Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 625 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.What is the difference between the compound interest and the simple interest on ₹50000 at 8% per year for 2 years (in ₹)?
2. 2.Find the compound interest on ₹32700 at 20% per year for 2 years, compounded every year (in ₹).
3. 3.What is the difference between the compound interest and the simple interest on ₹17600 at 10% per year for 2 years (in ₹)?
4. 4.A town has 21200 people. The population grows by 25% every year. What will the population be after 2 years?
5. 5.What amount will ₹24700 grow to in 1 year at 20% per year compound interest (in ₹)?
6. 6.What is the difference between the compound interest and the simple interest on ₹12500 at 8% per year for 2 years (in ₹)?
7. 7.What is the difference between the compound interest and the simple interest on ₹24400 at 25% per year for 2 years (in ₹)?
8. 8.A town has 9200 people. The population grows by 10% every year. What will the population be after 2 years?
9. 9.Find the compound interest on ₹58300 at 4% per year for 1 year, compounded every year (in ₹).
10. 10.Find the compound interest on ₹16000 at 15% per year for 3 years, compounded every year (in ₹).
11. 11.What is the difference between the compound interest and the simple interest on ₹32500 at 12% per year for 2 years (in ₹)?
12. 12.Find the compound interest on ₹26600 at 10% per year for 2 years, compounded every year (in ₹).
13. 13.What amount will ₹2600 grow to in 1 year at 4% per year compound interest (in ₹)?
14. 14.What amount will ₹58400 grow to in 2 years at 25% per year compound interest (in ₹)?
15. 15.A scooter is worth ₹18400. Its value falls by 25% every year. What will it be worth after 2 years (in ₹)?
16. 16.What is the difference between the compound interest and the simple interest on ₹30000 at 12% per year for 2 years (in ₹)?
17. 17.Find the compound interest on ₹11000 at 15% per year for 1 year, compounded every year (in ₹).
18. 18.What amount will ₹47200 grow to in 1 year at 15% per year compound interest (in ₹)?
19. 19.What is the difference between the compound interest and the simple interest on ₹7800 at 20% per year for 2 years (in ₹)?
20. 20.What is the difference between the compound interest and the simple interest on ₹8400 at 20% per year for 2 years (in ₹)?
21. 21.What is the difference between the compound interest and the simple interest on ₹10400 at 25% per year for 2 years (in ₹)?
22. 22.What is the difference between the compound interest and the simple interest on ₹12000 at 15% per year for 2 years (in ₹)?
23. 23.What amount will ₹42500 grow to in 2 years at 8% per year compound interest (in ₹)?
24. 24.Find the compound interest on ₹57500 at 12% per year for 2 years, compounded every year (in ₹).
25. 25.A town has 8000 people. The population grows by 15% every year. What will the population be after 3 years?
26. 26.What amount will ₹23100 grow to in 1 year at 4% per year compound interest (in ₹)?
27. 27.A town has 21800 people. The population grows by 15% every year. What will the population be after 1 year?
28. 28.A scooter is worth ₹8000. Its value falls by 15% every year. What will it be worth after 3 years (in ₹)?
29. 29.Find the compound interest on ₹39000 at 20% per year for 3 years, compounded every year (in ₹).
30. 30.What amount will ₹8000 grow to in 3 years at 5% per year compound interest (in ₹)?
31. 31.A town has 24200 people. The population grows by 5% every year. What will the population be after 1 year?
32. 32.What amount will ₹28700 grow to in 1 year at 4% per year compound interest (in ₹)?
33. 33.Find the compound interest on ₹44700 at 10% per year for 2 years, compounded every year (in ₹).
34. 34.Find the compound interest on ₹9100 at 20% per year for 1 year, compounded every year (in ₹).
35. 35.What is the difference between the compound interest and the simple interest on ₹34800 at 15% per year for 2 years (in ₹)?
36. 36.A scooter is worth ₹42000. Its value falls by 4% every year. What will it be worth after 1 year (in ₹)?
37. 37.A town has 11300 people. The population grows by 25% every year. What will the population be after 1 year?
38. 38.A town has 57900 people. The population grows by 10% every year. What will the population be after 1 year?
39. 39.Find the compound interest on ₹56000 at 5% per year for 3 years, compounded every year (in ₹).
40. 40.What amount will ₹25600 grow to in 1 year at 25% per year compound interest (in ₹)?

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