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Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 631 · 40 sums
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The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

NameDateTime takenScore ___ / 40
  1. 1.A town has 30800 people. The population grows by 5% every year. What will the population be after 2 years?
  2. 2.What is the difference between the compound interest and the simple interest on ₹3600 at 5% per year for 2 years (in ₹)?
  3. 3.What is the difference between the compound interest and the simple interest on ₹27200 at 5% per year for 2 years (in ₹)?
  4. 4.A town has 29100 people. The population grows by 12% every year. What will the population be after 1 year?
  5. 5.What is the difference between the compound interest and the simple interest on ₹8200 at 10% per year for 2 years (in ₹)?
  6. 6.A town has 22500 people. The population grows by 8% every year. What will the population be after 2 years?
  7. 7.What amount will ₹57600 grow to in 3 years at 25% per year compound interest (in ₹)?
  8. 8.A town has 46400 people. The population grows by 20% every year. What will the population be after 2 years?
  9. 9.What amount will ₹46400 grow to in 1 year at 10% per year compound interest (in ₹)?
  10. 10.What amount will ₹2000 grow to in 2 years at 25% per year compound interest (in ₹)?
  11. 11.Find the compound interest on ₹36400 at 4% per year for 1 year, compounded every year (in ₹).
  12. 12.A town has 15000 people. The population grows by 8% every year. What will the population be after 2 years?
  13. 13.What is the difference between the compound interest and the simple interest on ₹50000 at 8% per year for 2 years (in ₹)?
  14. 14.Find the compound interest on ₹17100 at 8% per year for 1 year, compounded every year (in ₹).
  15. 15.What amount will ₹29000 grow to in 1 year at 12% per year compound interest (in ₹)?
  16. 16.A town has 35600 people. The population grows by 5% every year. What will the population be after 2 years?
  17. 17.What is the difference between the compound interest and the simple interest on ₹2500 at 4% per year for 2 years (in ₹)?
  18. 18.What is the difference between the compound interest and the simple interest on ₹54400 at 25% per year for 2 years (in ₹)?
  19. 19.What amount will ₹8000 grow to in 3 years at 15% per year compound interest (in ₹)?
  20. 20.What is the difference between the compound interest and the simple interest on ₹60000 at 12% per year for 2 years (in ₹)?
  21. 21.What is the difference between the compound interest and the simple interest on ₹34800 at 25% per year for 2 years (in ₹)?
  22. 22.What is the difference between the compound interest and the simple interest on ₹4400 at 10% per year for 2 years (in ₹)?
  23. 23.Find the compound interest on ₹37500 at 8% per year for 2 years, compounded every year (in ₹).
  24. 24.What is the difference between the compound interest and the simple interest on ₹37300 at 20% per year for 2 years (in ₹)?
  25. 25.Find the compound interest on ₹2800 at 25% per year for 1 year, compounded every year (in ₹).
  26. 26.What amount will ₹53300 grow to in 1 year at 4% per year compound interest (in ₹)?
  27. 27.What is the difference between the compound interest and the simple interest on ₹10200 at 10% per year for 2 years (in ₹)?
  28. 28.Find the compound interest on ₹6600 at 20% per year for 2 years, compounded every year (in ₹).
  29. 29.Find the compound interest on ₹29900 at 20% per year for 2 years, compounded every year (in ₹).
  30. 30.Find the compound interest on ₹23200 at 20% per year for 2 years, compounded every year (in ₹).
  31. 31.A town has 31500 people. The population grows by 20% every year. What will the population be after 3 years?
  32. 32.Find the compound interest on ₹47300 at 12% per year for 1 year, compounded every year (in ₹).
  33. 33.What amount will ₹51200 grow to in 2 years at 5% per year compound interest (in ₹)?
  34. 34.What amount will ₹11700 grow to in 1 year at 15% per year compound interest (in ₹)?
  35. 35.Find the compound interest on ₹51700 at 5% per year for 1 year, compounded every year (in ₹).
  36. 36.What amount will ₹60000 grow to in 2 years at 4% per year compound interest (in ₹)?
  37. 37.Find the compound interest on ₹25200 at 4% per year for 1 year, compounded every year (in ₹).
  38. 38.A town has 48000 people. The population grows by 5% every year. What will the population be after 3 years?
  39. 39.A scooter is worth ₹22500. Its value falls by 12% every year. What will it be worth after 2 years (in ₹)?
  40. 40.Find the compound interest on ₹29000 at 10% per year for 3 years, compounded every year (in ₹).

Answer key

  1. 33957
  2. 9
  3. 68
  4. 32592
  5. 82
  6. 26244
  7. 112500
  8. 66816
  9. 51040
  10. 3125
  11. 1456
  12. 17496
  13. 320
  14. 1368
  15. 32480
  16. 39249
  17. 4
  18. 3400
  19. 12167
  20. 864
  21. 2175
  22. 44
  23. 6240
  24. 1492
  25. 700
  26. 55432
  27. 102
  28. 2904
  29. 13156
  30. 10208
  31. 54432
  32. 5676
  33. 56448
  34. 13455
  35. 2585
  36. 64896
  37. 1008
  38. 55566
  39. 17424
  40. 9599

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