Class 8 Maths Worksheet: Compound Interest
The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.
NameDateTime takenScore ___ / 40
- 1.What amount will ₹59100 grow to in 1 year at 12% per year compound interest (in ₹)?
- 2.A town has 15000 people. The population grows by 12% every year. What will the population be after 2 years?
- 3.What is the difference between the compound interest and the simple interest on ₹54800 at 20% per year for 2 years (in ₹)?
- 4.Find the compound interest on ₹2500 at 8% per year for 2 years, compounded every year (in ₹).
- 5.What is the difference between the compound interest and the simple interest on ₹58400 at 5% per year for 2 years (in ₹)?
- 6.What amount will ₹44000 grow to in 2 years at 25% per year compound interest (in ₹)?
- 7.What amount will ₹46400 grow to in 3 years at 25% per year compound interest (in ₹)?
- 8.What amount will ₹14400 grow to in 1 year at 4% per year compound interest (in ₹)?
- 9.What amount will ₹5000 grow to in 2 years at 8% per year compound interest (in ₹)?
- 10.Find the compound interest on ₹18900 at 8% per year for 1 year, compounded every year (in ₹).
- 11.What amount will ₹13400 grow to in 1 year at 20% per year compound interest (in ₹)?
- 12.A scooter is worth ₹10400. Its value falls by 20% every year. What will it be worth after 2 years (in ₹)?
- 13.A scooter is worth ₹44200. Its value falls by 12% every year. What will it be worth after 1 year (in ₹)?
- 14.Find the compound interest on ₹34000 at 25% per year for 2 years, compounded every year (in ₹).
- 15.What amount will ₹18100 grow to in 1 year at 8% per year compound interest (in ₹)?
- 16.Find the compound interest on ₹13400 at 20% per year for 1 year, compounded every year (in ₹).
- 17.Find the compound interest on ₹36300 at 25% per year for 1 year, compounded every year (in ₹).
- 18.Find the compound interest on ₹15200 at 25% per year for 2 years, compounded every year (in ₹).
- 19.What is the difference between the compound interest and the simple interest on ₹2500 at 12% per year for 2 years (in ₹)?
- 20.What amount will ₹46900 grow to in 1 year at 25% per year compound interest (in ₹)?
- 21.What is the difference between the compound interest and the simple interest on ₹25900 at 10% per year for 2 years (in ₹)?
- 22.What amount will ₹52500 grow to in 2 years at 4% per year compound interest (in ₹)?
- 23.A scooter is worth ₹31500. Its value falls by 15% every year. What will it be worth after 1 year (in ₹)?
- 24.Find the compound interest on ₹54700 at 10% per year for 2 years, compounded every year (in ₹).
- 25.A scooter is worth ₹7500. Its value falls by 8% every year. What will it be worth after 2 years (in ₹)?
- 26.Find the compound interest on ₹56800 at 25% per year for 2 years, compounded every year (in ₹).
- 27.Find the compound interest on ₹24000 at 5% per year for 3 years, compounded every year (in ₹).
- 28.Find the compound interest on ₹9700 at 20% per year for 1 year, compounded every year (in ₹).
- 29.What amount will ₹7100 grow to in 2 years at 20% per year compound interest (in ₹)?
- 30.What is the difference between the compound interest and the simple interest on ₹48800 at 10% per year for 2 years (in ₹)?
- 31.A town has 11400 people. The population grows by 20% every year. What will the population be after 1 year?
- 32.What is the difference between the compound interest and the simple interest on ₹45200 at 5% per year for 2 years (in ₹)?
- 33.Find the compound interest on ₹28700 at 25% per year for 1 year, compounded every year (in ₹).
- 34.What is the difference between the compound interest and the simple interest on ₹5000 at 12% per year for 2 years (in ₹)?
- 35.What is the difference between the compound interest and the simple interest on ₹28800 at 25% per year for 2 years (in ₹)?
- 36.A scooter is worth ₹15600. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
- 37.What amount will ₹16000 grow to in 3 years at 25% per year compound interest (in ₹)?
- 38.A town has 31900 people. The population grows by 4% every year. What will the population be after 1 year?
- 39.Find the compound interest on ₹48700 at 12% per year for 1 year, compounded every year (in ₹).
- 40.What is the difference between the compound interest and the simple interest on ₹3200 at 5% per year for 2 years (in ₹)?
Answer key
- 66192
- 18816
- 2192
- 416
- 146
- 68750
- 90625
- 14976
- 5832
- 1512
- 16080
- 6656
- 38896
- 19125
- 19548
- 2680
- 9075
- 8550
- 36
- 58625
- 259
- 56784
- 26775
- 11487
- 6348
- 31950
- 3783
- 1940
- 10224
- 488
- 13680
- 113
- 7175
- 72
- 1800
- 14079
- 31250
- 33176
- 5844
- 8
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