Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 682 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.What amount will ₹59500 grow to in 3 years at 20% per year compound interest (in ₹)?
2. 2.What is the difference between the compound interest and the simple interest on ₹27000 at 10% per year for 2 years (in ₹)?
3. 3.What is the difference between the compound interest and the simple interest on ₹45600 at 20% per year for 2 years (in ₹)?
4. 4.Find the compound interest on ₹7500 at 4% per year for 2 years, compounded every year (in ₹).
5. 5.A town has 1600 people. The population grows by 25% every year. What will the population be after 3 years?
6. 6.What amount will ₹55000 grow to in 2 years at 12% per year compound interest (in ₹)?
7. 7.What amount will ₹4800 grow to in 2 years at 5% per year compound interest (in ₹)?
8. 8.What amount will ₹56000 grow to in 3 years at 15% per year compound interest (in ₹)?
9. 9.What is the difference between the compound interest and the simple interest on ₹4800 at 25% per year for 2 years (in ₹)?
10. 10.What amount will ₹36800 grow to in 3 years at 25% per year compound interest (in ₹)?
11. 11.A scooter is worth ₹20000. Its value falls by 4% every year. What will it be worth after 2 years (in ₹)?
12. 12.Find the compound interest on ₹47600 at 25% per year for 2 years, compounded every year (in ₹).
13. 13.A scooter is worth ₹60000. Its value falls by 12% every year. What will it be worth after 2 years (in ₹)?
14. 14.A town has 32000 people. The population grows by 15% every year. What will the population be after 3 years?
15. 15.What is the difference between the compound interest and the simple interest on ₹40000 at 8% per year for 2 years (in ₹)?
16. 16.A scooter is worth ₹40000. Its value falls by 15% every year. What will it be worth after 3 years (in ₹)?
17. 17.What is the difference between the compound interest and the simple interest on ₹2500 at 8% per year for 2 years (in ₹)?
18. 18.A town has 25000 people. The population grows by 8% every year. What will the population be after 2 years?
19. 19.A scooter is worth ₹32000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
20. 20.What amount will ₹53900 grow to in 1 year at 4% per year compound interest (in ₹)?
21. 21.What is the difference between the compound interest and the simple interest on ₹12400 at 5% per year for 2 years (in ₹)?
22. 22.Find the compound interest on ₹45000 at 10% per year for 3 years, compounded every year (in ₹).
23. 23.Find the compound interest on ₹16700 at 25% per year for 1 year, compounded every year (in ₹).
24. 24.What amount will ₹18800 grow to in 2 years at 10% per year compound interest (in ₹)?
25. 25.Find the compound interest on ₹16700 at 4% per year for 1 year, compounded every year (in ₹).
26. 26.Find the compound interest on ₹52800 at 15% per year for 2 years, compounded every year (in ₹).
27. 27.Find the compound interest on ₹40400 at 15% per year for 1 year, compounded every year (in ₹).
28. 28.What amount will ₹8000 grow to in 3 years at 10% per year compound interest (in ₹)?
29. 29.A town has 8600 people. The population grows by 20% every year. What will the population be after 2 years?
30. 30.A town has 33800 people. The population grows by 5% every year. What will the population be after 1 year?
31. 31.What amount will ₹40000 grow to in 1 year at 4% per year compound interest (in ₹)?
32. 32.What amount will ₹44000 grow to in 3 years at 10% per year compound interest (in ₹)?
33. 33.Find the compound interest on ₹10000 at 4% per year for 2 years, compounded every year (in ₹).
34. 34.What is the difference between the compound interest and the simple interest on ₹41600 at 20% per year for 2 years (in ₹)?
35. 35.Find the compound interest on ₹35800 at 10% per year for 2 years, compounded every year (in ₹).
36. 36.What amount will ₹14800 grow to in 2 years at 25% per year compound interest (in ₹)?
37. 37.Find the compound interest on ₹32000 at 15% per year for 3 years, compounded every year (in ₹).
38. 38.A scooter is worth ₹9100. Its value falls by 10% every year. What will it be worth after 2 years (in ₹)?
39. 39.Find the compound interest on ₹17400 at 5% per year for 1 year, compounded every year (in ₹).
40. 40.What is the difference between the compound interest and the simple interest on ₹52500 at 8% per year for 2 years (in ₹)?

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