Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 620 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.What amount will ₹49000 grow to in 3 years at 10% per year compound interest (in ₹)?
2. 2.What is the difference between the compound interest and the simple interest on ₹47500 at 12% per year for 2 years (in ₹)?
3. 3.What amount will ₹59700 grow to in 1 year at 15% per year compound interest (in ₹)?
4. 4.Find the compound interest on ₹42400 at 5% per year for 1 year, compounded every year (in ₹).
5. 5.Find the compound interest on ₹19100 at 10% per year for 2 years, compounded every year (in ₹).
6. 6.A town has 32400 people. The population grows by 12% every year. What will the population be after 1 year?
7. 7.What amount will ₹16900 grow to in 1 year at 5% per year compound interest (in ₹)?
8. 8.What is the difference between the compound interest and the simple interest on ₹53600 at 15% per year for 2 years (in ₹)?
9. 9.What amount will ₹50000 grow to in 2 years at 4% per year compound interest (in ₹)?
10. 10.What amount will ₹11400 grow to in 2 years at 20% per year compound interest (in ₹)?
11. 11.What is the difference between the compound interest and the simple interest on ₹18400 at 5% per year for 2 years (in ₹)?
12. 12.A scooter is worth ₹42900. Its value falls by 20% every year. What will it be worth after 2 years (in ₹)?
13. 13.Find the compound interest on ₹8600 at 4% per year for 1 year, compounded every year (in ₹).
14. 14.Find the compound interest on ₹8000 at 5% per year for 3 years, compounded every year (in ₹).
15. 15.What is the difference between the compound interest and the simple interest on ₹7200 at 25% per year for 2 years (in ₹)?
16. 16.Find the compound interest on ₹20400 at 15% per year for 2 years, compounded every year (in ₹).
17. 17.What amount will ₹15200 grow to in 1 year at 10% per year compound interest (in ₹)?
18. 18.What is the difference between the compound interest and the simple interest on ₹53200 at 25% per year for 2 years (in ₹)?
19. 19.What is the difference between the compound interest and the simple interest on ₹9100 at 20% per year for 2 years (in ₹)?
20. 20.A town has 56000 people. The population grows by 5% every year. What will the population be after 3 years?
21. 21.A scooter is worth ₹19700. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
22. 22.A town has 37500 people. The population grows by 12% every year. What will the population be after 2 years?
23. 23.A town has 43000 people. The population grows by 10% every year. What will the population be after 3 years?
24. 24.What amount will ₹22300 grow to in 2 years at 20% per year compound interest (in ₹)?
25. 25.What is the difference between the compound interest and the simple interest on ₹55000 at 8% per year for 2 years (in ₹)?
26. 26.A town has 11600 people. The population grows by 8% every year. What will the population be after 1 year?
27. 27.What amount will ₹30000 grow to in 3 years at 20% per year compound interest (in ₹)?
28. 28.Find the compound interest on ₹50000 at 4% per year for 2 years, compounded every year (in ₹).
29. 29.A town has 56000 people. The population grows by 20% every year. What will the population be after 3 years?
30. 30.What amount will ₹4000 grow to in 2 years at 15% per year compound interest (in ₹)?
31. 31.A town has 5400 people. The population grows by 10% every year. What will the population be after 2 years?
32. 32.A scooter is worth ₹37000. Its value falls by 10% every year. What will it be worth after 3 years (in ₹)?
33. 33.A town has 4700 people. The population grows by 8% every year. What will the population be after 1 year?
34. 34.Find the compound interest on ₹17600 at 10% per year for 1 year, compounded every year (in ₹).
35. 35.Find the compound interest on ₹35000 at 8% per year for 2 years, compounded every year (in ₹).
36. 36.Find the compound interest on ₹9400 at 25% per year for 1 year, compounded every year (in ₹).
37. 37.Find the compound interest on ₹10000 at 10% per year for 3 years, compounded every year (in ₹).
38. 38.A scooter is worth ₹28600. Its value falls by 8% every year. What will it be worth after 1 year (in ₹)?
39. 39.What is the difference between the compound interest and the simple interest on ₹25000 at 4% per year for 2 years (in ₹)?
40. 40.Find the compound interest on ₹48000 at 15% per year for 3 years, compounded every year (in ₹).

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