Class 8 Maths Worksheet: Compound Interest
The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.
NameDateTime takenScore ___ / 40
- 1.A town has 32000 people. The population grows by 15% every year. What will the population be after 3 years?
- 2.A town has 31700 people. The population grows by 8% every year. What will the population be after 1 year?
- 3.A scooter is worth ₹30000. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
- 4.Find the compound interest on ₹54000 at 20% per year for 3 years, compounded every year (in ₹).
- 5.What amount will ₹7000 grow to in 2 years at 20% per year compound interest (in ₹)?
- 6.Find the compound interest on ₹2500 at 4% per year for 2 years, compounded every year (in ₹).
- 7.What is the difference between the compound interest and the simple interest on ₹10400 at 15% per year for 2 years (in ₹)?
- 8.Find the compound interest on ₹33900 at 10% per year for 2 years, compounded every year (in ₹).
- 9.What amount will ₹16500 grow to in 1 year at 4% per year compound interest (in ₹)?
- 10.What amount will ₹32500 grow to in 2 years at 8% per year compound interest (in ₹)?
- 11.Find the compound interest on ₹37500 at 12% per year for 2 years, compounded every year (in ₹).
- 12.What amount will ₹12100 grow to in 1 year at 25% per year compound interest (in ₹)?
- 13.A town has 5600 people. The population grows by 8% every year. What will the population be after 1 year?
- 14.Find the compound interest on ₹55000 at 12% per year for 2 years, compounded every year (in ₹).
- 15.Find the compound interest on ₹15100 at 25% per year for 1 year, compounded every year (in ₹).
- 16.What is the difference between the compound interest and the simple interest on ₹22800 at 5% per year for 2 years (in ₹)?
- 17.A town has 16000 people. The population grows by 20% every year. What will the population be after 3 years?
- 18.A town has 11500 people. The population grows by 10% every year. What will the population be after 2 years?
- 19.Find the compound interest on ₹39800 at 20% per year for 2 years, compounded every year (in ₹).
- 20.What is the difference between the compound interest and the simple interest on ₹47300 at 20% per year for 2 years (in ₹)?
- 21.Find the compound interest on ₹2700 at 20% per year for 2 years, compounded every year (in ₹).
- 22.What is the difference between the compound interest and the simple interest on ₹9600 at 5% per year for 2 years (in ₹)?
- 23.What is the difference between the compound interest and the simple interest on ₹52000 at 5% per year for 2 years (in ₹)?
- 24.What is the difference between the compound interest and the simple interest on ₹54600 at 10% per year for 2 years (in ₹)?
- 25.What is the difference between the compound interest and the simple interest on ₹25000 at 12% per year for 2 years (in ₹)?
- 26.Find the compound interest on ₹8000 at 5% per year for 3 years, compounded every year (in ₹).
- 27.Find the compound interest on ₹32800 at 25% per year for 2 years, compounded every year (in ₹).
- 28.What is the difference between the compound interest and the simple interest on ₹20000 at 10% per year for 2 years (in ₹)?
- 29.Find the compound interest on ₹48000 at 5% per year for 3 years, compounded every year (in ₹).
- 30.What is the difference between the compound interest and the simple interest on ₹18800 at 5% per year for 2 years (in ₹)?
- 31.Find the compound interest on ₹27400 at 5% per year for 1 year, compounded every year (in ₹).
- 32.What amount will ₹19500 grow to in 3 years at 20% per year compound interest (in ₹)?
- 33.What is the difference between the compound interest and the simple interest on ₹47500 at 8% per year for 2 years (in ₹)?
- 34.What amount will ₹24000 grow to in 3 years at 5% per year compound interest (in ₹)?
- 35.What is the difference between the compound interest and the simple interest on ₹22200 at 10% per year for 2 years (in ₹)?
- 36.Find the compound interest on ₹23600 at 5% per year for 2 years, compounded every year (in ₹).
- 37.A town has 58000 people. The population grows by 20% every year. What will the population be after 2 years?
- 38.What amount will ₹50000 grow to in 2 years at 8% per year compound interest (in ₹)?
- 39.What amount will ₹49000 grow to in 2 years at 20% per year compound interest (in ₹)?
- 40.A town has 35200 people. The population grows by 25% every year. What will the population be after 3 years?
Answer key
- 48668
- 34236
- 27000
- 39312
- 10080
- 204
- 234
- 7119
- 17160
- 37908
- 9540
- 15125
- 6048
- 13992
- 3775
- 57
- 27648
- 13915
- 17512
- 1892
- 1188
- 24
- 130
- 546
- 360
- 1261
- 18450
- 200
- 7566
- 47
- 1370
- 33696
- 304
- 27783
- 222
- 2419
- 83520
- 58320
- 70560
- 68750
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