Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 681 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.Find the compound interest on ₹5000 at 10% per year for 3 years, compounded every year (in ₹).
2. 2.Find the compound interest on ₹11000 at 20% per year for 3 years, compounded every year (in ₹).
3. 3.Find the compound interest on ₹10800 at 15% per year for 1 year, compounded every year (in ₹).
4. 4.A town has 30800 people. The population grows by 5% every year. What will the population be after 2 years?
5. 5.A town has 8800 people. The population grows by 5% every year. What will the population be after 2 years?
6. 6.What amount will ₹59200 grow to in 2 years at 25% per year compound interest (in ₹)?
7. 7.Find the compound interest on ₹46800 at 15% per year for 2 years, compounded every year (in ₹).
8. 8.A town has 7500 people. The population grows by 20% every year. What will the population be after 3 years?
9. 9.Find the compound interest on ₹25000 at 12% per year for 2 years, compounded every year (in ₹).
10. 10.Find the compound interest on ₹51700 at 10% per year for 2 years, compounded every year (in ₹).
11. 11.A scooter is worth ₹21500. Its value falls by 20% every year. What will it be worth after 3 years (in ₹)?
12. 12.What amount will ₹46700 grow to in 1 year at 8% per year compound interest (in ₹)?
13. 13.What amount will ₹9400 grow to in 1 year at 10% per year compound interest (in ₹)?
14. 14.Find the compound interest on ₹37500 at 4% per year for 2 years, compounded every year (in ₹).
15. 15.What amount will ₹7200 grow to in 1 year at 8% per year compound interest (in ₹)?
16. 16.What is the difference between the compound interest and the simple interest on ₹47500 at 20% per year for 2 years (in ₹)?
17. 17.What is the difference between the compound interest and the simple interest on ₹10600 at 10% per year for 2 years (in ₹)?
18. 18.Find the compound interest on ₹12500 at 20% per year for 1 year, compounded every year (in ₹).
19. 19.Find the compound interest on ₹34400 at 25% per year for 2 years, compounded every year (in ₹).
20. 20.A scooter is worth ₹57500. Its value falls by 12% every year. What will it be worth after 2 years (in ₹)?
21. 21.What amount will ₹16000 grow to in 3 years at 5% per year compound interest (in ₹)?
22. 22.Find the compound interest on ₹16000 at 15% per year for 3 years, compounded every year (in ₹).
23. 23.What is the difference between the compound interest and the simple interest on ₹15000 at 12% per year for 2 years (in ₹)?
24. 24.Find the compound interest on ₹27400 at 10% per year for 1 year, compounded every year (in ₹).
25. 25.What is the difference between the compound interest and the simple interest on ₹2500 at 12% per year for 2 years (in ₹)?
26. 26.What amount will ₹33100 grow to in 1 year at 5% per year compound interest (in ₹)?
27. 27.A scooter is worth ₹60000. Its value falls by 10% every year. What will it be worth after 3 years (in ₹)?
28. 28.A town has 19000 people. The population grows by 25% every year. What will the population be after 1 year?
29. 29.A scooter is worth ₹43800. Its value falls by 12% every year. What will it be worth after 1 year (in ₹)?
30. 30.What is the difference between the compound interest and the simple interest on ₹45200 at 10% per year for 2 years (in ₹)?
31. 31.Find the compound interest on ₹17200 at 5% per year for 2 years, compounded every year (in ₹).
32. 32.What is the difference between the compound interest and the simple interest on ₹33200 at 5% per year for 2 years (in ₹)?
33. 33.Find the compound interest on ₹6500 at 20% per year for 3 years, compounded every year (in ₹).
34. 34.A town has 37500 people. The population grows by 8% every year. What will the population be after 2 years?
35. 35.Find the compound interest on ₹43500 at 20% per year for 1 year, compounded every year (in ₹).
36. 36.What is the difference between the compound interest and the simple interest on ₹40000 at 8% per year for 2 years (in ₹)?
37. 37.Find the compound interest on ₹9600 at 15% per year for 2 years, compounded every year (in ₹).
38. 38.Find the compound interest on ₹17000 at 10% per year for 3 years, compounded every year (in ₹).
39. 39.Find the compound interest on ₹52800 at 25% per year for 3 years, compounded every year (in ₹).
40. 40.What amount will ₹14000 grow to in 2 years at 5% per year compound interest (in ₹)?

Free maths worksheets lessons, practice and worksheets at talentjr.in/maths-worksheets