Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 683 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.Find the compound interest on ₹38400 at 25% per year for 3 years, compounded every year (in ₹).
2. 2.Find the compound interest on ₹2100 at 15% per year for 1 year, compounded every year (in ₹).
3. 3.What amount will ₹32400 grow to in 1 year at 25% per year compound interest (in ₹)?
4. 4.A scooter is worth ₹34400. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
5. 5.Find the compound interest on ₹18400 at 5% per year for 2 years, compounded every year (in ₹).
6. 6.A scooter is worth ₹51600. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
7. 7.What is the difference between the compound interest and the simple interest on ₹11300 at 20% per year for 2 years (in ₹)?
8. 8.A scooter is worth ₹28000. Its value falls by 10% every year. What will it be worth after 3 years (in ₹)?
9. 9.A town has 41100 people. The population grows by 4% every year. What will the population be after 1 year?
10. 10.Find the compound interest on ₹50600 at 25% per year for 1 year, compounded every year (in ₹).
11. 11.What amount will ₹6000 grow to in 3 years at 10% per year compound interest (in ₹)?
12. 12.Find the compound interest on ₹14800 at 8% per year for 1 year, compounded every year (in ₹).
13. 13.Find the compound interest on ₹42500 at 8% per year for 2 years, compounded every year (in ₹).
14. 14.Find the compound interest on ₹52400 at 5% per year for 2 years, compounded every year (in ₹).
15. 15.Find the compound interest on ₹33200 at 10% per year for 1 year, compounded every year (in ₹).
16. 16.Find the compound interest on ₹40000 at 10% per year for 2 years, compounded every year (in ₹).
17. 17.What is the difference between the compound interest and the simple interest on ₹52000 at 10% per year for 2 years (in ₹)?
18. 18.Find the compound interest on ₹49000 at 10% per year for 3 years, compounded every year (in ₹).
19. 19.Find the compound interest on ₹30000 at 4% per year for 2 years, compounded every year (in ₹).
20. 20.What is the difference between the compound interest and the simple interest on ₹6000 at 20% per year for 2 years (in ₹)?
21. 21.What is the difference between the compound interest and the simple interest on ₹16400 at 25% per year for 2 years (in ₹)?
22. 22.A town has 59500 people. The population grows by 25% every year. What will the population be after 1 year?
23. 23.What amount will ₹46700 grow to in 2 years at 10% per year compound interest (in ₹)?
24. 24.Find the compound interest on ₹31300 at 10% per year for 2 years, compounded every year (in ₹).
25. 25.A scooter is worth ₹23600. Its value falls by 10% every year. What will it be worth after 2 years (in ₹)?
26. 26.What amount will ₹53500 grow to in 3 years at 20% per year compound interest (in ₹)?
27. 27.A town has 1600 people. The population grows by 25% every year. What will the population be after 3 years?
28. 28.Find the compound interest on ₹53200 at 10% per year for 2 years, compounded every year (in ₹).
29. 29.A scooter is worth ₹8800. Its value falls by 25% every year. What will it be worth after 2 years (in ₹)?
30. 30.What is the difference between the compound interest and the simple interest on ₹40400 at 5% per year for 2 years (in ₹)?
31. 31.What amount will ₹2500 grow to in 2 years at 4% per year compound interest (in ₹)?
32. 32.Find the compound interest on ₹19500 at 20% per year for 1 year, compounded every year (in ₹).
33. 33.What is the difference between the compound interest and the simple interest on ₹5000 at 12% per year for 2 years (in ₹)?
34. 34.What amount will ₹44700 grow to in 1 year at 12% per year compound interest (in ₹)?
35. 35.What amount will ₹40000 grow to in 3 years at 5% per year compound interest (in ₹)?
36. 36.What amount will ₹22500 grow to in 2 years at 4% per year compound interest (in ₹)?
37. 37.What is the difference between the compound interest and the simple interest on ₹21200 at 25% per year for 2 years (in ₹)?
38. 38.What amount will ₹42500 grow to in 2 years at 8% per year compound interest (in ₹)?
39. 39.A town has 57500 people. The population grows by 20% every year. What will the population be after 1 year?
40. 40.Find the compound interest on ₹59200 at 5% per year for 2 years, compounded every year (in ₹).

Free maths worksheets lessons, practice and worksheets at talentjr.in/maths-worksheets