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Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 689 · 40 sums
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The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

NameDateTime takenScore ___ / 40
  1. 1.Find the compound interest on ₹60000 at 8% per year for 2 years, compounded every year (in ₹).
  2. 2.What is the difference between the compound interest and the simple interest on ₹7200 at 15% per year for 2 years (in ₹)?
  3. 3.What is the difference between the compound interest and the simple interest on ₹27500 at 12% per year for 2 years (in ₹)?
  4. 4.What amount will ₹36000 grow to in 1 year at 5% per year compound interest (in ₹)?
  5. 5.What is the difference between the compound interest and the simple interest on ₹38400 at 20% per year for 2 years (in ₹)?
  6. 6.What amount will ₹9900 grow to in 1 year at 10% per year compound interest (in ₹)?
  7. 7.What is the difference between the compound interest and the simple interest on ₹31600 at 20% per year for 2 years (in ₹)?
  8. 8.Find the compound interest on ₹40000 at 8% per year for 2 years, compounded every year (in ₹).
  9. 9.Find the compound interest on ₹20000 at 5% per year for 2 years, compounded every year (in ₹).
  10. 10.What is the difference between the compound interest and the simple interest on ₹17500 at 4% per year for 2 years (in ₹)?
  11. 11.A scooter is worth ₹2500. Its value falls by 12% every year. What will it be worth after 2 years (in ₹)?
  12. 12.Find the compound interest on ₹6100 at 20% per year for 1 year, compounded every year (in ₹).
  13. 13.What is the difference between the compound interest and the simple interest on ₹43500 at 20% per year for 2 years (in ₹)?
  14. 14.Find the compound interest on ₹20000 at 8% per year for 2 years, compounded every year (in ₹).
  15. 15.What is the difference between the compound interest and the simple interest on ₹53900 at 10% per year for 2 years (in ₹)?
  16. 16.Find the compound interest on ₹32400 at 20% per year for 1 year, compounded every year (in ₹).
  17. 17.A town has 59500 people. The population grows by 5% every year. What will the population be after 1 year?
  18. 18.What is the difference between the compound interest and the simple interest on ₹20000 at 25% per year for 2 years (in ₹)?
  19. 19.A town has 27300 people. The population grows by 20% every year. What will the population be after 1 year?
  20. 20.What is the difference between the compound interest and the simple interest on ₹27500 at 4% per year for 2 years (in ₹)?
  21. 21.Find the compound interest on ₹49200 at 25% per year for 2 years, compounded every year (in ₹).
  22. 22.A scooter is worth ₹8000. Its value falls by 15% every year. What will it be worth after 3 years (in ₹)?
  23. 23.What is the difference between the compound interest and the simple interest on ₹2500 at 4% per year for 2 years (in ₹)?
  24. 24.A scooter is worth ₹22500. Its value falls by 8% every year. What will it be worth after 2 years (in ₹)?
  25. 25.What is the difference between the compound interest and the simple interest on ₹40000 at 12% per year for 2 years (in ₹)?
  26. 26.A town has 22500 people. The population grows by 8% every year. What will the population be after 1 year?
  27. 27.What amount will ₹39900 grow to in 1 year at 5% per year compound interest (in ₹)?
  28. 28.What amount will ₹43400 grow to in 1 year at 4% per year compound interest (in ₹)?
  29. 29.A town has 40300 people. The population grows by 20% every year. What will the population be after 1 year?
  30. 30.What is the difference between the compound interest and the simple interest on ₹44500 at 10% per year for 2 years (in ₹)?
  31. 31.Find the compound interest on ₹48400 at 10% per year for 2 years, compounded every year (in ₹).
  32. 32.Find the compound interest on ₹24000 at 20% per year for 2 years, compounded every year (in ₹).
  33. 33.A town has 24000 people. The population grows by 25% every year. What will the population be after 3 years?
  34. 34.What amount will ₹32000 grow to in 3 years at 20% per year compound interest (in ₹)?
  35. 35.What is the difference between the compound interest and the simple interest on ₹25000 at 8% per year for 2 years (in ₹)?
  36. 36.What amount will ₹37500 grow to in 2 years at 4% per year compound interest (in ₹)?
  37. 37.A scooter is worth ₹53700. Its value falls by 15% every year. What will it be worth after 1 year (in ₹)?
  38. 38.A scooter is worth ₹57500. Its value falls by 12% every year. What will it be worth after 2 years (in ₹)?
  39. 39.What amount will ₹27500 grow to in 3 years at 20% per year compound interest (in ₹)?
  40. 40.Find the compound interest on ₹21000 at 10% per year for 2 years, compounded every year (in ₹).

Answer key

  1. 9984
  2. 162
  3. 396
  4. 37800
  5. 1536
  6. 10890
  7. 1264
  8. 6656
  9. 2050
  10. 28
  11. 1936
  12. 1220
  13. 1740
  14. 3328
  15. 539
  16. 6480
  17. 62475
  18. 1250
  19. 32760
  20. 44
  21. 27675
  22. 4913
  23. 4
  24. 19044
  25. 576
  26. 24300
  27. 41895
  28. 45136
  29. 48360
  30. 445
  31. 10164
  32. 10560
  33. 46875
  34. 55296
  35. 160
  36. 40560
  37. 45645
  38. 44528
  39. 47520
  40. 4410

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