Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 606 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.A town has 15700 people. The population grows by 10% every year. What will the population be after 1 year?
2. 2.What is the difference between the compound interest and the simple interest on ₹5000 at 8% per year for 2 years (in ₹)?
3. 3.A town has 23500 people. The population grows by 20% every year. What will the population be after 1 year?
4. 4.A scooter is worth ₹32300. Its value falls by 4% every year. What will it be worth after 1 year (in ₹)?
5. 5.A town has 52400 people. The population grows by 15% every year. What will the population be after 2 years?
6. 6.A scooter is worth ₹20800. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
7. 7.Find the compound interest on ₹53000 at 20% per year for 1 year, compounded every year (in ₹).
8. 8.Find the compound interest on ₹19200 at 25% per year for 3 years, compounded every year (in ₹).
9. 9.What amount will ₹18100 grow to in 2 years at 20% per year compound interest (in ₹)?
10. 10.What is the difference between the compound interest and the simple interest on ₹42500 at 12% per year for 2 years (in ₹)?
11. 11.What amount will ₹56000 grow to in 3 years at 25% per year compound interest (in ₹)?
12. 12.What is the difference between the compound interest and the simple interest on ₹27700 at 20% per year for 2 years (in ₹)?
13. 13.What amount will ₹35000 grow to in 2 years at 8% per year compound interest (in ₹)?
14. 14.Find the compound interest on ₹14500 at 4% per year for 1 year, compounded every year (in ₹).
15. 15.Find the compound interest on ₹2300 at 5% per year for 1 year, compounded every year (in ₹).
16. 16.Find the compound interest on ₹40000 at 5% per year for 3 years, compounded every year (in ₹).
17. 17.What amount will ₹37500 grow to in 2 years at 12% per year compound interest (in ₹)?
18. 18.Find the compound interest on ₹25000 at 8% per year for 2 years, compounded every year (in ₹).
19. 19.What amount will ₹44300 grow to in 1 year at 10% per year compound interest (in ₹)?
20. 20.Find the compound interest on ₹24000 at 15% per year for 3 years, compounded every year (in ₹).
21. 21.What amount will ₹55000 grow to in 2 years at 12% per year compound interest (in ₹)?
22. 22.What is the difference between the compound interest and the simple interest on ₹40000 at 12% per year for 2 years (in ₹)?
23. 23.A town has 2500 people. The population grows by 12% every year. What will the population be after 2 years?
24. 24.Find the compound interest on ₹16600 at 20% per year for 2 years, compounded every year (in ₹).
25. 25.What amount will ₹34200 grow to in 2 years at 20% per year compound interest (in ₹)?
26. 26.Find the compound interest on ₹56500 at 20% per year for 1 year, compounded every year (in ₹).
27. 27.A scooter is worth ₹45000. Its value falls by 4% every year. What will it be worth after 2 years (in ₹)?
28. 28.What is the difference between the compound interest and the simple interest on ₹40400 at 25% per year for 2 years (in ₹)?
29. 29.What is the difference between the compound interest and the simple interest on ₹10500 at 20% per year for 2 years (in ₹)?
30. 30.What is the difference between the compound interest and the simple interest on ₹5000 at 4% per year for 2 years (in ₹)?
31. 31.What is the difference between the compound interest and the simple interest on ₹12000 at 25% per year for 2 years (in ₹)?
32. 32.Find the compound interest on ₹15100 at 4% per year for 1 year, compounded every year (in ₹).
33. 33.A town has 30700 people. The population grows by 20% every year. What will the population be after 1 year?
34. 34.A town has 29300 people. The population grows by 12% every year. What will the population be after 1 year?
35. 35.Find the compound interest on ₹48200 at 10% per year for 1 year, compounded every year (in ₹).
36. 36.Find the compound interest on ₹37500 at 12% per year for 2 years, compounded every year (in ₹).
37. 37.What is the difference between the compound interest and the simple interest on ₹10000 at 5% per year for 2 years (in ₹)?
38. 38.A scooter is worth ₹32000. Its value falls by 25% every year. What will it be worth after 3 years (in ₹)?
39. 39.Find the compound interest on ₹14700 at 10% per year for 1 year, compounded every year (in ₹).
40. 40.What amount will ₹5000 grow to in 2 years at 4% per year compound interest (in ₹)?

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