Class 8 Maths Worksheet: Compound Interest
The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.
NameDateTime takenScore ___ / 40
- 1.Find the compound interest on ₹27500 at 8% per year for 2 years, compounded every year (in ₹).
- 2.Find the compound interest on ₹46100 at 25% per year for 1 year, compounded every year (in ₹).
- 3.What amount will ₹37500 grow to in 2 years at 12% per year compound interest (in ₹)?
- 4.Find the compound interest on ₹13400 at 10% per year for 2 years, compounded every year (in ₹).
- 5.What amount will ₹32200 grow to in 1 year at 5% per year compound interest (in ₹)?
- 6.What is the difference between the compound interest and the simple interest on ₹20000 at 8% per year for 2 years (in ₹)?
- 7.Find the compound interest on ₹25000 at 10% per year for 3 years, compounded every year (in ₹).
- 8.What is the difference between the compound interest and the simple interest on ₹31300 at 10% per year for 2 years (in ₹)?
- 9.A town has 48000 people. The population grows by 15% every year. What will the population be after 3 years?
- 10.A scooter is worth ₹57600. Its value falls by 25% every year. What will it be worth after 3 years (in ₹)?
- 11.What is the difference between the compound interest and the simple interest on ₹10000 at 4% per year for 2 years (in ₹)?
- 12.What amount will ₹47800 grow to in 1 year at 20% per year compound interest (in ₹)?
- 13.Find the compound interest on ₹53000 at 10% per year for 3 years, compounded every year (in ₹).
- 14.A scooter is worth ₹12000. Its value falls by 10% every year. What will it be worth after 3 years (in ₹)?
- 15.A town has 31000 people. The population grows by 10% every year. What will the population be after 3 years?
- 16.Find the compound interest on ₹25000 at 8% per year for 2 years, compounded every year (in ₹).
- 17.What amount will ₹30000 grow to in 2 years at 15% per year compound interest (in ₹)?
- 18.What is the difference between the compound interest and the simple interest on ₹12500 at 8% per year for 2 years (in ₹)?
- 19.What is the difference between the compound interest and the simple interest on ₹5000 at 12% per year for 2 years (in ₹)?
- 20.A town has 53100 people. The population grows by 20% every year. What will the population be after 2 years?
- 21.What is the difference between the compound interest and the simple interest on ₹37500 at 8% per year for 2 years (in ₹)?
- 22.What amount will ₹19200 grow to in 3 years at 25% per year compound interest (in ₹)?
- 23.Find the compound interest on ₹18800 at 25% per year for 2 years, compounded every year (in ₹).
- 24.What is the difference between the compound interest and the simple interest on ₹14000 at 25% per year for 2 years (in ₹)?
- 25.What amount will ₹31600 grow to in 1 year at 20% per year compound interest (in ₹)?
- 26.A town has 13700 people. The population grows by 10% every year. What will the population be after 1 year?
- 27.A scooter is worth ₹42500. Its value falls by 20% every year. What will it be worth after 1 year (in ₹)?
- 28.Find the compound interest on ₹4000 at 20% per year for 2 years, compounded every year (in ₹).
- 29.Find the compound interest on ₹8000 at 20% per year for 3 years, compounded every year (in ₹).
- 30.What is the difference between the compound interest and the simple interest on ₹2500 at 12% per year for 2 years (in ₹)?
- 31.What is the difference between the compound interest and the simple interest on ₹2000 at 5% per year for 2 years (in ₹)?
- 32.What amount will ₹8400 grow to in 1 year at 10% per year compound interest (in ₹)?
- 33.A scooter is worth ₹47500. Its value falls by 8% every year. What will it be worth after 2 years (in ₹)?
- 34.What amount will ₹30900 grow to in 1 year at 20% per year compound interest (in ₹)?
- 35.What amount will ₹5200 grow to in 1 year at 8% per year compound interest (in ₹)?
- 36.A scooter is worth ₹52500. Its value falls by 12% every year. What will it be worth after 2 years (in ₹)?
- 37.What amount will ₹22500 grow to in 2 years at 12% per year compound interest (in ₹)?
- 38.A scooter is worth ₹19500. Its value falls by 20% every year. What will it be worth after 1 year (in ₹)?
- 39.What is the difference between the compound interest and the simple interest on ₹42500 at 8% per year for 2 years (in ₹)?
- 40.What amount will ₹50000 grow to in 2 years at 4% per year compound interest (in ₹)?
Answer key
- 4576
- 11525
- 47040
- 2814
- 33810
- 128
- 8275
- 313
- 73002
- 24300
- 16
- 57360
- 17543
- 8748
- 41261
- 4160
- 39675
- 80
- 72
- 76464
- 240
- 37500
- 10575
- 875
- 37920
- 15070
- 34000
- 1760
- 5824
- 36
- 5
- 9240
- 40204
- 37080
- 5616
- 40656
- 28224
- 15600
- 272
- 54080
Free maths worksheets lessons, practice and worksheets at talentjr.in/maths-worksheets