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Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 665 · 40 sums
TalentJR

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

NameDateTime takenScore ___ / 40
  1. 1.What is the difference between the compound interest and the simple interest on ₹34800 at 5% per year for 2 years (in ₹)?
  2. 2.What is the difference between the compound interest and the simple interest on ₹55200 at 15% per year for 2 years (in ₹)?
  3. 3.What is the difference between the compound interest and the simple interest on ₹55000 at 4% per year for 2 years (in ₹)?
  4. 4.Find the compound interest on ₹8000 at 25% per year for 3 years, compounded every year (in ₹).
  5. 5.A town has 2900 people. The population grows by 20% every year. What will the population be after 1 year?
  6. 6.Find the compound interest on ₹45000 at 12% per year for 2 years, compounded every year (in ₹).
  7. 7.Find the compound interest on ₹32900 at 20% per year for 2 years, compounded every year (in ₹).
  8. 8.What amount will ₹16000 grow to in 3 years at 5% per year compound interest (in ₹)?
  9. 9.What is the difference between the compound interest and the simple interest on ₹3000 at 20% per year for 2 years (in ₹)?
  10. 10.Find the compound interest on ₹26600 at 10% per year for 2 years, compounded every year (in ₹).
  11. 11.What is the difference between the compound interest and the simple interest on ₹18800 at 25% per year for 2 years (in ₹)?
  12. 12.A scooter is worth ₹39000. Its value falls by 20% every year. What will it be worth after 3 years (in ₹)?
  13. 13.A town has 4900 people. The population grows by 10% every year. What will the population be after 1 year?
  14. 14.Find the compound interest on ₹19400 at 10% per year for 1 year, compounded every year (in ₹).
  15. 15.What amount will ₹16000 grow to in 3 years at 25% per year compound interest (in ₹)?
  16. 16.A scooter is worth ₹7500. Its value falls by 12% every year. What will it be worth after 2 years (in ₹)?
  17. 17.What amount will ₹40000 grow to in 3 years at 5% per year compound interest (in ₹)?
  18. 18.Find the compound interest on ₹2600 at 8% per year for 1 year, compounded every year (in ₹).
  19. 19.A scooter is worth ₹43600. Its value falls by 15% every year. What will it be worth after 1 year (in ₹)?
  20. 20.What is the difference between the compound interest and the simple interest on ₹2800 at 20% per year for 2 years (in ₹)?
  21. 21.A town has 35500 people. The population grows by 10% every year. What will the population be after 1 year?
  22. 22.A town has 43000 people. The population grows by 15% every year. What will the population be after 1 year?
  23. 23.What is the difference between the compound interest and the simple interest on ₹12500 at 8% per year for 2 years (in ₹)?
  24. 24.Find the compound interest on ₹30400 at 25% per year for 2 years, compounded every year (in ₹).
  25. 25.What is the difference between the compound interest and the simple interest on ₹46400 at 5% per year for 2 years (in ₹)?
  26. 26.A scooter is worth ₹56000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
  27. 27.A scooter is worth ₹14400. Its value falls by 25% every year. What will it be worth after 3 years (in ₹)?
  28. 28.A scooter is worth ₹22400. Its value falls by 25% every year. What will it be worth after 2 years (in ₹)?
  29. 29.What amount will ₹54800 grow to in 2 years at 5% per year compound interest (in ₹)?
  30. 30.What amount will ₹50000 grow to in 2 years at 12% per year compound interest (in ₹)?
  31. 31.What is the difference between the compound interest and the simple interest on ₹52500 at 4% per year for 2 years (in ₹)?
  32. 32.What amount will ₹48000 grow to in 3 years at 5% per year compound interest (in ₹)?
  33. 33.What is the difference between the compound interest and the simple interest on ₹53900 at 20% per year for 2 years (in ₹)?
  34. 34.A town has 60000 people. The population grows by 4% every year. What will the population be after 1 year?
  35. 35.What amount will ₹22300 grow to in 1 year at 25% per year compound interest (in ₹)?
  36. 36.What amount will ₹16000 grow to in 3 years at 15% per year compound interest (in ₹)?
  37. 37.What is the difference between the compound interest and the simple interest on ₹46400 at 25% per year for 2 years (in ₹)?
  38. 38.Find the compound interest on ₹6500 at 8% per year for 1 year, compounded every year (in ₹).
  39. 39.What amount will ₹39600 grow to in 1 year at 12% per year compound interest (in ₹)?
  40. 40.Find the compound interest on ₹16000 at 5% per year for 3 years, compounded every year (in ₹).

Answer key

  1. 87
  2. 1242
  3. 88
  4. 7625
  5. 3480
  6. 11448
  7. 14476
  8. 18522
  9. 120
  10. 5586
  11. 1175
  12. 19968
  13. 5390
  14. 1940
  15. 31250
  16. 5808
  17. 46305
  18. 208
  19. 37060
  20. 112
  21. 39050
  22. 49450
  23. 80
  24. 17100
  25. 116
  26. 48013
  27. 6075
  28. 12600
  29. 60417
  30. 62720
  31. 84
  32. 55566
  33. 2156
  34. 62400
  35. 27875
  36. 24334
  37. 2900
  38. 520
  39. 44352
  40. 2522

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