Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 688 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.What is the difference between the compound interest and the simple interest on ₹40000 at 8% per year for 2 years (in ₹)?
2. 2.Find the compound interest on ₹13600 at 12% per year for 1 year, compounded every year (in ₹).
3. 3.A scooter is worth ₹32900. Its value falls by 25% every year. What will it be worth after 1 year (in ₹)?
4. 4.What is the difference between the compound interest and the simple interest on ₹50200 at 10% per year for 2 years (in ₹)?
5. 5.What is the difference between the compound interest and the simple interest on ₹32700 at 20% per year for 2 years (in ₹)?
6. 6.Find the compound interest on ₹52500 at 4% per year for 2 years, compounded every year (in ₹).
7. 7.What amount will ₹57000 grow to in 3 years at 10% per year compound interest (in ₹)?
8. 8.What is the difference between the compound interest and the simple interest on ₹26400 at 15% per year for 2 years (in ₹)?
9. 9.What is the difference between the compound interest and the simple interest on ₹26300 at 10% per year for 2 years (in ₹)?
10. 10.What amount will ₹12500 grow to in 2 years at 12% per year compound interest (in ₹)?
11. 11.What amount will ₹47500 grow to in 1 year at 12% per year compound interest (in ₹)?
12. 12.What is the difference between the compound interest and the simple interest on ₹15200 at 5% per year for 2 years (in ₹)?
13. 13.What amount will ₹34500 grow to in 3 years at 20% per year compound interest (in ₹)?
14. 14.A town has 2500 people. The population grows by 12% every year. What will the population be after 2 years?
15. 15.What is the difference between the compound interest and the simple interest on ₹9200 at 25% per year for 2 years (in ₹)?
16. 16.A town has 3200 people. The population grows by 25% every year. What will the population be after 3 years?
17. 17.What amount will ₹2800 grow to in 2 years at 25% per year compound interest (in ₹)?
18. 18.What amount will ₹57500 grow to in 2 years at 4% per year compound interest (in ₹)?
19. 19.What is the difference between the compound interest and the simple interest on ₹5000 at 8% per year for 2 years (in ₹)?
20. 20.Find the compound interest on ₹19500 at 20% per year for 3 years, compounded every year (in ₹).
21. 21.Find the compound interest on ₹30000 at 10% per year for 3 years, compounded every year (in ₹).
22. 22.What is the difference between the compound interest and the simple interest on ₹40400 at 25% per year for 2 years (in ₹)?
23. 23.What is the difference between the compound interest and the simple interest on ₹42500 at 8% per year for 2 years (in ₹)?
24. 24.A scooter is worth ₹8000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
25. 25.What amount will ₹18900 grow to in 2 years at 20% per year compound interest (in ₹)?
26. 26.What amount will ₹5200 grow to in 2 years at 5% per year compound interest (in ₹)?
27. 27.Find the compound interest on ₹19500 at 25% per year for 1 year, compounded every year (in ₹).
28. 28.What amount will ₹15200 grow to in 1 year at 10% per year compound interest (in ₹)?
29. 29.What is the difference between the compound interest and the simple interest on ₹12800 at 10% per year for 2 years (in ₹)?
30. 30.Find the compound interest on ₹2800 at 10% per year for 2 years, compounded every year (in ₹).
31. 31.What is the difference between the compound interest and the simple interest on ₹31200 at 25% per year for 2 years (in ₹)?
32. 32.Find the compound interest on ₹56900 at 10% per year for 1 year, compounded every year (in ₹).
33. 33.What is the difference between the compound interest and the simple interest on ₹21600 at 15% per year for 2 years (in ₹)?
34. 34.A town has 36800 people. The population grows by 25% every year. What will the population be after 3 years?
35. 35.Find the compound interest on ₹56700 at 10% per year for 1 year, compounded every year (in ₹).
36. 36.What is the difference between the compound interest and the simple interest on ₹12000 at 5% per year for 2 years (in ₹)?
37. 37.What amount will ₹42600 grow to in 1 year at 10% per year compound interest (in ₹)?
38. 38.What amount will ₹6200 grow to in 1 year at 5% per year compound interest (in ₹)?
39. 39.A town has 26900 people. The population grows by 4% every year. What will the population be after 1 year?
40. 40.What is the difference between the compound interest and the simple interest on ₹18300 at 20% per year for 2 years (in ₹)?

Free maths worksheets lessons, practice and worksheets at talentjr.in/maths-worksheets