Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 651 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.What amount will ₹36800 grow to in 2 years at 25% per year compound interest (in ₹)?
2. 2.What amount will ₹13100 grow to in 1 year at 4% per year compound interest (in ₹)?
3. 3.A town has 14500 people. The population grows by 4% every year. What will the population be after 1 year?
4. 4.What is the difference between the compound interest and the simple interest on ₹24800 at 5% per year for 2 years (in ₹)?
5. 5.What is the difference between the compound interest and the simple interest on ₹60000 at 4% per year for 2 years (in ₹)?
6. 6.What amount will ₹38400 grow to in 2 years at 5% per year compound interest (in ₹)?
7. 7.Find the compound interest on ₹5000 at 12% per year for 1 year, compounded every year (in ₹).
8. 8.A town has 44000 people. The population grows by 10% every year. What will the population be after 2 years?
9. 9.Find the compound interest on ₹10000 at 8% per year for 2 years, compounded every year (in ₹).
10. 10.Find the compound interest on ₹40000 at 5% per year for 3 years, compounded every year (in ₹).
11. 11.A town has 29500 people. The population grows by 4% every year. What will the population be after 1 year?
12. 12.What amount will ₹40700 grow to in 1 year at 8% per year compound interest (in ₹)?
13. 13.What amount will ₹54500 grow to in 2 years at 10% per year compound interest (in ₹)?
14. 14.What amount will ₹8500 grow to in 1 year at 25% per year compound interest (in ₹)?
15. 15.What is the difference between the compound interest and the simple interest on ₹16800 at 25% per year for 2 years (in ₹)?
16. 16.What amount will ₹33300 grow to in 1 year at 10% per year compound interest (in ₹)?
17. 17.A town has 28800 people. The population grows by 25% every year. What will the population be after 3 years?
18. 18.Find the compound interest on ₹25000 at 8% per year for 2 years, compounded every year (in ₹).
19. 19.What is the difference between the compound interest and the simple interest on ₹45000 at 12% per year for 2 years (in ₹)?
20. 20.Find the compound interest on ₹5400 at 20% per year for 1 year, compounded every year (in ₹).
21. 21.A town has 26000 people. The population grows by 20% every year. What will the population be after 3 years?
22. 22.What is the difference between the compound interest and the simple interest on ₹3300 at 10% per year for 2 years (in ₹)?
23. 23.A town has 40000 people. The population grows by 5% every year. What will the population be after 3 years?
24. 24.A scooter is worth ₹49400. Its value falls by 15% every year. What will it be worth after 1 year (in ₹)?
25. 25.What is the difference between the compound interest and the simple interest on ₹40000 at 4% per year for 2 years (in ₹)?
26. 26.What amount will ₹47900 grow to in 1 year at 25% per year compound interest (in ₹)?
27. 27.A scooter is worth ₹27400. Its value falls by 4% every year. What will it be worth after 1 year (in ₹)?
28. 28.A scooter is worth ₹35700. Its value falls by 4% every year. What will it be worth after 1 year (in ₹)?
29. 29.What is the difference between the compound interest and the simple interest on ₹25000 at 8% per year for 2 years (in ₹)?
30. 30.Find the compound interest on ₹57200 at 5% per year for 2 years, compounded every year (in ₹).
31. 31.What amount will ₹59800 grow to in 1 year at 5% per year compound interest (in ₹)?
32. 32.A scooter is worth ₹35200. Its value falls by 25% every year. What will it be worth after 3 years (in ₹)?
33. 33.What is the difference between the compound interest and the simple interest on ₹35000 at 4% per year for 2 years (in ₹)?
34. 34.A town has 41600 people. The population grows by 15% every year. What will the population be after 2 years?
35. 35.Find the compound interest on ₹9400 at 8% per year for 1 year, compounded every year (in ₹).
36. 36.A scooter is worth ₹8000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
37. 37.Find the compound interest on ₹8500 at 20% per year for 3 years, compounded every year (in ₹).
38. 38.Find the compound interest on ₹46700 at 8% per year for 1 year, compounded every year (in ₹).
39. 39.Find the compound interest on ₹40400 at 15% per year for 2 years, compounded every year (in ₹).
40. 40.A scooter is worth ₹44500. Its value falls by 8% every year. What will it be worth after 1 year (in ₹)?

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