Class 8 Maths Worksheet: Compound Interest
The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.
NameDateTime takenScore ___ / 40
- 1.What is the difference between the compound interest and the simple interest on ₹45600 at 20% per year for 2 years (in ₹)?
- 2.What amount will ₹28000 grow to in 3 years at 10% per year compound interest (in ₹)?
- 3.Find the compound interest on ₹27400 at 20% per year for 2 years, compounded every year (in ₹).
- 4.What amount will ₹12500 grow to in 3 years at 20% per year compound interest (in ₹)?
- 5.What amount will ₹9400 grow to in 1 year at 20% per year compound interest (in ₹)?
- 6.Find the compound interest on ₹3200 at 25% per year for 3 years, compounded every year (in ₹).
- 7.Find the compound interest on ₹16100 at 12% per year for 1 year, compounded every year (in ₹).
- 8.What is the difference between the compound interest and the simple interest on ₹5600 at 15% per year for 2 years (in ₹)?
- 9.A town has 54800 people. The population grows by 5% every year. What will the population be after 2 years?
- 10.What is the difference between the compound interest and the simple interest on ₹57500 at 4% per year for 2 years (in ₹)?
- 11.Find the compound interest on ₹42500 at 20% per year for 2 years, compounded every year (in ₹).
- 12.What is the difference between the compound interest and the simple interest on ₹53700 at 20% per year for 2 years (in ₹)?
- 13.What amount will ₹15000 grow to in 3 years at 10% per year compound interest (in ₹)?
- 14.What amount will ₹18000 grow to in 2 years at 15% per year compound interest (in ₹)?
- 15.Find the compound interest on ₹16000 at 15% per year for 3 years, compounded every year (in ₹).
- 16.A scooter is worth ₹19000. Its value falls by 8% every year. What will it be worth after 1 year (in ₹)?
- 17.Find the compound interest on ₹59500 at 8% per year for 1 year, compounded every year (in ₹).
- 18.What is the difference between the compound interest and the simple interest on ₹60000 at 4% per year for 2 years (in ₹)?
- 19.A town has 53800 people. The population grows by 10% every year. What will the population be after 2 years?
- 20.What is the difference between the compound interest and the simple interest on ₹35400 at 10% per year for 2 years (in ₹)?
- 21.A scooter is worth ₹23100. Its value falls by 10% every year. What will it be worth after 2 years (in ₹)?
- 22.A scooter is worth ₹50200. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
- 23.A scooter is worth ₹23500. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
- 24.A scooter is worth ₹4800. Its value falls by 25% every year. What will it be worth after 3 years (in ₹)?
- 25.Find the compound interest on ₹3400 at 20% per year for 2 years, compounded every year (in ₹).
- 26.Find the compound interest on ₹45600 at 15% per year for 2 years, compounded every year (in ₹).
- 27.What is the difference between the compound interest and the simple interest on ₹40700 at 20% per year for 2 years (in ₹)?
- 28.What amount will ₹24500 grow to in 2 years at 10% per year compound interest (in ₹)?
- 29.What is the difference between the compound interest and the simple interest on ₹29100 at 20% per year for 2 years (in ₹)?
- 30.A town has 45200 people. The population grows by 4% every year. What will the population be after 1 year?
- 31.A town has 4800 people. The population grows by 25% every year. What will the population be after 3 years?
- 32.What amount will ₹21400 grow to in 1 year at 5% per year compound interest (in ₹)?
- 33.Find the compound interest on ₹16800 at 5% per year for 2 years, compounded every year (in ₹).
- 34.Find the compound interest on ₹52500 at 4% per year for 2 years, compounded every year (in ₹).
- 35.What is the difference between the compound interest and the simple interest on ₹17500 at 4% per year for 2 years (in ₹)?
- 36.What amount will ₹30400 grow to in 1 year at 4% per year compound interest (in ₹)?
- 37.Find the compound interest on ₹13600 at 25% per year for 2 years, compounded every year (in ₹).
- 38.What is the difference between the compound interest and the simple interest on ₹19200 at 15% per year for 2 years (in ₹)?
- 39.What amount will ₹40000 grow to in 3 years at 15% per year compound interest (in ₹)?
- 40.A town has 10000 people. The population grows by 4% every year. What will the population be after 2 years?
Answer key
- 1824
- 37268
- 12056
- 21600
- 11280
- 3050
- 1932
- 126
- 60417
- 92
- 18700
- 2148
- 19965
- 23805
- 8334
- 17480
- 4760
- 96
- 65098
- 354
- 18711
- 47690
- 22325
- 2025
- 1496
- 14706
- 1628
- 29645
- 1164
- 47008
- 9375
- 22470
- 1722
- 4284
- 28
- 31616
- 7650
- 432
- 60835
- 10816
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