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Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 621 · 40 sums
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The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

NameDateTime takenScore ___ / 40
  1. 1.What amount will ₹50400 grow to in 2 years at 5% per year compound interest (in ₹)?
  2. 2.Find the compound interest on ₹53100 at 20% per year for 1 year, compounded every year (in ₹).
  3. 3.A scooter is worth ₹56000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
  4. 4.Find the compound interest on ₹39000 at 12% per year for 1 year, compounded every year (in ₹).
  5. 5.What is the difference between the compound interest and the simple interest on ₹44800 at 10% per year for 2 years (in ₹)?
  6. 6.A scooter is worth ₹19200. Its value falls by 8% every year. What will it be worth after 1 year (in ₹)?
  7. 7.What amount will ₹2500 grow to in 2 years at 4% per year compound interest (in ₹)?
  8. 8.What amount will ₹33700 grow to in 1 year at 4% per year compound interest (in ₹)?
  9. 9.What amount will ₹24000 grow to in 3 years at 5% per year compound interest (in ₹)?
  10. 10.Find the compound interest on ₹51400 at 10% per year for 2 years, compounded every year (in ₹).
  11. 11.What is the difference between the compound interest and the simple interest on ₹17600 at 5% per year for 2 years (in ₹)?
  12. 12.Find the compound interest on ₹23600 at 25% per year for 2 years, compounded every year (in ₹).
  13. 13.What amount will ₹47500 grow to in 2 years at 4% per year compound interest (in ₹)?
  14. 14.What is the difference between the compound interest and the simple interest on ₹30800 at 10% per year for 2 years (in ₹)?
  15. 15.What amount will ₹35000 grow to in 2 years at 12% per year compound interest (in ₹)?
  16. 16.What is the difference between the compound interest and the simple interest on ₹10000 at 12% per year for 2 years (in ₹)?
  17. 17.What is the difference between the compound interest and the simple interest on ₹7500 at 4% per year for 2 years (in ₹)?
  18. 18.A scooter is worth ₹32500. Its value falls by 4% every year. What will it be worth after 2 years (in ₹)?
  19. 19.Find the compound interest on ₹21000 at 12% per year for 1 year, compounded every year (in ₹).
  20. 20.What is the difference between the compound interest and the simple interest on ₹32500 at 4% per year for 2 years (in ₹)?
  21. 21.Find the compound interest on ₹37800 at 25% per year for 1 year, compounded every year (in ₹).
  22. 22.What amount will ₹2800 grow to in 1 year at 10% per year compound interest (in ₹)?
  23. 23.What amount will ₹8000 grow to in 3 years at 25% per year compound interest (in ₹)?
  24. 24.What amount will ₹9600 grow to in 3 years at 25% per year compound interest (in ₹)?
  25. 25.What amount will ₹10300 grow to in 1 year at 15% per year compound interest (in ₹)?
  26. 26.What is the difference between the compound interest and the simple interest on ₹11300 at 10% per year for 2 years (in ₹)?
  27. 27.Find the compound interest on ₹34900 at 10% per year for 2 years, compounded every year (in ₹).
  28. 28.What amount will ₹57500 grow to in 2 years at 12% per year compound interest (in ₹)?
  29. 29.Find the compound interest on ₹27500 at 20% per year for 1 year, compounded every year (in ₹).
  30. 30.A town has 55700 people. The population grows by 20% every year. What will the population be after 1 year?
  31. 31.A scooter is worth ₹46900. Its value falls by 8% every year. What will it be worth after 1 year (in ₹)?
  32. 32.Find the compound interest on ₹60000 at 4% per year for 2 years, compounded every year (in ₹).
  33. 33.A town has 53500 people. The population grows by 20% every year. What will the population be after 3 years?
  34. 34.A town has 18600 people. The population grows by 20% every year. What will the population be after 2 years?
  35. 35.A scooter is worth ₹27800. Its value falls by 10% every year. What will it be worth after 2 years (in ₹)?
  36. 36.What is the difference between the compound interest and the simple interest on ₹22500 at 12% per year for 2 years (in ₹)?
  37. 37.Find the compound interest on ₹16700 at 15% per year for 1 year, compounded every year (in ₹).
  38. 38.Find the compound interest on ₹39900 at 20% per year for 2 years, compounded every year (in ₹).
  39. 39.A town has 30100 people. The population grows by 10% every year. What will the population be after 1 year?
  40. 40.Find the compound interest on ₹52500 at 8% per year for 2 years, compounded every year (in ₹).

Answer key

  1. 55566
  2. 10620
  3. 48013
  4. 4680
  5. 448
  6. 17664
  7. 2704
  8. 35048
  9. 27783
  10. 10794
  11. 44
  12. 13275
  13. 51376
  14. 308
  15. 43904
  16. 144
  17. 12
  18. 29952
  19. 2520
  20. 52
  21. 9450
  22. 3080
  23. 15625
  24. 18750
  25. 11845
  26. 113
  27. 7329
  28. 72128
  29. 5500
  30. 66840
  31. 43148
  32. 4896
  33. 92448
  34. 26784
  35. 22518
  36. 324
  37. 2505
  38. 17556
  39. 33110
  40. 8736

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