Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 610 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.Find the compound interest on ₹48000 at 15% per year for 3 years, compounded every year (in ₹).
2. 2.A town has 53600 people. The population grows by 15% every year. What will the population be after 2 years?
3. 3.What is the difference between the compound interest and the simple interest on ₹35000 at 8% per year for 2 years (in ₹)?
4. 4.What is the difference between the compound interest and the simple interest on ₹53200 at 5% per year for 2 years (in ₹)?
5. 5.What amount will ₹38500 grow to in 1 year at 5% per year compound interest (in ₹)?
6. 6.What is the difference between the compound interest and the simple interest on ₹51900 at 20% per year for 2 years (in ₹)?
7. 7.Find the compound interest on ₹10000 at 10% per year for 3 years, compounded every year (in ₹).
8. 8.Find the compound interest on ₹30500 at 20% per year for 1 year, compounded every year (in ₹).
9. 9.What is the difference between the compound interest and the simple interest on ₹2500 at 12% per year for 2 years (in ₹)?
10. 10.What is the difference between the compound interest and the simple interest on ₹41600 at 5% per year for 2 years (in ₹)?
11. 11.What is the difference between the compound interest and the simple interest on ₹4300 at 10% per year for 2 years (in ₹)?
12. 12.What amount will ₹8600 grow to in 1 year at 15% per year compound interest (in ₹)?
13. 13.A town has 45400 people. The population grows by 5% every year. What will the population be after 1 year?
14. 14.What amount will ₹53100 grow to in 1 year at 20% per year compound interest (in ₹)?
15. 15.What is the difference between the compound interest and the simple interest on ₹11200 at 15% per year for 2 years (in ₹)?
16. 16.A town has 51000 people. The population grows by 20% every year. What will the population be after 1 year?
17. 17.A scooter is worth ₹22500. Its value falls by 8% every year. What will it be worth after 2 years (in ₹)?
18. 18.A town has 32500 people. The population grows by 25% every year. What will the population be after 1 year?
19. 19.Find the compound interest on ₹40000 at 4% per year for 2 years, compounded every year (in ₹).
20. 20.What amount will ₹30500 grow to in 1 year at 12% per year compound interest (in ₹)?
21. 21.Find the compound interest on ₹11200 at 25% per year for 3 years, compounded every year (in ₹).
22. 22.What is the difference between the compound interest and the simple interest on ₹30000 at 20% per year for 2 years (in ₹)?
23. 23.What amount will ₹20000 grow to in 1 year at 10% per year compound interest (in ₹)?
24. 24.A scooter is worth ₹47500. Its value falls by 8% every year. What will it be worth after 2 years (in ₹)?
25. 25.Find the compound interest on ₹4400 at 25% per year for 2 years, compounded every year (in ₹).
26. 26.Find the compound interest on ₹47500 at 8% per year for 2 years, compounded every year (in ₹).
27. 27.What is the difference between the compound interest and the simple interest on ₹27500 at 4% per year for 2 years (in ₹)?
28. 28.What amount will ₹18300 grow to in 1 year at 4% per year compound interest (in ₹)?
29. 29.Find the compound interest on ₹47900 at 8% per year for 1 year, compounded every year (in ₹).
30. 30.Find the compound interest on ₹14300 at 4% per year for 1 year, compounded every year (in ₹).
31. 31.A town has 16000 people. The population grows by 25% every year. What will the population be after 3 years?
32. 32.What amount will ₹7200 grow to in 1 year at 5% per year compound interest (in ₹)?
33. 33.Find the compound interest on ₹31400 at 25% per year for 1 year, compounded every year (in ₹).
34. 34.What amount will ₹22400 grow to in 3 years at 25% per year compound interest (in ₹)?
35. 35.What amount will ₹5000 grow to in 2 years at 4% per year compound interest (in ₹)?
36. 36.Find the compound interest on ₹34400 at 5% per year for 1 year, compounded every year (in ₹).
37. 37.Find the compound interest on ₹50300 at 12% per year for 1 year, compounded every year (in ₹).
38. 38.Find the compound interest on ₹40000 at 5% per year for 3 years, compounded every year (in ₹).
39. 39.What is the difference between the compound interest and the simple interest on ₹7500 at 8% per year for 2 years (in ₹)?
40. 40.What amount will ₹13600 grow to in 1 year at 5% per year compound interest (in ₹)?

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