Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 624 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.A town has 24700 people. The population grows by 4% every year. What will the population be after 1 year?
2. 2.What amount will ₹27500 grow to in 2 years at 8% per year compound interest (in ₹)?
3. 3.A scooter is worth ₹18000. Its value falls by 15% every year. What will it be worth after 2 years (in ₹)?
4. 4.A scooter is worth ₹47400. Its value falls by 20% every year. What will it be worth after 1 year (in ₹)?
5. 5.What is the difference between the compound interest and the simple interest on ₹5700 at 20% per year for 2 years (in ₹)?
6. 6.Find the compound interest on ₹4100 at 10% per year for 1 year, compounded every year (in ₹).
7. 7.What amount will ₹24000 grow to in 2 years at 5% per year compound interest (in ₹)?
8. 8.Find the compound interest on ₹6400 at 25% per year for 3 years, compounded every year (in ₹).
9. 9.Find the compound interest on ₹56900 at 15% per year for 1 year, compounded every year (in ₹).
10. 10.What amount will ₹15600 grow to in 1 year at 20% per year compound interest (in ₹)?
11. 11.Find the compound interest on ₹10000 at 8% per year for 2 years, compounded every year (in ₹).
12. 12.Find the compound interest on ₹27000 at 10% per year for 1 year, compounded every year (in ₹).
13. 13.What is the difference between the compound interest and the simple interest on ₹4300 at 10% per year for 2 years (in ₹)?
14. 14.What is the difference between the compound interest and the simple interest on ₹55200 at 25% per year for 2 years (in ₹)?
15. 15.A scooter is worth ₹19200. Its value falls by 25% every year. What will it be worth after 3 years (in ₹)?
16. 16.Find the compound interest on ₹16700 at 15% per year for 1 year, compounded every year (in ₹).
17. 17.What is the difference between the compound interest and the simple interest on ₹35200 at 25% per year for 2 years (in ₹)?
18. 18.A scooter is worth ₹3200. Its value falls by 25% every year. What will it be worth after 2 years (in ₹)?
19. 19.What amount will ₹10200 grow to in 2 years at 20% per year compound interest (in ₹)?
20. 20.A scooter is worth ₹3200. Its value falls by 25% every year. What will it be worth after 3 years (in ₹)?
21. 21.Find the compound interest on ₹41000 at 25% per year for 1 year, compounded every year (in ₹).
22. 22.What is the difference between the compound interest and the simple interest on ₹10000 at 4% per year for 2 years (in ₹)?
23. 23.A scooter is worth ₹13600. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
24. 24.What amount will ₹24800 grow to in 1 year at 20% per year compound interest (in ₹)?
25. 25.Find the compound interest on ₹4800 at 4% per year for 1 year, compounded every year (in ₹).
26. 26.What amount will ₹42900 grow to in 1 year at 12% per year compound interest (in ₹)?
27. 27.A scooter is worth ₹51200. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
28. 28.Find the compound interest on ₹22500 at 12% per year for 2 years, compounded every year (in ₹).
29. 29.What is the difference between the compound interest and the simple interest on ₹46000 at 5% per year for 2 years (in ₹)?
30. 30.A scooter is worth ₹56000. Its value falls by 15% every year. What will it be worth after 3 years (in ₹)?
31. 31.What amount will ₹8400 grow to in 1 year at 5% per year compound interest (in ₹)?
32. 32.A town has 21400 people. The population grows by 5% every year. What will the population be after 1 year?
33. 33.What is the difference between the compound interest and the simple interest on ₹7500 at 12% per year for 2 years (in ₹)?
34. 34.Find the compound interest on ₹5600 at 15% per year for 2 years, compounded every year (in ₹).
35. 35.Find the compound interest on ₹23600 at 5% per year for 2 years, compounded every year (in ₹).
36. 36.Find the compound interest on ₹5000 at 4% per year for 2 years, compounded every year (in ₹).
37. 37.A scooter is worth ₹44800. Its value falls by 12% every year. What will it be worth after 1 year (in ₹)?
38. 38.What amount will ₹16700 grow to in 2 years at 10% per year compound interest (in ₹)?
39. 39.What is the difference between the compound interest and the simple interest on ₹25000 at 12% per year for 2 years (in ₹)?
40. 40.A town has 5000 people. The population grows by 8% every year. What will the population be after 2 years?

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