Class 8 Maths Worksheet: Compound Interest
The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.
NameDateTime takenScore ___ / 40
- 1.What is the difference between the compound interest and the simple interest on ₹34800 at 5% per year for 2 years (in ₹)?
- 2.What is the difference between the compound interest and the simple interest on ₹55200 at 15% per year for 2 years (in ₹)?
- 3.What is the difference between the compound interest and the simple interest on ₹55000 at 4% per year for 2 years (in ₹)?
- 4.Find the compound interest on ₹8000 at 25% per year for 3 years, compounded every year (in ₹).
- 5.A town has 2900 people. The population grows by 20% every year. What will the population be after 1 year?
- 6.Find the compound interest on ₹45000 at 12% per year for 2 years, compounded every year (in ₹).
- 7.Find the compound interest on ₹32900 at 20% per year for 2 years, compounded every year (in ₹).
- 8.What amount will ₹16000 grow to in 3 years at 5% per year compound interest (in ₹)?
- 9.What is the difference between the compound interest and the simple interest on ₹3000 at 20% per year for 2 years (in ₹)?
- 10.Find the compound interest on ₹26600 at 10% per year for 2 years, compounded every year (in ₹).
- 11.What is the difference between the compound interest and the simple interest on ₹18800 at 25% per year for 2 years (in ₹)?
- 12.A scooter is worth ₹39000. Its value falls by 20% every year. What will it be worth after 3 years (in ₹)?
- 13.A town has 4900 people. The population grows by 10% every year. What will the population be after 1 year?
- 14.Find the compound interest on ₹19400 at 10% per year for 1 year, compounded every year (in ₹).
- 15.What amount will ₹16000 grow to in 3 years at 25% per year compound interest (in ₹)?
- 16.A scooter is worth ₹7500. Its value falls by 12% every year. What will it be worth after 2 years (in ₹)?
- 17.What amount will ₹40000 grow to in 3 years at 5% per year compound interest (in ₹)?
- 18.Find the compound interest on ₹2600 at 8% per year for 1 year, compounded every year (in ₹).
- 19.A scooter is worth ₹43600. Its value falls by 15% every year. What will it be worth after 1 year (in ₹)?
- 20.What is the difference between the compound interest and the simple interest on ₹2800 at 20% per year for 2 years (in ₹)?
- 21.A town has 35500 people. The population grows by 10% every year. What will the population be after 1 year?
- 22.A town has 43000 people. The population grows by 15% every year. What will the population be after 1 year?
- 23.What is the difference between the compound interest and the simple interest on ₹12500 at 8% per year for 2 years (in ₹)?
- 24.Find the compound interest on ₹30400 at 25% per year for 2 years, compounded every year (in ₹).
- 25.What is the difference between the compound interest and the simple interest on ₹46400 at 5% per year for 2 years (in ₹)?
- 26.A scooter is worth ₹56000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
- 27.A scooter is worth ₹14400. Its value falls by 25% every year. What will it be worth after 3 years (in ₹)?
- 28.A scooter is worth ₹22400. Its value falls by 25% every year. What will it be worth after 2 years (in ₹)?
- 29.What amount will ₹54800 grow to in 2 years at 5% per year compound interest (in ₹)?
- 30.What amount will ₹50000 grow to in 2 years at 12% per year compound interest (in ₹)?
- 31.What is the difference between the compound interest and the simple interest on ₹52500 at 4% per year for 2 years (in ₹)?
- 32.What amount will ₹48000 grow to in 3 years at 5% per year compound interest (in ₹)?
- 33.What is the difference between the compound interest and the simple interest on ₹53900 at 20% per year for 2 years (in ₹)?
- 34.A town has 60000 people. The population grows by 4% every year. What will the population be after 1 year?
- 35.What amount will ₹22300 grow to in 1 year at 25% per year compound interest (in ₹)?
- 36.What amount will ₹16000 grow to in 3 years at 15% per year compound interest (in ₹)?
- 37.What is the difference between the compound interest and the simple interest on ₹46400 at 25% per year for 2 years (in ₹)?
- 38.Find the compound interest on ₹6500 at 8% per year for 1 year, compounded every year (in ₹).
- 39.What amount will ₹39600 grow to in 1 year at 12% per year compound interest (in ₹)?
- 40.Find the compound interest on ₹16000 at 5% per year for 3 years, compounded every year (in ₹).
Answer key
- 87
- 1242
- 88
- 7625
- 3480
- 11448
- 14476
- 18522
- 120
- 5586
- 1175
- 19968
- 5390
- 1940
- 31250
- 5808
- 46305
- 208
- 37060
- 112
- 39050
- 49450
- 80
- 17100
- 116
- 48013
- 6075
- 12600
- 60417
- 62720
- 84
- 55566
- 2156
- 62400
- 27875
- 24334
- 2900
- 520
- 44352
- 2522
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