Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 630 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.What amount will ₹3800 grow to in 2 years at 10% per year compound interest (in ₹)?
2. 2.A scooter is worth ₹55000. Its value falls by 12% every year. What will it be worth after 2 years (in ₹)?
3. 3.Find the compound interest on ₹52000 at 4% per year for 1 year, compounded every year (in ₹).
4. 4.What is the difference between the compound interest and the simple interest on ₹46400 at 5% per year for 2 years (in ₹)?
5. 5.A scooter is worth ₹36500. Its value falls by 20% every year. What will it be worth after 3 years (in ₹)?
6. 6.What amount will ₹16000 grow to in 3 years at 15% per year compound interest (in ₹)?
7. 7.What is the difference between the compound interest and the simple interest on ₹27500 at 8% per year for 2 years (in ₹)?
8. 8.A town has 41800 people. The population grows by 20% every year. What will the population be after 1 year?
9. 9.Find the compound interest on ₹23800 at 15% per year for 1 year, compounded every year (in ₹).
10. 10.Find the compound interest on ₹21000 at 10% per year for 3 years, compounded every year (in ₹).
11. 11.A town has 35200 people. The population grows by 15% every year. What will the population be after 1 year?
12. 12.A scooter is worth ₹34800. Its value falls by 15% every year. What will it be worth after 2 years (in ₹)?
13. 13.What amount will ₹50000 grow to in 3 years at 10% per year compound interest (in ₹)?
14. 14.A town has 53400 people. The population grows by 20% every year. What will the population be after 1 year?
15. 15.Find the compound interest on ₹48000 at 5% per year for 2 years, compounded every year (in ₹).
16. 16.A town has 31000 people. The population grows by 20% every year. What will the population be after 2 years?
17. 17.What amount will ₹33100 grow to in 1 year at 25% per year compound interest (in ₹)?
18. 18.What is the difference between the compound interest and the simple interest on ₹11100 at 20% per year for 2 years (in ₹)?
19. 19.What is the difference between the compound interest and the simple interest on ₹17500 at 4% per year for 2 years (in ₹)?
20. 20.A town has 16000 people. The population grows by 15% every year. What will the population be after 3 years?
21. 21.A scooter is worth ₹55300. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
22. 22.Find the compound interest on ₹15000 at 4% per year for 2 years, compounded every year (in ₹).
23. 23.A scooter is worth ₹11500. Its value falls by 20% every year. What will it be worth after 3 years (in ₹)?
24. 24.Find the compound interest on ₹36000 at 25% per year for 2 years, compounded every year (in ₹).
25. 25.A scooter is worth ₹4800. Its value falls by 10% every year. What will it be worth after 2 years (in ₹)?
26. 26.Find the compound interest on ₹59700 at 12% per year for 1 year, compounded every year (in ₹).
27. 27.Find the compound interest on ₹46000 at 5% per year for 2 years, compounded every year (in ₹).
28. 28.Find the compound interest on ₹2500 at 12% per year for 2 years, compounded every year (in ₹).
29. 29.What is the difference between the compound interest and the simple interest on ₹14100 at 10% per year for 2 years (in ₹)?
30. 30.A town has 12000 people. The population grows by 5% every year. What will the population be after 2 years?
31. 31.What is the difference between the compound interest and the simple interest on ₹27500 at 12% per year for 2 years (in ₹)?
32. 32.What amount will ₹42100 grow to in 2 years at 20% per year compound interest (in ₹)?
33. 33.What amount will ₹38000 grow to in 2 years at 20% per year compound interest (in ₹)?
34. 34.What is the difference between the compound interest and the simple interest on ₹40800 at 10% per year for 2 years (in ₹)?
35. 35.Find the compound interest on ₹32200 at 10% per year for 2 years, compounded every year (in ₹).
36. 36.What amount will ₹56000 grow to in 2 years at 10% per year compound interest (in ₹)?
37. 37.What amount will ₹48300 grow to in 1 year at 20% per year compound interest (in ₹)?
38. 38.Find the compound interest on ₹27200 at 8% per year for 1 year, compounded every year (in ₹).
39. 39.A scooter is worth ₹45000. Its value falls by 8% every year. What will it be worth after 2 years (in ₹)?
40. 40.What is the difference between the compound interest and the simple interest on ₹42600 at 20% per year for 2 years (in ₹)?

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