Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 690 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.Find the compound interest on ₹34000 at 5% per year for 1 year, compounded every year (in ₹).
2. 2.A town has 37600 people. The population grows by 15% every year. What will the population be after 2 years?
3. 3.A town has 4000 people. The population grows by 4% every year. What will the population be after 1 year?
4. 4.Find the compound interest on ₹26300 at 20% per year for 2 years, compounded every year (in ₹).
5. 5.A town has 23000 people. The population grows by 10% every year. What will the population be after 3 years?
6. 6.Find the compound interest on ₹59500 at 25% per year for 1 year, compounded every year (in ₹).
7. 7.What amount will ₹33700 grow to in 1 year at 20% per year compound interest (in ₹)?
8. 8.What is the difference between the compound interest and the simple interest on ₹33600 at 10% per year for 2 years (in ₹)?
9. 9.Find the compound interest on ₹5200 at 5% per year for 2 years, compounded every year (in ₹).
10. 10.Find the compound interest on ₹7800 at 20% per year for 2 years, compounded every year (in ₹).
11. 11.A scooter is worth ₹24000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
12. 12.Find the compound interest on ₹51200 at 25% per year for 1 year, compounded every year (in ₹).
13. 13.Find the compound interest on ₹56000 at 15% per year for 3 years, compounded every year (in ₹).
14. 14.What is the difference between the compound interest and the simple interest on ₹7600 at 10% per year for 2 years (in ₹)?
15. 15.Find the compound interest on ₹40000 at 5% per year for 3 years, compounded every year (in ₹).
16. 16.What is the difference between the compound interest and the simple interest on ₹31200 at 5% per year for 2 years (in ₹)?
17. 17.What amount will ₹22300 grow to in 2 years at 10% per year compound interest (in ₹)?
18. 18.A town has 20000 people. The population grows by 8% every year. What will the population be after 2 years?
19. 19.What is the difference between the compound interest and the simple interest on ₹27500 at 20% per year for 2 years (in ₹)?
20. 20.A scooter is worth ₹39700. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
21. 21.What amount will ₹25000 grow to in 2 years at 8% per year compound interest (in ₹)?
22. 22.A scooter is worth ₹10900. Its value falls by 10% every year. What will it be worth after 2 years (in ₹)?
23. 23.What amount will ₹39500 grow to in 2 years at 20% per year compound interest (in ₹)?
24. 24.A scooter is worth ₹22100. Its value falls by 8% every year. What will it be worth after 1 year (in ₹)?
25. 25.A town has 40600 people. The population grows by 4% every year. What will the population be after 1 year?
26. 26.What is the difference between the compound interest and the simple interest on ₹52500 at 12% per year for 2 years (in ₹)?
27. 27.Find the compound interest on ₹6800 at 15% per year for 2 years, compounded every year (in ₹).
28. 28.Find the compound interest on ₹33600 at 25% per year for 3 years, compounded every year (in ₹).
29. 29.A scooter is worth ₹32600. Its value falls by 8% every year. What will it be worth after 1 year (in ₹)?
30. 30.Find the compound interest on ₹51400 at 4% per year for 1 year, compounded every year (in ₹).
31. 31.What amount will ₹37700 grow to in 2 years at 10% per year compound interest (in ₹)?
32. 32.What amount will ₹50600 grow to in 1 year at 10% per year compound interest (in ₹)?
33. 33.A town has 24000 people. The population grows by 25% every year. What will the population be after 3 years?
34. 34.What amount will ₹22500 grow to in 2 years at 8% per year compound interest (in ₹)?
35. 35.A town has 29200 people. The population grows by 5% every year. What will the population be after 2 years?
36. 36.Find the compound interest on ₹27500 at 4% per year for 2 years, compounded every year (in ₹).
37. 37.What is the difference between the compound interest and the simple interest on ₹60000 at 10% per year for 2 years (in ₹)?
38. 38.Find the compound interest on ₹12200 at 10% per year for 1 year, compounded every year (in ₹).
39. 39.A scooter is worth ₹29600. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
40. 40.Find the compound interest on ₹31200 at 15% per year for 1 year, compounded every year (in ₹).

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