Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 605 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.Find the compound interest on ₹7900 at 10% per year for 1 year, compounded every year (in ₹).
2. 2.What is the difference between the compound interest and the simple interest on ₹40000 at 12% per year for 2 years (in ₹)?
3. 3.Find the compound interest on ₹32000 at 5% per year for 3 years, compounded every year (in ₹).
4. 4.A town has 10800 people. The population grows by 25% every year. What will the population be after 2 years?
5. 5.Find the compound interest on ₹58700 at 10% per year for 2 years, compounded every year (in ₹).
6. 6.What is the difference between the compound interest and the simple interest on ₹56800 at 10% per year for 2 years (in ₹)?
7. 7.What is the difference between the compound interest and the simple interest on ₹14400 at 15% per year for 2 years (in ₹)?
8. 8.Find the compound interest on ₹45000 at 10% per year for 3 years, compounded every year (in ₹).
9. 9.What amount will ₹16500 grow to in 1 year at 4% per year compound interest (in ₹)?
10. 10.What is the difference between the compound interest and the simple interest on ₹51600 at 15% per year for 2 years (in ₹)?
11. 11.A scooter is worth ₹32000. Its value falls by 15% every year. What will it be worth after 3 years (in ₹)?
12. 12.What is the difference between the compound interest and the simple interest on ₹60000 at 12% per year for 2 years (in ₹)?
13. 13.Find the compound interest on ₹7000 at 10% per year for 1 year, compounded every year (in ₹).
14. 14.Find the compound interest on ₹40000 at 5% per year for 3 years, compounded every year (in ₹).
15. 15.A town has 18000 people. The population grows by 5% every year. What will the population be after 2 years?
16. 16.What amount will ₹50400 grow to in 1 year at 25% per year compound interest (in ₹)?
17. 17.A town has 47000 people. The population grows by 10% every year. What will the population be after 3 years?
18. 18.What is the difference between the compound interest and the simple interest on ₹50000 at 4% per year for 2 years (in ₹)?
19. 19.Find the compound interest on ₹52400 at 5% per year for 1 year, compounded every year (in ₹).
20. 20.What is the difference between the compound interest and the simple interest on ₹40000 at 15% per year for 2 years (in ₹)?
21. 21.Find the compound interest on ₹40000 at 15% per year for 3 years, compounded every year (in ₹).
22. 22.What amount will ₹13500 grow to in 3 years at 20% per year compound interest (in ₹)?
23. 23.Find the compound interest on ₹24000 at 5% per year for 3 years, compounded every year (in ₹).
24. 24.What amount will ₹22500 grow to in 2 years at 12% per year compound interest (in ₹)?
25. 25.What is the difference between the compound interest and the simple interest on ₹33600 at 5% per year for 2 years (in ₹)?
26. 26.A town has 40000 people. The population grows by 20% every year. What will the population be after 1 year?
27. 27.What amount will ₹5000 grow to in 2 years at 12% per year compound interest (in ₹)?
28. 28.What is the difference between the compound interest and the simple interest on ₹35600 at 10% per year for 2 years (in ₹)?
29. 29.What is the difference between the compound interest and the simple interest on ₹42500 at 10% per year for 2 years (in ₹)?
30. 30.What amount will ₹9200 grow to in 2 years at 15% per year compound interest (in ₹)?
31. 31.Find the compound interest on ₹33200 at 10% per year for 2 years, compounded every year (in ₹).
32. 32.Find the compound interest on ₹56000 at 5% per year for 3 years, compounded every year (in ₹).
33. 33.A scooter is worth ₹11000. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
34. 34.What is the difference between the compound interest and the simple interest on ₹46500 at 10% per year for 2 years (in ₹)?
35. 35.A town has 25600 people. The population grows by 25% every year. What will the population be after 3 years?
36. 36.Find the compound interest on ₹24000 at 5% per year for 2 years, compounded every year (in ₹).
37. 37.Find the compound interest on ₹42400 at 5% per year for 1 year, compounded every year (in ₹).
38. 38.What is the difference between the compound interest and the simple interest on ₹8400 at 15% per year for 2 years (in ₹)?
39. 39.A scooter is worth ₹38500. Its value falls by 15% every year. What will it be worth after 1 year (in ₹)?
40. 40.Find the compound interest on ₹4300 at 8% per year for 1 year, compounded every year (in ₹).

Free maths worksheets lessons, practice and worksheets at talentjr.in/maths-worksheets