Class 8 Maths Worksheet: Compound Interest
The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.
NameDateTime takenScore ___ / 40
- 1.Find the compound interest on ₹60000 at 8% per year for 2 years, compounded every year (in ₹).
- 2.What is the difference between the compound interest and the simple interest on ₹7200 at 15% per year for 2 years (in ₹)?
- 3.What is the difference between the compound interest and the simple interest on ₹27500 at 12% per year for 2 years (in ₹)?
- 4.What amount will ₹36000 grow to in 1 year at 5% per year compound interest (in ₹)?
- 5.What is the difference between the compound interest and the simple interest on ₹38400 at 20% per year for 2 years (in ₹)?
- 6.What amount will ₹9900 grow to in 1 year at 10% per year compound interest (in ₹)?
- 7.What is the difference between the compound interest and the simple interest on ₹31600 at 20% per year for 2 years (in ₹)?
- 8.Find the compound interest on ₹40000 at 8% per year for 2 years, compounded every year (in ₹).
- 9.Find the compound interest on ₹20000 at 5% per year for 2 years, compounded every year (in ₹).
- 10.What is the difference between the compound interest and the simple interest on ₹17500 at 4% per year for 2 years (in ₹)?
- 11.A scooter is worth ₹2500. Its value falls by 12% every year. What will it be worth after 2 years (in ₹)?
- 12.Find the compound interest on ₹6100 at 20% per year for 1 year, compounded every year (in ₹).
- 13.What is the difference between the compound interest and the simple interest on ₹43500 at 20% per year for 2 years (in ₹)?
- 14.Find the compound interest on ₹20000 at 8% per year for 2 years, compounded every year (in ₹).
- 15.What is the difference between the compound interest and the simple interest on ₹53900 at 10% per year for 2 years (in ₹)?
- 16.Find the compound interest on ₹32400 at 20% per year for 1 year, compounded every year (in ₹).
- 17.A town has 59500 people. The population grows by 5% every year. What will the population be after 1 year?
- 18.What is the difference between the compound interest and the simple interest on ₹20000 at 25% per year for 2 years (in ₹)?
- 19.A town has 27300 people. The population grows by 20% every year. What will the population be after 1 year?
- 20.What is the difference between the compound interest and the simple interest on ₹27500 at 4% per year for 2 years (in ₹)?
- 21.Find the compound interest on ₹49200 at 25% per year for 2 years, compounded every year (in ₹).
- 22.A scooter is worth ₹8000. Its value falls by 15% every year. What will it be worth after 3 years (in ₹)?
- 23.What is the difference between the compound interest and the simple interest on ₹2500 at 4% per year for 2 years (in ₹)?
- 24.A scooter is worth ₹22500. Its value falls by 8% every year. What will it be worth after 2 years (in ₹)?
- 25.What is the difference between the compound interest and the simple interest on ₹40000 at 12% per year for 2 years (in ₹)?
- 26.A town has 22500 people. The population grows by 8% every year. What will the population be after 1 year?
- 27.What amount will ₹39900 grow to in 1 year at 5% per year compound interest (in ₹)?
- 28.What amount will ₹43400 grow to in 1 year at 4% per year compound interest (in ₹)?
- 29.A town has 40300 people. The population grows by 20% every year. What will the population be after 1 year?
- 30.What is the difference between the compound interest and the simple interest on ₹44500 at 10% per year for 2 years (in ₹)?
- 31.Find the compound interest on ₹48400 at 10% per year for 2 years, compounded every year (in ₹).
- 32.Find the compound interest on ₹24000 at 20% per year for 2 years, compounded every year (in ₹).
- 33.A town has 24000 people. The population grows by 25% every year. What will the population be after 3 years?
- 34.What amount will ₹32000 grow to in 3 years at 20% per year compound interest (in ₹)?
- 35.What is the difference between the compound interest and the simple interest on ₹25000 at 8% per year for 2 years (in ₹)?
- 36.What amount will ₹37500 grow to in 2 years at 4% per year compound interest (in ₹)?
- 37.A scooter is worth ₹53700. Its value falls by 15% every year. What will it be worth after 1 year (in ₹)?
- 38.A scooter is worth ₹57500. Its value falls by 12% every year. What will it be worth after 2 years (in ₹)?
- 39.What amount will ₹27500 grow to in 3 years at 20% per year compound interest (in ₹)?
- 40.Find the compound interest on ₹21000 at 10% per year for 2 years, compounded every year (in ₹).
Answer key
- 9984
- 162
- 396
- 37800
- 1536
- 10890
- 1264
- 6656
- 2050
- 28
- 1936
- 1220
- 1740
- 3328
- 539
- 6480
- 62475
- 1250
- 32760
- 44
- 27675
- 4913
- 4
- 19044
- 576
- 24300
- 41895
- 45136
- 48360
- 445
- 10164
- 10560
- 46875
- 55296
- 160
- 40560
- 45645
- 44528
- 47520
- 4410
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