Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 637 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.What is the difference between the compound interest and the simple interest on ₹6100 at 10% per year for 2 years (in ₹)?
2. 2.Find the compound interest on ₹50000 at 8% per year for 2 years, compounded every year (in ₹).
3. 3.What is the difference between the compound interest and the simple interest on ₹58000 at 25% per year for 2 years (in ₹)?
4. 4.What is the difference between the compound interest and the simple interest on ₹57500 at 8% per year for 2 years (in ₹)?
5. 5.Find the compound interest on ₹38200 at 10% per year for 2 years, compounded every year (in ₹).
6. 6.Find the compound interest on ₹24000 at 5% per year for 3 years, compounded every year (in ₹).
7. 7.Find the compound interest on ₹53200 at 25% per year for 2 years, compounded every year (in ₹).
8. 8.Find the compound interest on ₹40000 at 25% per year for 3 years, compounded every year (in ₹).
9. 9.What amount will ₹41700 grow to in 1 year at 25% per year compound interest (in ₹)?
10. 10.Find the compound interest on ₹25000 at 8% per year for 2 years, compounded every year (in ₹).
11. 11.A town has 46700 people. The population grows by 20% every year. What will the population be after 1 year?
12. 12.A town has 22500 people. The population grows by 8% every year. What will the population be after 2 years?
13. 13.What is the difference between the compound interest and the simple interest on ₹8800 at 25% per year for 2 years (in ₹)?
14. 14.What is the difference between the compound interest and the simple interest on ₹11900 at 10% per year for 2 years (in ₹)?
15. 15.Find the compound interest on ₹48000 at 5% per year for 3 years, compounded every year (in ₹).
16. 16.Find the compound interest on ₹3000 at 20% per year for 1 year, compounded every year (in ₹).
17. 17.What amount will ₹52300 grow to in 2 years at 20% per year compound interest (in ₹)?
18. 18.What amount will ₹23000 grow to in 3 years at 10% per year compound interest (in ₹)?
19. 19.What amount will ₹38500 grow to in 1 year at 15% per year compound interest (in ₹)?
20. 20.What is the difference between the compound interest and the simple interest on ₹8000 at 5% per year for 2 years (in ₹)?
21. 21.A scooter is worth ₹21700. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
22. 22.What amount will ₹17500 grow to in 2 years at 12% per year compound interest (in ₹)?
23. 23.A town has 18400 people. The population grows by 5% every year. What will the population be after 2 years?
24. 24.Find the compound interest on ₹26800 at 5% per year for 1 year, compounded every year (in ₹).
25. 25.Find the compound interest on ₹6000 at 10% per year for 3 years, compounded every year (in ₹).
26. 26.What amount will ₹57600 grow to in 2 years at 20% per year compound interest (in ₹)?
27. 27.A scooter is worth ₹42100. Its value falls by 20% every year. What will it be worth after 2 years (in ₹)?
28. 28.Find the compound interest on ₹33600 at 25% per year for 3 years, compounded every year (in ₹).
29. 29.What is the difference between the compound interest and the simple interest on ₹31200 at 25% per year for 2 years (in ₹)?
30. 30.What amount will ₹6000 grow to in 1 year at 4% per year compound interest (in ₹)?
31. 31.What amount will ₹50000 grow to in 2 years at 12% per year compound interest (in ₹)?
32. 32.What amount will ₹22500 grow to in 2 years at 8% per year compound interest (in ₹)?
33. 33.Find the compound interest on ₹49200 at 10% per year for 1 year, compounded every year (in ₹).
34. 34.A scooter is worth ₹40400. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
35. 35.A town has 10900 people. The population grows by 5% every year. What will the population be after 1 year?
36. 36.Find the compound interest on ₹41500 at 10% per year for 1 year, compounded every year (in ₹).
37. 37.What is the difference between the compound interest and the simple interest on ₹10400 at 25% per year for 2 years (in ₹)?
38. 38.What amount will ₹18900 grow to in 1 year at 12% per year compound interest (in ₹)?
39. 39.A scooter is worth ₹8100. Its value falls by 20% every year. What will it be worth after 1 year (in ₹)?
40. 40.Find the compound interest on ₹44000 at 20% per year for 3 years, compounded every year (in ₹).

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