← Compound interest lesson New set →

Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 659 · 40 sums
TalentJR

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

NameDateTime takenScore ___ / 40
  1. 1.What amount will ₹32300 grow to in 1 year at 5% per year compound interest (in ₹)?
  2. 2.Find the compound interest on ₹22400 at 15% per year for 2 years, compounded every year (in ₹).
  3. 3.What is the difference between the compound interest and the simple interest on ₹55300 at 20% per year for 2 years (in ₹)?
  4. 4.What amount will ₹38000 grow to in 2 years at 20% per year compound interest (in ₹)?
  5. 5.What is the difference between the compound interest and the simple interest on ₹55000 at 8% per year for 2 years (in ₹)?
  6. 6.Find the compound interest on ₹18400 at 15% per year for 2 years, compounded every year (in ₹).
  7. 7.What is the difference between the compound interest and the simple interest on ₹47200 at 20% per year for 2 years (in ₹)?
  8. 8.What amount will ₹27700 grow to in 1 year at 25% per year compound interest (in ₹)?
  9. 9.What is the difference between the compound interest and the simple interest on ₹29000 at 10% per year for 2 years (in ₹)?
  10. 10.Find the compound interest on ₹24000 at 20% per year for 3 years, compounded every year (in ₹).
  11. 11.A town has 37500 people. The population grows by 8% every year. What will the population be after 2 years?
  12. 12.Find the compound interest on ₹8700 at 25% per year for 1 year, compounded every year (in ₹).
  13. 13.What is the difference between the compound interest and the simple interest on ₹27200 at 15% per year for 2 years (in ₹)?
  14. 14.What is the difference between the compound interest and the simple interest on ₹45000 at 8% per year for 2 years (in ₹)?
  15. 15.Find the compound interest on ₹29400 at 10% per year for 1 year, compounded every year (in ₹).
  16. 16.What is the difference between the compound interest and the simple interest on ₹58200 at 10% per year for 2 years (in ₹)?
  17. 17.Find the compound interest on ₹19100 at 15% per year for 1 year, compounded every year (in ₹).
  18. 18.A scooter is worth ₹38500. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
  19. 19.What amount will ₹2500 grow to in 2 years at 4% per year compound interest (in ₹)?
  20. 20.What amount will ₹59300 grow to in 1 year at 12% per year compound interest (in ₹)?
  21. 21.A town has 6300 people. The population grows by 8% every year. What will the population be after 1 year?
  22. 22.What amount will ₹55500 grow to in 1 year at 8% per year compound interest (in ₹)?
  23. 23.A town has 20800 people. The population grows by 25% every year. What will the population be after 2 years?
  24. 24.A town has 53900 people. The population grows by 10% every year. What will the population be after 1 year?
  25. 25.What is the difference between the compound interest and the simple interest on ₹50000 at 15% per year for 2 years (in ₹)?
  26. 26.Find the compound interest on ₹36800 at 10% per year for 2 years, compounded every year (in ₹).
  27. 27.A town has 59500 people. The population grows by 10% every year. What will the population be after 2 years?
  28. 28.Find the compound interest on ₹5600 at 10% per year for 1 year, compounded every year (in ₹).
  29. 29.What amount will ₹20000 grow to in 2 years at 8% per year compound interest (in ₹)?
  30. 30.What is the difference between the compound interest and the simple interest on ₹18400 at 5% per year for 2 years (in ₹)?
  31. 31.A town has 5000 people. The population grows by 4% every year. What will the population be after 2 years?
  32. 32.What amount will ₹21600 grow to in 2 years at 25% per year compound interest (in ₹)?
  33. 33.Find the compound interest on ₹56000 at 5% per year for 3 years, compounded every year (in ₹).
  34. 34.What amount will ₹50000 grow to in 2 years at 5% per year compound interest (in ₹)?
  35. 35.A town has 10000 people. The population grows by 4% every year. What will the population be after 2 years?
  36. 36.Find the compound interest on ₹31600 at 15% per year for 2 years, compounded every year (in ₹).
  37. 37.Find the compound interest on ₹39600 at 15% per year for 2 years, compounded every year (in ₹).
  38. 38.What is the difference between the compound interest and the simple interest on ₹16800 at 25% per year for 2 years (in ₹)?
  39. 39.What is the difference between the compound interest and the simple interest on ₹60000 at 4% per year for 2 years (in ₹)?
  40. 40.A town has 7400 people. The population grows by 8% every year. What will the population be after 1 year?

Answer key

  1. 33915
  2. 7224
  3. 2212
  4. 54720
  5. 352
  6. 5934
  7. 1888
  8. 34625
  9. 290
  10. 17472
  11. 43740
  12. 2175
  13. 612
  14. 288
  15. 2940
  16. 582
  17. 2865
  18. 36575
  19. 2704
  20. 66416
  21. 6804
  22. 59940
  23. 32500
  24. 59290
  25. 1125
  26. 7728
  27. 71995
  28. 560
  29. 23328
  30. 46
  31. 5408
  32. 33750
  33. 8827
  34. 55125
  35. 10816
  36. 10191
  37. 12771
  38. 1050
  39. 96
  40. 7992

Free maths worksheets lessons, practice and worksheets at talentjr.in/maths-worksheets