Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 678 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.A scooter is worth ₹3900. Its value falls by 4% every year. What will it be worth after 1 year (in ₹)?
2. 2.Find the compound interest on ₹2000 at 8% per year for 1 year, compounded every year (in ₹).
3. 3.A town has 54800 people. The population grows by 5% every year. What will the population be after 1 year?
4. 4.Find the compound interest on ₹34800 at 15% per year for 1 year, compounded every year (in ₹).
5. 5.What amount will ₹46400 grow to in 3 years at 25% per year compound interest (in ₹)?
6. 6.What is the difference between the compound interest and the simple interest on ₹51800 at 20% per year for 2 years (in ₹)?
7. 7.Find the compound interest on ₹43400 at 10% per year for 1 year, compounded every year (in ₹).
8. 8.What is the difference between the compound interest and the simple interest on ₹18800 at 5% per year for 2 years (in ₹)?
9. 9.What amount will ₹25200 grow to in 1 year at 12% per year compound interest (in ₹)?
10. 10.Find the compound interest on ₹28500 at 20% per year for 3 years, compounded every year (in ₹).
11. 11.What is the difference between the compound interest and the simple interest on ₹25600 at 25% per year for 2 years (in ₹)?
12. 12.Find the compound interest on ₹33900 at 12% per year for 1 year, compounded every year (in ₹).
13. 13.What is the difference between the compound interest and the simple interest on ₹46000 at 5% per year for 2 years (in ₹)?
14. 14.What amount will ₹57500 grow to in 2 years at 20% per year compound interest (in ₹)?
15. 15.A town has 13900 people. The population grows by 10% every year. What will the population be after 1 year?
16. 16.What amount will ₹19000 grow to in 2 years at 10% per year compound interest (in ₹)?
17. 17.A town has 10200 people. The population grows by 25% every year. What will the population be after 1 year?
18. 18.What amount will ₹50100 grow to in 1 year at 5% per year compound interest (in ₹)?
19. 19.What amount will ₹30000 grow to in 1 year at 10% per year compound interest (in ₹)?
20. 20.What amount will ₹17900 grow to in 1 year at 15% per year compound interest (in ₹)?
21. 21.A town has 7100 people. The population grows by 10% every year. What will the population be after 1 year?
22. 22.A scooter is worth ₹54400. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
23. 23.A town has 16000 people. The population grows by 5% every year. What will the population be after 3 years?
24. 24.What is the difference between the compound interest and the simple interest on ₹48300 at 10% per year for 2 years (in ₹)?
25. 25.What amount will ₹46300 grow to in 2 years at 10% per year compound interest (in ₹)?
26. 26.Find the compound interest on ₹30200 at 25% per year for 1 year, compounded every year (in ₹).
27. 27.What amount will ₹45000 grow to in 2 years at 4% per year compound interest (in ₹)?
28. 28.What is the difference between the compound interest and the simple interest on ₹40000 at 12% per year for 2 years (in ₹)?
29. 29.A scooter is worth ₹55800. Its value falls by 10% every year. What will it be worth after 2 years (in ₹)?
30. 30.What is the difference between the compound interest and the simple interest on ₹16200 at 10% per year for 2 years (in ₹)?
31. 31.What amount will ₹37600 grow to in 2 years at 15% per year compound interest (in ₹)?
32. 32.Find the compound interest on ₹48300 at 10% per year for 2 years, compounded every year (in ₹).
33. 33.A town has 46100 people. The population grows by 10% every year. What will the population be after 2 years?
34. 34.What amount will ₹40000 grow to in 3 years at 5% per year compound interest (in ₹)?
35. 35.Find the compound interest on ₹16000 at 5% per year for 3 years, compounded every year (in ₹).
36. 36.Find the compound interest on ₹27500 at 8% per year for 2 years, compounded every year (in ₹).
37. 37.Find the compound interest on ₹57200 at 5% per year for 2 years, compounded every year (in ₹).
38. 38.What amount will ₹48000 grow to in 3 years at 5% per year compound interest (in ₹)?
39. 39.What is the difference between the compound interest and the simple interest on ₹9200 at 25% per year for 2 years (in ₹)?
40. 40.Find the compound interest on ₹37500 at 4% per year for 2 years, compounded every year (in ₹).

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