Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 691 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.Find the compound interest on ₹9600 at 5% per year for 2 years, compounded every year (in ₹).
2. 2.A town has 16500 people. The population grows by 20% every year. What will the population be after 3 years?
3. 3.What amount will ₹34200 grow to in 2 years at 10% per year compound interest (in ₹)?
4. 4.Find the compound interest on ₹58400 at 25% per year for 2 years, compounded every year (in ₹).
5. 5.What amount will ₹14800 grow to in 1 year at 12% per year compound interest (in ₹)?
6. 6.Find the compound interest on ₹32000 at 25% per year for 3 years, compounded every year (in ₹).
7. 7.What is the difference between the compound interest and the simple interest on ₹21500 at 10% per year for 2 years (in ₹)?
8. 8.A town has 13600 people. The population grows by 20% every year. What will the population be after 2 years?
9. 9.What is the difference between the compound interest and the simple interest on ₹47200 at 5% per year for 2 years (in ₹)?
10. 10.Find the compound interest on ₹36900 at 10% per year for 2 years, compounded every year (in ₹).
11. 11.What is the difference between the compound interest and the simple interest on ₹7500 at 4% per year for 2 years (in ₹)?
12. 12.What amount will ₹22000 grow to in 3 years at 20% per year compound interest (in ₹)?
13. 13.What is the difference between the compound interest and the simple interest on ₹42100 at 20% per year for 2 years (in ₹)?
14. 14.Find the compound interest on ₹50000 at 8% per year for 2 years, compounded every year (in ₹).
15. 15.A scooter is worth ₹7200. Its value falls by 25% every year. What will it be worth after 2 years (in ₹)?
16. 16.What amount will ₹11100 grow to in 1 year at 12% per year compound interest (in ₹)?
17. 17.What is the difference between the compound interest and the simple interest on ₹19200 at 25% per year for 2 years (in ₹)?
18. 18.What amount will ₹10800 grow to in 2 years at 25% per year compound interest (in ₹)?
19. 19.What is the difference between the compound interest and the simple interest on ₹50000 at 25% per year for 2 years (in ₹)?
20. 20.A town has 2500 people. The population grows by 12% every year. What will the population be after 2 years?
21. 21.What is the difference between the compound interest and the simple interest on ₹50700 at 10% per year for 2 years (in ₹)?
22. 22.What is the difference between the compound interest and the simple interest on ₹57500 at 4% per year for 2 years (in ₹)?
23. 23.A scooter is worth ₹35200. Its value falls by 15% every year. What will it be worth after 2 years (in ₹)?
24. 24.What amount will ₹8600 grow to in 1 year at 12% per year compound interest (in ₹)?
25. 25.What is the difference between the compound interest and the simple interest on ₹45100 at 10% per year for 2 years (in ₹)?
26. 26.What amount will ₹29200 grow to in 1 year at 20% per year compound interest (in ₹)?
27. 27.What is the difference between the compound interest and the simple interest on ₹25000 at 8% per year for 2 years (in ₹)?
28. 28.What amount will ₹10400 grow to in 2 years at 5% per year compound interest (in ₹)?
29. 29.What amount will ₹23400 grow to in 1 year at 5% per year compound interest (in ₹)?
30. 30.What is the difference between the compound interest and the simple interest on ₹52500 at 8% per year for 2 years (in ₹)?
31. 31.Find the compound interest on ₹7500 at 4% per year for 2 years, compounded every year (in ₹).
32. 32.Find the compound interest on ₹14700 at 10% per year for 1 year, compounded every year (in ₹).
33. 33.A town has 42400 people. The population grows by 15% every year. What will the population be after 1 year?
34. 34.A town has 53500 people. The population grows by 20% every year. What will the population be after 3 years?
35. 35.What amount will ₹46800 grow to in 2 years at 15% per year compound interest (in ₹)?
36. 36.Find the compound interest on ₹42000 at 10% per year for 3 years, compounded every year (in ₹).
37. 37.A town has 42500 people. The population grows by 8% every year. What will the population be after 2 years?
38. 38.What amount will ₹9200 grow to in 1 year at 10% per year compound interest (in ₹)?
39. 39.What is the difference between the compound interest and the simple interest on ₹15000 at 12% per year for 2 years (in ₹)?
40. 40.What is the difference between the compound interest and the simple interest on ₹8600 at 20% per year for 2 years (in ₹)?

Free maths worksheets lessons, practice and worksheets at talentjr.in/maths-worksheets