Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 670 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.A town has 43000 people. The population grows by 10% every year. What will the population be after 3 years?
2. 2.Find the compound interest on ₹59400 at 15% per year for 1 year, compounded every year (in ₹).
3. 3.Find the compound interest on ₹7900 at 20% per year for 2 years, compounded every year (in ₹).
4. 4.What is the difference between the compound interest and the simple interest on ₹7500 at 8% per year for 2 years (in ₹)?
5. 5.A scooter is worth ₹11700. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
6. 6.What is the difference between the compound interest and the simple interest on ₹36300 at 10% per year for 2 years (in ₹)?
7. 7.What amount will ₹50000 grow to in 2 years at 12% per year compound interest (in ₹)?
8. 8.What is the difference between the compound interest and the simple interest on ₹57800 at 20% per year for 2 years (in ₹)?
9. 9.What is the difference between the compound interest and the simple interest on ₹38200 at 10% per year for 2 years (in ₹)?
10. 10.Find the compound interest on ₹56900 at 10% per year for 2 years, compounded every year (in ₹).
11. 11.What is the difference between the compound interest and the simple interest on ₹44400 at 25% per year for 2 years (in ₹)?
12. 12.What is the difference between the compound interest and the simple interest on ₹52800 at 25% per year for 2 years (in ₹)?
13. 13.What amount will ₹16000 grow to in 3 years at 5% per year compound interest (in ₹)?
14. 14.What amount will ₹9000 grow to in 2 years at 20% per year compound interest (in ₹)?
15. 15.What is the difference between the compound interest and the simple interest on ₹3200 at 5% per year for 2 years (in ₹)?
16. 16.Find the compound interest on ₹30100 at 25% per year for 1 year, compounded every year (in ₹).
17. 17.A town has 32000 people. The population grows by 15% every year. What will the population be after 3 years?
18. 18.Find the compound interest on ₹50000 at 8% per year for 2 years, compounded every year (in ₹).
19. 19.A scooter is worth ₹32000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
20. 20.What amount will ₹33600 grow to in 1 year at 4% per year compound interest (in ₹)?
21. 21.What amount will ₹52200 grow to in 1 year at 10% per year compound interest (in ₹)?
22. 22.A town has 17500 people. The population grows by 4% every year. What will the population be after 1 year?
23. 23.Find the compound interest on ₹16500 at 20% per year for 3 years, compounded every year (in ₹).
24. 24.What amount will ₹41400 grow to in 1 year at 8% per year compound interest (in ₹)?
25. 25.Find the compound interest on ₹8000 at 25% per year for 3 years, compounded every year (in ₹).
26. 26.What amount will ₹40000 grow to in 3 years at 25% per year compound interest (in ₹)?
27. 27.A town has 34400 people. The population grows by 10% every year. What will the population be after 1 year?
28. 28.What is the difference between the compound interest and the simple interest on ₹29300 at 20% per year for 2 years (in ₹)?
29. 29.Find the compound interest on ₹26800 at 25% per year for 2 years, compounded every year (in ₹).
30. 30.A scooter is worth ₹43400. Its value falls by 15% every year. What will it be worth after 1 year (in ₹)?
31. 31.A town has 8400 people. The population grows by 20% every year. What will the population be after 1 year?
32. 32.What amount will ₹40000 grow to in 3 years at 15% per year compound interest (in ₹)?
33. 33.Find the compound interest on ₹40200 at 15% per year for 1 year, compounded every year (in ₹).
34. 34.What is the difference between the compound interest and the simple interest on ₹16800 at 5% per year for 2 years (in ₹)?
35. 35.A town has 40400 people. The population grows by 8% every year. What will the population be after 1 year?
36. 36.A town has 16000 people. The population grows by 10% every year. What will the population be after 3 years?
37. 37.Find the compound interest on ₹8000 at 5% per year for 3 years, compounded every year (in ₹).
38. 38.What is the difference between the compound interest and the simple interest on ₹27500 at 8% per year for 2 years (in ₹)?
39. 39.What amount will ₹13500 grow to in 3 years at 20% per year compound interest (in ₹)?
40. 40.Find the compound interest on ₹47400 at 10% per year for 1 year, compounded every year (in ₹).

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