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Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 609 · 40 sums
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The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

NameDateTime takenScore ___ / 40
  1. 1.What is the difference between the compound interest and the simple interest on ₹45600 at 20% per year for 2 years (in ₹)?
  2. 2.What amount will ₹28000 grow to in 3 years at 10% per year compound interest (in ₹)?
  3. 3.Find the compound interest on ₹27400 at 20% per year for 2 years, compounded every year (in ₹).
  4. 4.What amount will ₹12500 grow to in 3 years at 20% per year compound interest (in ₹)?
  5. 5.What amount will ₹9400 grow to in 1 year at 20% per year compound interest (in ₹)?
  6. 6.Find the compound interest on ₹3200 at 25% per year for 3 years, compounded every year (in ₹).
  7. 7.Find the compound interest on ₹16100 at 12% per year for 1 year, compounded every year (in ₹).
  8. 8.What is the difference between the compound interest and the simple interest on ₹5600 at 15% per year for 2 years (in ₹)?
  9. 9.A town has 54800 people. The population grows by 5% every year. What will the population be after 2 years?
  10. 10.What is the difference between the compound interest and the simple interest on ₹57500 at 4% per year for 2 years (in ₹)?
  11. 11.Find the compound interest on ₹42500 at 20% per year for 2 years, compounded every year (in ₹).
  12. 12.What is the difference between the compound interest and the simple interest on ₹53700 at 20% per year for 2 years (in ₹)?
  13. 13.What amount will ₹15000 grow to in 3 years at 10% per year compound interest (in ₹)?
  14. 14.What amount will ₹18000 grow to in 2 years at 15% per year compound interest (in ₹)?
  15. 15.Find the compound interest on ₹16000 at 15% per year for 3 years, compounded every year (in ₹).
  16. 16.A scooter is worth ₹19000. Its value falls by 8% every year. What will it be worth after 1 year (in ₹)?
  17. 17.Find the compound interest on ₹59500 at 8% per year for 1 year, compounded every year (in ₹).
  18. 18.What is the difference between the compound interest and the simple interest on ₹60000 at 4% per year for 2 years (in ₹)?
  19. 19.A town has 53800 people. The population grows by 10% every year. What will the population be after 2 years?
  20. 20.What is the difference between the compound interest and the simple interest on ₹35400 at 10% per year for 2 years (in ₹)?
  21. 21.A scooter is worth ₹23100. Its value falls by 10% every year. What will it be worth after 2 years (in ₹)?
  22. 22.A scooter is worth ₹50200. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
  23. 23.A scooter is worth ₹23500. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
  24. 24.A scooter is worth ₹4800. Its value falls by 25% every year. What will it be worth after 3 years (in ₹)?
  25. 25.Find the compound interest on ₹3400 at 20% per year for 2 years, compounded every year (in ₹).
  26. 26.Find the compound interest on ₹45600 at 15% per year for 2 years, compounded every year (in ₹).
  27. 27.What is the difference between the compound interest and the simple interest on ₹40700 at 20% per year for 2 years (in ₹)?
  28. 28.What amount will ₹24500 grow to in 2 years at 10% per year compound interest (in ₹)?
  29. 29.What is the difference between the compound interest and the simple interest on ₹29100 at 20% per year for 2 years (in ₹)?
  30. 30.A town has 45200 people. The population grows by 4% every year. What will the population be after 1 year?
  31. 31.A town has 4800 people. The population grows by 25% every year. What will the population be after 3 years?
  32. 32.What amount will ₹21400 grow to in 1 year at 5% per year compound interest (in ₹)?
  33. 33.Find the compound interest on ₹16800 at 5% per year for 2 years, compounded every year (in ₹).
  34. 34.Find the compound interest on ₹52500 at 4% per year for 2 years, compounded every year (in ₹).
  35. 35.What is the difference between the compound interest and the simple interest on ₹17500 at 4% per year for 2 years (in ₹)?
  36. 36.What amount will ₹30400 grow to in 1 year at 4% per year compound interest (in ₹)?
  37. 37.Find the compound interest on ₹13600 at 25% per year for 2 years, compounded every year (in ₹).
  38. 38.What is the difference between the compound interest and the simple interest on ₹19200 at 15% per year for 2 years (in ₹)?
  39. 39.What amount will ₹40000 grow to in 3 years at 15% per year compound interest (in ₹)?
  40. 40.A town has 10000 people. The population grows by 4% every year. What will the population be after 2 years?

Answer key

  1. 1824
  2. 37268
  3. 12056
  4. 21600
  5. 11280
  6. 3050
  7. 1932
  8. 126
  9. 60417
  10. 92
  11. 18700
  12. 2148
  13. 19965
  14. 23805
  15. 8334
  16. 17480
  17. 4760
  18. 96
  19. 65098
  20. 354
  21. 18711
  22. 47690
  23. 22325
  24. 2025
  25. 1496
  26. 14706
  27. 1628
  28. 29645
  29. 1164
  30. 47008
  31. 9375
  32. 22470
  33. 1722
  34. 4284
  35. 28
  36. 31616
  37. 7650
  38. 432
  39. 60835
  40. 10816

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