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Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 626 · 40 sums
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The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

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  1. 1.What is the difference between the compound interest and the simple interest on ₹50000 at 12% per year for 2 years (in ₹)?
  2. 2.Find the compound interest on ₹55200 at 25% per year for 2 years, compounded every year (in ₹).
  3. 3.A town has 43100 people. The population grows by 20% every year. What will the population be after 1 year?
  4. 4.Find the compound interest on ₹36000 at 15% per year for 2 years, compounded every year (in ₹).
  5. 5.What is the difference between the compound interest and the simple interest on ₹20000 at 8% per year for 2 years (in ₹)?
  6. 6.What amount will ₹4600 grow to in 1 year at 4% per year compound interest (in ₹)?
  7. 7.A scooter is worth ₹39800. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
  8. 8.What amount will ₹14000 grow to in 1 year at 8% per year compound interest (in ₹)?
  9. 9.Find the compound interest on ₹24000 at 5% per year for 3 years, compounded every year (in ₹).
  10. 10.Find the compound interest on ₹20000 at 12% per year for 1 year, compounded every year (in ₹).
  11. 11.A scooter is worth ₹3300. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
  12. 12.A town has 9900 people. The population grows by 25% every year. What will the population be after 1 year?
  13. 13.A town has 5200 people. The population grows by 5% every year. What will the population be after 2 years?
  14. 14.Find the compound interest on ₹52000 at 8% per year for 1 year, compounded every year (in ₹).
  15. 15.Find the compound interest on ₹14000 at 15% per year for 2 years, compounded every year (in ₹).
  16. 16.What is the difference between the compound interest and the simple interest on ₹4800 at 5% per year for 2 years (in ₹)?
  17. 17.What is the difference between the compound interest and the simple interest on ₹34000 at 25% per year for 2 years (in ₹)?
  18. 18.What is the difference between the compound interest and the simple interest on ₹50000 at 8% per year for 2 years (in ₹)?
  19. 19.What is the difference between the compound interest and the simple interest on ₹8700 at 20% per year for 2 years (in ₹)?
  20. 20.What amount will ₹55400 grow to in 2 years at 20% per year compound interest (in ₹)?
  21. 21.A town has 24000 people. The population grows by 5% every year. What will the population be after 3 years?
  22. 22.A scooter is worth ₹24700. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
  23. 23.What is the difference between the compound interest and the simple interest on ₹34400 at 5% per year for 2 years (in ₹)?
  24. 24.A scooter is worth ₹32000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
  25. 25.A scooter is worth ₹5000. Its value falls by 8% every year. What will it be worth after 2 years (in ₹)?
  26. 26.What is the difference between the compound interest and the simple interest on ₹38500 at 20% per year for 2 years (in ₹)?
  27. 27.Find the compound interest on ₹23700 at 5% per year for 1 year, compounded every year (in ₹).
  28. 28.A scooter is worth ₹52500. Its value falls by 20% every year. What will it be worth after 1 year (in ₹)?
  29. 29.What amount will ₹18900 grow to in 1 year at 20% per year compound interest (in ₹)?
  30. 30.A scooter is worth ₹24000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
  31. 31.Find the compound interest on ₹29200 at 5% per year for 2 years, compounded every year (in ₹).
  32. 32.What is the difference between the compound interest and the simple interest on ₹38100 at 10% per year for 2 years (in ₹)?
  33. 33.Find the compound interest on ₹11000 at 20% per year for 3 years, compounded every year (in ₹).
  34. 34.A scooter is worth ₹39000. Its value falls by 10% every year. What will it be worth after 3 years (in ₹)?
  35. 35.What is the difference between the compound interest and the simple interest on ₹42500 at 4% per year for 2 years (in ₹)?
  36. 36.What amount will ₹24000 grow to in 3 years at 15% per year compound interest (in ₹)?
  37. 37.Find the compound interest on ₹58400 at 15% per year for 2 years, compounded every year (in ₹).
  38. 38.A town has 45100 people. The population grows by 4% every year. What will the population be after 1 year?
  39. 39.What is the difference between the compound interest and the simple interest on ₹16800 at 25% per year for 2 years (in ₹)?
  40. 40.What amount will ₹42900 grow to in 1 year at 25% per year compound interest (in ₹)?

Answer key

  1. 720
  2. 31050
  3. 51720
  4. 11610
  5. 128
  6. 4784
  7. 35820
  8. 15120
  9. 3783
  10. 2400
  11. 2970
  12. 12375
  13. 5733
  14. 4160
  15. 4515
  16. 12
  17. 2125
  18. 320
  19. 348
  20. 79776
  21. 27783
  22. 22230
  23. 86
  24. 27436
  25. 4232
  26. 1540
  27. 1185
  28. 42000
  29. 22680
  30. 20577
  31. 2993
  32. 381
  33. 8008
  34. 28431
  35. 68
  36. 36501
  37. 18834
  38. 46904
  39. 1050
  40. 53625

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