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Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 614 · 40 sums
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The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

NameDateTime takenScore ___ / 40
  1. 1.A scooter is worth ₹40000. Its value falls by 4% every year. What will it be worth after 2 years (in ₹)?
  2. 2.What amount will ₹24000 grow to in 3 years at 5% per year compound interest (in ₹)?
  3. 3.Find the compound interest on ₹18000 at 10% per year for 1 year, compounded every year (in ₹).
  4. 4.What amount will ₹50900 grow to in 1 year at 25% per year compound interest (in ₹)?
  5. 5.Find the compound interest on ₹31000 at 10% per year for 3 years, compounded every year (in ₹).
  6. 6.A town has 59200 people. The population grows by 25% every year. What will the population be after 3 years?
  7. 7.What is the difference between the compound interest and the simple interest on ₹10000 at 8% per year for 2 years (in ₹)?
  8. 8.What is the difference between the compound interest and the simple interest on ₹10800 at 5% per year for 2 years (in ₹)?
  9. 9.What is the difference between the compound interest and the simple interest on ₹8300 at 20% per year for 2 years (in ₹)?
  10. 10.What is the difference between the compound interest and the simple interest on ₹19600 at 25% per year for 2 years (in ₹)?
  11. 11.What amount will ₹5600 grow to in 2 years at 25% per year compound interest (in ₹)?
  12. 12.Find the compound interest on ₹27200 at 25% per year for 3 years, compounded every year (in ₹).
  13. 13.What amount will ₹8000 grow to in 3 years at 5% per year compound interest (in ₹)?
  14. 14.Find the compound interest on ₹32000 at 25% per year for 1 year, compounded every year (in ₹).
  15. 15.What is the difference between the compound interest and the simple interest on ₹32500 at 4% per year for 2 years (in ₹)?
  16. 16.A scooter is worth ₹57500. Its value falls by 8% every year. What will it be worth after 2 years (in ₹)?
  17. 17.Find the compound interest on ₹46000 at 10% per year for 3 years, compounded every year (in ₹).
  18. 18.Find the compound interest on ₹39100 at 25% per year for 1 year, compounded every year (in ₹).
  19. 19.What amount will ₹51600 grow to in 2 years at 10% per year compound interest (in ₹)?
  20. 20.A town has 7300 people. The population grows by 15% every year. What will the population be after 1 year?
  21. 21.A scooter is worth ₹28800. Its value falls by 20% every year. What will it be worth after 1 year (in ₹)?
  22. 22.Find the compound interest on ₹32000 at 20% per year for 3 years, compounded every year (in ₹).
  23. 23.A scooter is worth ₹39600. Its value falls by 10% every year. What will it be worth after 2 years (in ₹)?
  24. 24.A scooter is worth ₹49000. Its value falls by 10% every year. What will it be worth after 3 years (in ₹)?
  25. 25.A town has 16200 people. The population grows by 25% every year. What will the population be after 1 year?
  26. 26.Find the compound interest on ₹35900 at 20% per year for 2 years, compounded every year (in ₹).
  27. 27.Find the compound interest on ₹44100 at 10% per year for 2 years, compounded every year (in ₹).
  28. 28.A scooter is worth ₹8600. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
  29. 29.What is the difference between the compound interest and the simple interest on ₹45000 at 12% per year for 2 years (in ₹)?
  30. 30.A town has 8100 people. The population grows by 12% every year. What will the population be after 1 year?
  31. 31.What is the difference between the compound interest and the simple interest on ₹39200 at 25% per year for 2 years (in ₹)?
  32. 32.What amount will ₹25600 grow to in 3 years at 25% per year compound interest (in ₹)?
  33. 33.Find the compound interest on ₹11200 at 25% per year for 3 years, compounded every year (in ₹).
  34. 34.What is the difference between the compound interest and the simple interest on ₹41100 at 20% per year for 2 years (in ₹)?
  35. 35.What amount will ₹6400 grow to in 3 years at 25% per year compound interest (in ₹)?
  36. 36.What amount will ₹57700 grow to in 1 year at 8% per year compound interest (in ₹)?
  37. 37.A town has 24000 people. The population grows by 15% every year. What will the population be after 3 years?
  38. 38.What amount will ₹37000 grow to in 3 years at 10% per year compound interest (in ₹)?
  39. 39.Find the compound interest on ₹22500 at 4% per year for 2 years, compounded every year (in ₹).
  40. 40.Find the compound interest on ₹2500 at 8% per year for 2 years, compounded every year (in ₹).

Answer key

  1. 36864
  2. 27783
  3. 1800
  4. 63625
  5. 10261
  6. 115625
  7. 64
  8. 27
  9. 332
  10. 1225
  11. 8750
  12. 25925
  13. 9261
  14. 8000
  15. 52
  16. 48668
  17. 15226
  18. 9775
  19. 62436
  20. 8395
  21. 23040
  22. 23296
  23. 32076
  24. 35721
  25. 20250
  26. 15796
  27. 9261
  28. 7740
  29. 648
  30. 9072
  31. 2450
  32. 50000
  33. 10675
  34. 1644
  35. 12500
  36. 62316
  37. 36501
  38. 49247
  39. 1836
  40. 416

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