Class 8 Maths Worksheet: Compound Interest
The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.
NameDateTime takenScore ___ / 40
- 1.What is the difference between the compound interest and the simple interest on ₹17900 at 20% per year for 2 years (in ₹)?
- 2.A town has 16000 people. The population grows by 5% every year. What will the population be after 3 years?
- 3.Find the compound interest on ₹12500 at 10% per year for 1 year, compounded every year (in ₹).
- 4.A town has 40000 people. The population grows by 15% every year. What will the population be after 3 years?
- 5.A town has 56000 people. The population grows by 25% every year. What will the population be after 3 years?
- 6.A town has 40000 people. The population grows by 5% every year. What will the population be after 3 years?
- 7.What is the difference between the compound interest and the simple interest on ₹56300 at 10% per year for 2 years (in ₹)?
- 8.A scooter is worth ₹30600. Its value falls by 8% every year. What will it be worth after 1 year (in ₹)?
- 9.A town has 36800 people. The population grows by 5% every year. What will the population be after 1 year?
- 10.What is the difference between the compound interest and the simple interest on ₹55000 at 4% per year for 2 years (in ₹)?
- 11.A town has 40000 people. The population grows by 12% every year. What will the population be after 2 years?
- 12.What amount will ₹8000 grow to in 3 years at 15% per year compound interest (in ₹)?
- 13.What amount will ₹26000 grow to in 2 years at 25% per year compound interest (in ₹)?
- 14.Find the compound interest on ₹7500 at 12% per year for 2 years, compounded every year (in ₹).
- 15.What is the difference between the compound interest and the simple interest on ₹16800 at 5% per year for 2 years (in ₹)?
- 16.Find the compound interest on ₹41700 at 20% per year for 1 year, compounded every year (in ₹).
- 17.What amount will ₹47600 grow to in 1 year at 4% per year compound interest (in ₹)?
- 18.What is the difference between the compound interest and the simple interest on ₹12500 at 12% per year for 2 years (in ₹)?
- 19.Find the compound interest on ₹30700 at 20% per year for 1 year, compounded every year (in ₹).
- 20.What amount will ₹9900 grow to in 1 year at 20% per year compound interest (in ₹)?
- 21.Find the compound interest on ₹43500 at 20% per year for 3 years, compounded every year (in ₹).
- 22.What is the difference between the compound interest and the simple interest on ₹30000 at 5% per year for 2 years (in ₹)?
- 23.A town has 26000 people. The population grows by 10% every year. What will the population be after 3 years?
- 24.A scooter is worth ₹21100. Its value falls by 12% every year. What will it be worth after 1 year (in ₹)?
- 25.Find the compound interest on ₹8000 at 5% per year for 3 years, compounded every year (in ₹).
- 26.A town has 57000 people. The population grows by 10% every year. What will the population be after 3 years?
- 27.What amount will ₹16800 grow to in 2 years at 15% per year compound interest (in ₹)?
- 28.Find the compound interest on ₹23300 at 10% per year for 1 year, compounded every year (in ₹).
- 29.A scooter is worth ₹7000. Its value falls by 15% every year. What will it be worth after 1 year (in ₹)?
- 30.What is the difference between the compound interest and the simple interest on ₹55200 at 5% per year for 2 years (in ₹)?
- 31.Find the compound interest on ₹39600 at 5% per year for 1 year, compounded every year (in ₹).
- 32.What is the difference between the compound interest and the simple interest on ₹31200 at 5% per year for 2 years (in ₹)?
- 33.What amount will ₹5000 grow to in 2 years at 12% per year compound interest (in ₹)?
- 34.Find the compound interest on ₹5000 at 10% per year for 3 years, compounded every year (in ₹).
- 35.What is the difference between the compound interest and the simple interest on ₹12500 at 4% per year for 2 years (in ₹)?
- 36.Find the compound interest on ₹32800 at 5% per year for 2 years, compounded every year (in ₹).
- 37.A town has 21500 people. The population grows by 20% every year. What will the population be after 3 years?
- 38.Find the compound interest on ₹13900 at 8% per year for 1 year, compounded every year (in ₹).
- 39.What is the difference between the compound interest and the simple interest on ₹39300 at 20% per year for 2 years (in ₹)?
- 40.What amount will ₹19500 grow to in 3 years at 20% per year compound interest (in ₹)?
Answer key
- 716
- 18522
- 1250
- 60835
- 109375
- 46305
- 563
- 28152
- 38640
- 88
- 50176
- 12167
- 40625
- 1908
- 42
- 8340
- 49504
- 180
- 6140
- 11880
- 31668
- 75
- 34606
- 18568
- 1261
- 75867
- 22218
- 2330
- 5950
- 138
- 1980
- 78
- 6272
- 1655
- 20
- 3362
- 37152
- 1112
- 1572
- 33696
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