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Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 686 · 40 sums
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The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

NameDateTime takenScore ___ / 40
  1. 1.What is the difference between the compound interest and the simple interest on ₹5200 at 15% per year for 2 years (in ₹)?
  2. 2.Find the compound interest on ₹58000 at 25% per year for 2 years, compounded every year (in ₹).
  3. 3.Find the compound interest on ₹19800 at 15% per year for 1 year, compounded every year (in ₹).
  4. 4.What amount will ₹56400 grow to in 1 year at 12% per year compound interest (in ₹)?
  5. 5.What amount will ₹57500 grow to in 2 years at 4% per year compound interest (in ₹)?
  6. 6.What is the difference between the compound interest and the simple interest on ₹23600 at 10% per year for 2 years (in ₹)?
  7. 7.What is the difference between the compound interest and the simple interest on ₹50500 at 20% per year for 2 years (in ₹)?
  8. 8.Find the compound interest on ₹58200 at 20% per year for 1 year, compounded every year (in ₹).
  9. 9.What is the difference between the compound interest and the simple interest on ₹24600 at 20% per year for 2 years (in ₹)?
  10. 10.What is the difference between the compound interest and the simple interest on ₹32500 at 12% per year for 2 years (in ₹)?
  11. 11.What is the difference between the compound interest and the simple interest on ₹10000 at 12% per year for 2 years (in ₹)?
  12. 12.A scooter is worth ₹16300. Its value falls by 25% every year. What will it be worth after 1 year (in ₹)?
  13. 13.A town has 4500 people. The population grows by 10% every year. What will the population be after 1 year?
  14. 14.Find the compound interest on ₹2500 at 12% per year for 2 years, compounded every year (in ₹).
  15. 15.What amount will ₹14000 grow to in 2 years at 15% per year compound interest (in ₹)?
  16. 16.A town has 48000 people. The population grows by 5% every year. What will the population be after 3 years?
  17. 17.What is the difference between the compound interest and the simple interest on ₹7500 at 4% per year for 2 years (in ₹)?
  18. 18.What is the difference between the compound interest and the simple interest on ₹40000 at 8% per year for 2 years (in ₹)?
  19. 19.Find the compound interest on ₹22400 at 25% per year for 3 years, compounded every year (in ₹).
  20. 20.A town has 56500 people. The population grows by 8% every year. What will the population be after 1 year?
  21. 21.What amount will ₹59900 grow to in 1 year at 20% per year compound interest (in ₹)?
  22. 22.What amount will ₹19300 grow to in 1 year at 12% per year compound interest (in ₹)?
  23. 23.What is the difference between the compound interest and the simple interest on ₹5000 at 8% per year for 2 years (in ₹)?
  24. 24.Find the compound interest on ₹36100 at 20% per year for 1 year, compounded every year (in ₹).
  25. 25.A scooter is worth ₹29600. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
  26. 26.A town has 17500 people. The population grows by 4% every year. What will the population be after 1 year?
  27. 27.A scooter is worth ₹42500. Its value falls by 4% every year. What will it be worth after 2 years (in ₹)?
  28. 28.A town has 36200 people. The population grows by 15% every year. What will the population be after 1 year?
  29. 29.What is the difference between the compound interest and the simple interest on ₹20000 at 4% per year for 2 years (in ₹)?
  30. 30.What amount will ₹8300 grow to in 2 years at 10% per year compound interest (in ₹)?
  31. 31.What amount will ₹18400 grow to in 2 years at 5% per year compound interest (in ₹)?
  32. 32.A town has 8000 people. The population grows by 5% every year. What will the population be after 2 years?
  33. 33.What is the difference between the compound interest and the simple interest on ₹21600 at 10% per year for 2 years (in ₹)?
  34. 34.A town has 50900 people. The population grows by 25% every year. What will the population be after 1 year?
  35. 35.What amount will ₹33300 grow to in 1 year at 25% per year compound interest (in ₹)?
  36. 36.What amount will ₹41000 grow to in 3 years at 10% per year compound interest (in ₹)?
  37. 37.A town has 6000 people. The population grows by 10% every year. What will the population be after 3 years?
  38. 38.A scooter is worth ₹23100. Its value falls by 8% every year. What will it be worth after 1 year (in ₹)?
  39. 39.What amount will ₹44800 grow to in 3 years at 25% per year compound interest (in ₹)?
  40. 40.What is the difference between the compound interest and the simple interest on ₹9200 at 5% per year for 2 years (in ₹)?

Answer key

  1. 117
  2. 32625
  3. 2970
  4. 63168
  5. 62192
  6. 236
  7. 2020
  8. 11640
  9. 984
  10. 468
  11. 144
  12. 12225
  13. 4950
  14. 636
  15. 18515
  16. 55566
  17. 12
  18. 256
  19. 21350
  20. 61020
  21. 71880
  22. 21616
  23. 32
  24. 7220
  25. 26714
  26. 18200
  27. 39168
  28. 41630
  29. 32
  30. 10043
  31. 20286
  32. 8820
  33. 216
  34. 63625
  35. 41625
  36. 54571
  37. 7986
  38. 21252
  39. 87500
  40. 23

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