Class 8 Maths Worksheet: Compound Interest
The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.
NameDateTime takenScore ___ / 40
- 1.A town has 30800 people. The population grows by 5% every year. What will the population be after 2 years?
- 2.What is the difference between the compound interest and the simple interest on ₹3600 at 5% per year for 2 years (in ₹)?
- 3.What is the difference between the compound interest and the simple interest on ₹27200 at 5% per year for 2 years (in ₹)?
- 4.A town has 29100 people. The population grows by 12% every year. What will the population be after 1 year?
- 5.What is the difference between the compound interest and the simple interest on ₹8200 at 10% per year for 2 years (in ₹)?
- 6.A town has 22500 people. The population grows by 8% every year. What will the population be after 2 years?
- 7.What amount will ₹57600 grow to in 3 years at 25% per year compound interest (in ₹)?
- 8.A town has 46400 people. The population grows by 20% every year. What will the population be after 2 years?
- 9.What amount will ₹46400 grow to in 1 year at 10% per year compound interest (in ₹)?
- 10.What amount will ₹2000 grow to in 2 years at 25% per year compound interest (in ₹)?
- 11.Find the compound interest on ₹36400 at 4% per year for 1 year, compounded every year (in ₹).
- 12.A town has 15000 people. The population grows by 8% every year. What will the population be after 2 years?
- 13.What is the difference between the compound interest and the simple interest on ₹50000 at 8% per year for 2 years (in ₹)?
- 14.Find the compound interest on ₹17100 at 8% per year for 1 year, compounded every year (in ₹).
- 15.What amount will ₹29000 grow to in 1 year at 12% per year compound interest (in ₹)?
- 16.A town has 35600 people. The population grows by 5% every year. What will the population be after 2 years?
- 17.What is the difference between the compound interest and the simple interest on ₹2500 at 4% per year for 2 years (in ₹)?
- 18.What is the difference between the compound interest and the simple interest on ₹54400 at 25% per year for 2 years (in ₹)?
- 19.What amount will ₹8000 grow to in 3 years at 15% per year compound interest (in ₹)?
- 20.What is the difference between the compound interest and the simple interest on ₹60000 at 12% per year for 2 years (in ₹)?
- 21.What is the difference between the compound interest and the simple interest on ₹34800 at 25% per year for 2 years (in ₹)?
- 22.What is the difference between the compound interest and the simple interest on ₹4400 at 10% per year for 2 years (in ₹)?
- 23.Find the compound interest on ₹37500 at 8% per year for 2 years, compounded every year (in ₹).
- 24.What is the difference between the compound interest and the simple interest on ₹37300 at 20% per year for 2 years (in ₹)?
- 25.Find the compound interest on ₹2800 at 25% per year for 1 year, compounded every year (in ₹).
- 26.What amount will ₹53300 grow to in 1 year at 4% per year compound interest (in ₹)?
- 27.What is the difference between the compound interest and the simple interest on ₹10200 at 10% per year for 2 years (in ₹)?
- 28.Find the compound interest on ₹6600 at 20% per year for 2 years, compounded every year (in ₹).
- 29.Find the compound interest on ₹29900 at 20% per year for 2 years, compounded every year (in ₹).
- 30.Find the compound interest on ₹23200 at 20% per year for 2 years, compounded every year (in ₹).
- 31.A town has 31500 people. The population grows by 20% every year. What will the population be after 3 years?
- 32.Find the compound interest on ₹47300 at 12% per year for 1 year, compounded every year (in ₹).
- 33.What amount will ₹51200 grow to in 2 years at 5% per year compound interest (in ₹)?
- 34.What amount will ₹11700 grow to in 1 year at 15% per year compound interest (in ₹)?
- 35.Find the compound interest on ₹51700 at 5% per year for 1 year, compounded every year (in ₹).
- 36.What amount will ₹60000 grow to in 2 years at 4% per year compound interest (in ₹)?
- 37.Find the compound interest on ₹25200 at 4% per year for 1 year, compounded every year (in ₹).
- 38.A town has 48000 people. The population grows by 5% every year. What will the population be after 3 years?
- 39.A scooter is worth ₹22500. Its value falls by 12% every year. What will it be worth after 2 years (in ₹)?
- 40.Find the compound interest on ₹29000 at 10% per year for 3 years, compounded every year (in ₹).
Answer key
- 33957
- 9
- 68
- 32592
- 82
- 26244
- 112500
- 66816
- 51040
- 3125
- 1456
- 17496
- 320
- 1368
- 32480
- 39249
- 4
- 3400
- 12167
- 864
- 2175
- 44
- 6240
- 1492
- 700
- 55432
- 102
- 2904
- 13156
- 10208
- 54432
- 5676
- 56448
- 13455
- 2585
- 64896
- 1008
- 55566
- 17424
- 9599
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