Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 69 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.Find the compound interest on ₹6300 at 4% per year for 1 year, compounded every year (in ₹).
2. 2.A town has 32000 people. The population grows by 10% every year. What will the population be after 3 years?
3. 3.A town has 34800 people. The population grows by 15% every year. What will the population be after 2 years?
4. 4.A town has 3700 people. The population grows by 25% every year. What will the population be after 1 year?
5. 5.Find the compound interest on ₹22400 at 25% per year for 1 year, compounded every year (in ₹).
6. 6.Find the compound interest on ₹26000 at 10% per year for 3 years, compounded every year (in ₹).
7. 7.What is the difference between the compound interest and the simple interest on ₹36800 at 5% per year for 2 years (in ₹)?
8. 8.What is the difference between the compound interest and the simple interest on ₹47600 at 5% per year for 2 years (in ₹)?
9. 9.Find the compound interest on ₹9300 at 25% per year for 1 year, compounded every year (in ₹).
10. 10.Find the compound interest on ₹9200 at 8% per year for 1 year, compounded every year (in ₹).
11. 11.Find the compound interest on ₹34400 at 5% per year for 2 years, compounded every year (in ₹).
12. 12.What amount will ₹2900 grow to in 1 year at 12% per year compound interest (in ₹)?
13. 13.What is the difference between the compound interest and the simple interest on ₹35000 at 4% per year for 2 years (in ₹)?
14. 14.A scooter is worth ₹37600. Its value falls by 15% every year. What will it be worth after 2 years (in ₹)?
15. 15.What is the difference between the compound interest and the simple interest on ₹35900 at 10% per year for 2 years (in ₹)?
16. 16.What amount will ₹23600 grow to in 1 year at 12% per year compound interest (in ₹)?
17. 17.Find the compound interest on ₹57500 at 8% per year for 2 years, compounded every year (in ₹).
18. 18.What amount will ₹36000 grow to in 3 years at 10% per year compound interest (in ₹)?
19. 19.A scooter is worth ₹15000. Its value falls by 12% every year. What will it be worth after 2 years (in ₹)?
20. 20.Find the compound interest on ₹55400 at 12% per year for 1 year, compounded every year (in ₹).
21. 21.A town has 55200 people. The population grows by 25% every year. What will the population be after 1 year?
22. 22.A town has 29000 people. The population grows by 10% every year. What will the population be after 3 years?
23. 23.A town has 17200 people. The population grows by 5% every year. What will the population be after 2 years?
24. 24.What is the difference between the compound interest and the simple interest on ₹34400 at 5% per year for 2 years (in ₹)?
25. 25.What amount will ₹2700 grow to in 2 years at 20% per year compound interest (in ₹)?
26. 26.A scooter is worth ₹58400. Its value falls by 25% every year. What will it be worth after 2 years (in ₹)?
27. 27.What is the difference between the compound interest and the simple interest on ₹55000 at 4% per year for 2 years (in ₹)?
28. 28.What is the difference between the compound interest and the simple interest on ₹57800 at 20% per year for 2 years (in ₹)?
29. 29.A town has 26200 people. The population grows by 8% every year. What will the population be after 1 year?
30. 30.Find the compound interest on ₹38100 at 10% per year for 1 year, compounded every year (in ₹).
31. 31.What amount will ₹25600 grow to in 2 years at 25% per year compound interest (in ₹)?
32. 32.What amount will ₹4000 grow to in 2 years at 25% per year compound interest (in ₹)?
33. 33.A town has 42500 people. The population grows by 12% every year. What will the population be after 2 years?
34. 34.What is the difference between the compound interest and the simple interest on ₹27500 at 8% per year for 2 years (in ₹)?
35. 35.Find the compound interest on ₹39600 at 25% per year for 1 year, compounded every year (in ₹).
36. 36.What is the difference between the compound interest and the simple interest on ₹2400 at 5% per year for 2 years (in ₹)?
37. 37.A town has 12800 people. The population grows by 25% every year. What will the population be after 2 years?
38. 38.What is the difference between the compound interest and the simple interest on ₹38400 at 15% per year for 2 years (in ₹)?
39. 39.A town has 29100 people. The population grows by 12% every year. What will the population be after 1 year?
40. 40.Find the compound interest on ₹54000 at 5% per year for 2 years, compounded every year (in ₹).

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