Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 632 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.What is the difference between the compound interest and the simple interest on ₹44200 at 10% per year for 2 years (in ₹)?
2. 2.A town has 5600 people. The population grows by 5% every year. What will the population be after 1 year?
3. 3.A town has 37800 people. The population grows by 25% every year. What will the population be after 1 year?
4. 4.Find the compound interest on ₹12500 at 8% per year for 2 years, compounded every year (in ₹).
5. 5.A town has 15000 people. The population grows by 4% every year. What will the population be after 2 years?
6. 6.What is the difference between the compound interest and the simple interest on ₹10000 at 12% per year for 2 years (in ₹)?
7. 7.A scooter is worth ₹5000. Its value falls by 8% every year. What will it be worth after 2 years (in ₹)?
8. 8.What is the difference between the compound interest and the simple interest on ₹45900 at 20% per year for 2 years (in ₹)?
9. 9.What amount will ₹14800 grow to in 2 years at 25% per year compound interest (in ₹)?
10. 10.What amount will ₹50800 grow to in 2 years at 15% per year compound interest (in ₹)?
11. 11.Find the compound interest on ₹49000 at 10% per year for 3 years, compounded every year (in ₹).
12. 12.A town has 46800 people. The population grows by 12% every year. What will the population be after 1 year?
13. 13.A scooter is worth ₹4200. Its value falls by 20% every year. What will it be worth after 2 years (in ₹)?
14. 14.Find the compound interest on ₹27000 at 10% per year for 3 years, compounded every year (in ₹).
15. 15.A town has 6000 people. The population grows by 15% every year. What will the population be after 2 years?
16. 16.What amount will ₹11000 grow to in 3 years at 10% per year compound interest (in ₹)?
17. 17.Find the compound interest on ₹43300 at 20% per year for 2 years, compounded every year (in ₹).
18. 18.What amount will ₹31700 grow to in 1 year at 5% per year compound interest (in ₹)?
19. 19.What is the difference between the compound interest and the simple interest on ₹12500 at 8% per year for 2 years (in ₹)?
20. 20.What is the difference between the compound interest and the simple interest on ₹16800 at 25% per year for 2 years (in ₹)?
21. 21.A town has 52500 people. The population grows by 8% every year. What will the population be after 2 years?
22. 22.What amount will ₹30700 grow to in 1 year at 4% per year compound interest (in ₹)?
23. 23.Find the compound interest on ₹16000 at 15% per year for 3 years, compounded every year (in ₹).
24. 24.What is the difference between the compound interest and the simple interest on ₹34900 at 20% per year for 2 years (in ₹)?
25. 25.Find the compound interest on ₹20000 at 10% per year for 3 years, compounded every year (in ₹).
26. 26.A scooter is worth ₹42700. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
27. 27.A scooter is worth ₹27300. Its value falls by 25% every year. What will it be worth after 1 year (in ₹)?
28. 28.A town has 7500 people. The population grows by 25% every year. What will the population be after 1 year?
29. 29.A town has 25300 people. The population grows by 5% every year. What will the population be after 1 year?
30. 30.What is the difference between the compound interest and the simple interest on ₹5000 at 12% per year for 2 years (in ₹)?
31. 31.A scooter is worth ₹31100. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
32. 32.What is the difference between the compound interest and the simple interest on ₹31200 at 25% per year for 2 years (in ₹)?
33. 33.What is the difference between the compound interest and the simple interest on ₹47500 at 4% per year for 2 years (in ₹)?
34. 34.What is the difference between the compound interest and the simple interest on ₹56400 at 25% per year for 2 years (in ₹)?
35. 35.A scooter is worth ₹16000. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
36. 36.A scooter is worth ₹54900. Its value falls by 10% every year. What will it be worth after 2 years (in ₹)?
37. 37.What amount will ₹52300 grow to in 1 year at 8% per year compound interest (in ₹)?
38. 38.What amount will ₹16000 grow to in 1 year at 10% per year compound interest (in ₹)?
39. 39.Find the compound interest on ₹19200 at 20% per year for 2 years, compounded every year (in ₹).
40. 40.What amount will ₹52000 grow to in 1 year at 25% per year compound interest (in ₹)?

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