Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 636 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.What is the difference between the compound interest and the simple interest on ₹16400 at 25% per year for 2 years (in ₹)?
2. 2.Find the compound interest on ₹32000 at 5% per year for 3 years, compounded every year (in ₹).
3. 3.What is the difference between the compound interest and the simple interest on ₹2500 at 4% per year for 2 years (in ₹)?
4. 4.A scooter is worth ₹56000. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
5. 5.A scooter is worth ₹46000. Its value falls by 20% every year. What will it be worth after 3 years (in ₹)?
6. 6.What amount will ₹2500 grow to in 2 years at 12% per year compound interest (in ₹)?
7. 7.A scooter is worth ₹17000. Its value falls by 20% every year. What will it be worth after 3 years (in ₹)?
8. 8.Find the compound interest on ₹33600 at 25% per year for 3 years, compounded every year (in ₹).
9. 9.What amount will ₹19000 grow to in 1 year at 15% per year compound interest (in ₹)?
10. 10.What is the difference between the compound interest and the simple interest on ₹8600 at 10% per year for 2 years (in ₹)?
11. 11.Find the compound interest on ₹51000 at 10% per year for 3 years, compounded every year (in ₹).
12. 12.A scooter is worth ₹2800. Its value falls by 25% every year. What will it be worth after 2 years (in ₹)?
13. 13.Find the compound interest on ₹11400 at 4% per year for 1 year, compounded every year (in ₹).
14. 14.What is the difference between the compound interest and the simple interest on ₹40000 at 8% per year for 2 years (in ₹)?
15. 15.A town has 15600 people. The population grows by 4% every year. What will the population be after 1 year?
16. 16.A scooter is worth ₹58400. Its value falls by 15% every year. What will it be worth after 2 years (in ₹)?
17. 17.What amount will ₹23600 grow to in 1 year at 5% per year compound interest (in ₹)?
18. 18.What amount will ₹23400 grow to in 1 year at 10% per year compound interest (in ₹)?
19. 19.What amount will ₹2800 grow to in 2 years at 5% per year compound interest (in ₹)?
20. 20.What is the difference between the compound interest and the simple interest on ₹31500 at 20% per year for 2 years (in ₹)?
21. 21.Find the compound interest on ₹25000 at 12% per year for 2 years, compounded every year (in ₹).
22. 22.A scooter is worth ₹7600. Its value falls by 25% every year. What will it be worth after 1 year (in ₹)?
23. 23.What is the difference between the compound interest and the simple interest on ₹48700 at 10% per year for 2 years (in ₹)?
24. 24.What is the difference between the compound interest and the simple interest on ₹32800 at 5% per year for 2 years (in ₹)?
25. 25.Find the compound interest on ₹14400 at 25% per year for 3 years, compounded every year (in ₹).
26. 26.A scooter is worth ₹9600. Its value falls by 15% every year. What will it be worth after 1 year (in ₹)?
27. 27.What amount will ₹17400 grow to in 1 year at 5% per year compound interest (in ₹)?
28. 28.A scooter is worth ₹32100. Its value falls by 12% every year. What will it be worth after 1 year (in ₹)?
29. 29.What is the difference between the compound interest and the simple interest on ₹15000 at 12% per year for 2 years (in ₹)?
30. 30.A scooter is worth ₹38700. Its value falls by 15% every year. What will it be worth after 1 year (in ₹)?
31. 31.Find the compound interest on ₹14600 at 15% per year for 1 year, compounded every year (in ₹).
32. 32.A town has 3500 people. The population grows by 20% every year. What will the population be after 3 years?
33. 33.A town has 9200 people. The population grows by 5% every year. What will the population be after 2 years?
34. 34.Find the compound interest on ₹19600 at 20% per year for 2 years, compounded every year (in ₹).
35. 35.What amount will ₹23900 grow to in 1 year at 4% per year compound interest (in ₹)?
36. 36.Find the compound interest on ₹14700 at 8% per year for 1 year, compounded every year (in ₹).
37. 37.What is the difference between the compound interest and the simple interest on ₹26300 at 20% per year for 2 years (in ₹)?
38. 38.What is the difference between the compound interest and the simple interest on ₹60000 at 4% per year for 2 years (in ₹)?
39. 39.Find the compound interest on ₹54400 at 20% per year for 2 years, compounded every year (in ₹).
40. 40.A town has 28700 people. The population grows by 4% every year. What will the population be after 1 year?

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