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Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 643 · 40 sums
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The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

NameDateTime takenScore ___ / 40
  1. 1.What amount will ₹37600 grow to in 2 years at 10% per year compound interest (in ₹)?
  2. 2.A town has 13600 people. The population grows by 5% every year. What will the population be after 2 years?
  3. 3.What amount will ₹34800 grow to in 1 year at 12% per year compound interest (in ₹)?
  4. 4.Find the compound interest on ₹2800 at 25% per year for 2 years, compounded every year (in ₹).
  5. 5.Find the compound interest on ₹22100 at 12% per year for 1 year, compounded every year (in ₹).
  6. 6.What is the difference between the compound interest and the simple interest on ₹30000 at 8% per year for 2 years (in ₹)?
  7. 7.A scooter is worth ₹7800. Its value falls by 25% every year. What will it be worth after 1 year (in ₹)?
  8. 8.Find the compound interest on ₹28700 at 12% per year for 1 year, compounded every year (in ₹).
  9. 9.Find the compound interest on ₹10000 at 4% per year for 2 years, compounded every year (in ₹).
  10. 10.What amount will ₹10500 grow to in 2 years at 10% per year compound interest (in ₹)?
  11. 11.A scooter is worth ₹30900. Its value falls by 20% every year. What will it be worth after 1 year (in ₹)?
  12. 12.What is the difference between the compound interest and the simple interest on ₹34500 at 20% per year for 2 years (in ₹)?
  13. 13.What amount will ₹33500 grow to in 3 years at 20% per year compound interest (in ₹)?
  14. 14.What amount will ₹49700 grow to in 2 years at 20% per year compound interest (in ₹)?
  15. 15.Find the compound interest on ₹60000 at 15% per year for 2 years, compounded every year (in ₹).
  16. 16.What is the difference between the compound interest and the simple interest on ₹7500 at 12% per year for 2 years (in ₹)?
  17. 17.What amount will ₹13900 grow to in 2 years at 10% per year compound interest (in ₹)?
  18. 18.What amount will ₹42500 grow to in 2 years at 8% per year compound interest (in ₹)?
  19. 19.A scooter is worth ₹50200. Its value falls by 25% every year. What will it be worth after 1 year (in ₹)?
  20. 20.Find the compound interest on ₹11700 at 10% per year for 1 year, compounded every year (in ₹).
  21. 21.What is the difference between the compound interest and the simple interest on ₹46800 at 25% per year for 2 years (in ₹)?
  22. 22.A town has 14700 people. The population grows by 20% every year. What will the population be after 2 years?
  23. 23.Find the compound interest on ₹35100 at 12% per year for 1 year, compounded every year (in ₹).
  24. 24.A town has 26800 people. The population grows by 25% every year. What will the population be after 2 years?
  25. 25.Find the compound interest on ₹34200 at 12% per year for 1 year, compounded every year (in ₹).
  26. 26.A scooter is worth ₹9200. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
  27. 27.What is the difference between the compound interest and the simple interest on ₹51600 at 5% per year for 2 years (in ₹)?
  28. 28.What is the difference between the compound interest and the simple interest on ₹17600 at 15% per year for 2 years (in ₹)?
  29. 29.What amount will ₹45500 grow to in 1 year at 4% per year compound interest (in ₹)?
  30. 30.Find the compound interest on ₹54000 at 25% per year for 2 years, compounded every year (in ₹).
  31. 31.Find the compound interest on ₹9600 at 25% per year for 3 years, compounded every year (in ₹).
  32. 32.What is the difference between the compound interest and the simple interest on ₹45000 at 8% per year for 2 years (in ₹)?
  33. 33.What amount will ₹38100 grow to in 2 years at 10% per year compound interest (in ₹)?
  34. 34.What amount will ₹9400 grow to in 2 years at 20% per year compound interest (in ₹)?
  35. 35.A town has 48800 people. The population grows by 25% every year. What will the population be after 1 year?
  36. 36.What amount will ₹58400 grow to in 2 years at 5% per year compound interest (in ₹)?
  37. 37.Find the compound interest on ₹2500 at 12% per year for 2 years, compounded every year (in ₹).
  38. 38.Find the compound interest on ₹50200 at 12% per year for 1 year, compounded every year (in ₹).
  39. 39.What is the difference between the compound interest and the simple interest on ₹43200 at 25% per year for 2 years (in ₹)?
  40. 40.Find the compound interest on ₹45200 at 15% per year for 2 years, compounded every year (in ₹).

Answer key

  1. 45496
  2. 14994
  3. 38976
  4. 1575
  5. 2652
  6. 192
  7. 5850
  8. 3444
  9. 816
  10. 12705
  11. 24720
  12. 1380
  13. 57888
  14. 71568
  15. 19350
  16. 108
  17. 16819
  18. 49572
  19. 37650
  20. 1170
  21. 2925
  22. 21168
  23. 4212
  24. 41875
  25. 4104
  26. 8303
  27. 129
  28. 396
  29. 47320
  30. 30375
  31. 9150
  32. 288
  33. 46101
  34. 13536
  35. 61000
  36. 64386
  37. 636
  38. 6024
  39. 2700
  40. 14577

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