 grow to in 1 year at 8% per year compound interest (in ₹)?
36. 36.Find the compound interest on ₹46400 at 15% per year for 1 year, compounded every year (in ₹).
37. 37.Find the compound interest on ₹46200 at 5% per year for 1 year, compounded every year (in ₹).
38. 38.A town has 31500 people. The population grows by 8% every year. What will the population be after 1 year?
39. 39.What amount will ₹40000 grow to in 2 years at 4% per year compound interest (in ₹)?
40. 40.A scooter is worth ₹27400. Its value falls by 15% every year. What will it be worth after 1 year (in ₹)?

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