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Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 658 · 40 sums
TalentJR

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

NameDateTime takenScore ___ / 40
  1. 1.Find the compound interest on ₹15600 at 5% per year for 1 year, compounded every year (in ₹).
  2. 2.What is the difference between the compound interest and the simple interest on ₹45200 at 25% per year for 2 years (in ₹)?
  3. 3.What amount will ₹24000 grow to in 3 years at 5% per year compound interest (in ₹)?
  4. 4.What is the difference between the compound interest and the simple interest on ₹57400 at 10% per year for 2 years (in ₹)?
  5. 5.What is the difference between the compound interest and the simple interest on ₹25600 at 25% per year for 2 years (in ₹)?
  6. 6.Find the compound interest on ₹16000 at 15% per year for 2 years, compounded every year (in ₹).
  7. 7.What is the difference between the compound interest and the simple interest on ₹41200 at 15% per year for 2 years (in ₹)?
  8. 8.Find the compound interest on ₹54700 at 15% per year for 1 year, compounded every year (in ₹).
  9. 9.Find the compound interest on ₹35400 at 8% per year for 1 year, compounded every year (in ₹).
  10. 10.What is the difference between the compound interest and the simple interest on ₹2200 at 10% per year for 2 years (in ₹)?
  11. 11.What amount will ₹48500 grow to in 3 years at 20% per year compound interest (in ₹)?
  12. 12.What is the difference between the compound interest and the simple interest on ₹15000 at 8% per year for 2 years (in ₹)?
  13. 13.What is the difference between the compound interest and the simple interest on ₹60000 at 15% per year for 2 years (in ₹)?
  14. 14.What amount will ₹8100 grow to in 2 years at 10% per year compound interest (in ₹)?
  15. 15.Find the compound interest on ₹14000 at 15% per year for 2 years, compounded every year (in ₹).
  16. 16.What amount will ₹26300 grow to in 1 year at 20% per year compound interest (in ₹)?
  17. 17.Find the compound interest on ₹5000 at 12% per year for 2 years, compounded every year (in ₹).
  18. 18.A scooter is worth ₹52300. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
  19. 19.A town has 29100 people. The population grows by 8% every year. What will the population be after 1 year?
  20. 20.What is the difference between the compound interest and the simple interest on ₹17700 at 20% per year for 2 years (in ₹)?
  21. 21.Find the compound interest on ₹41300 at 10% per year for 1 year, compounded every year (in ₹).
  22. 22.What is the difference between the compound interest and the simple interest on ₹55000 at 4% per year for 2 years (in ₹)?
  23. 23.What amount will ₹52800 grow to in 2 years at 15% per year compound interest (in ₹)?
  24. 24.What amount will ₹31200 grow to in 2 years at 25% per year compound interest (in ₹)?
  25. 25.What is the difference between the compound interest and the simple interest on ₹14400 at 15% per year for 2 years (in ₹)?
  26. 26.What amount will ₹52500 grow to in 2 years at 8% per year compound interest (in ₹)?
  27. 27.A scooter is worth ₹27500. Its value falls by 8% every year. What will it be worth after 2 years (in ₹)?
  28. 28.Find the compound interest on ₹21000 at 20% per year for 3 years, compounded every year (in ₹).
  29. 29.What amount will ₹41200 grow to in 2 years at 15% per year compound interest (in ₹)?
  30. 30.A town has 12000 people. The population grows by 10% every year. What will the population be after 1 year?
  31. 31.What is the difference between the compound interest and the simple interest on ₹3300 at 20% per year for 2 years (in ₹)?
  32. 32.What is the difference between the compound interest and the simple interest on ₹30000 at 8% per year for 2 years (in ₹)?
  33. 33.Find the compound interest on ₹52500 at 20% per year for 3 years, compounded every year (in ₹).
  34. 34.Find the compound interest on ₹32500 at 8% per year for 2 years, compounded every year (in ₹).
  35. 35.What amount will ₹16000 grow to in 3 years at 15% per year compound interest (in ₹)?
  36. 36.What is the difference between the compound interest and the simple interest on ₹12500 at 12% per year for 2 years (in ₹)?
  37. 37.A scooter is worth ₹17500. Its value falls by 4% every year. What will it be worth after 2 years (in ₹)?
  38. 38.A town has 36800 people. The population grows by 15% every year. What will the population be after 1 year?
  39. 39.What is the difference between the compound interest and the simple interest on ₹18400 at 25% per year for 2 years (in ₹)?
  40. 40.What amount will ₹20000 grow to in 3 years at 10% per year compound interest (in ₹)?

Answer key

  1. 780
  2. 2825
  3. 27783
  4. 574
  5. 1600
  6. 5160
  7. 927
  8. 8205
  9. 2832
  10. 22
  11. 83808
  12. 96
  13. 1350
  14. 9801
  15. 4515
  16. 31560
  17. 1272
  18. 47070
  19. 31428
  20. 708
  21. 4130
  22. 88
  23. 69828
  24. 48750
  25. 324
  26. 61236
  27. 23276
  28. 15288
  29. 54487
  30. 13200
  31. 132
  32. 192
  33. 38220
  34. 5408
  35. 24334
  36. 180
  37. 16128
  38. 42320
  39. 1150
  40. 26620

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