Class 8 Maths Worksheet: Compound Interest
The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.
NameDateTime takenScore ___ / 40
- 1.What is the difference between the compound interest and the simple interest on ₹54600 at 20% per year for 2 years (in ₹)?
- 2.A town has 23600 people. The population grows by 25% every year. What will the population be after 2 years?
- 3.What amount will ₹22500 grow to in 3 years at 20% per year compound interest (in ₹)?
- 4.What amount will ₹40000 grow to in 3 years at 5% per year compound interest (in ₹)?
- 5.What amount will ₹50000 grow to in 2 years at 4% per year compound interest (in ₹)?
- 6.What amount will ₹24000 grow to in 3 years at 5% per year compound interest (in ₹)?
- 7.A scooter is worth ₹10000. Its value falls by 8% every year. What will it be worth after 2 years (in ₹)?
- 8.Find the compound interest on ₹55100 at 4% per year for 1 year, compounded every year (in ₹).
- 9.What amount will ₹58200 grow to in 2 years at 10% per year compound interest (in ₹)?
- 10.Find the compound interest on ₹41000 at 10% per year for 2 years, compounded every year (in ₹).
- 11.What amount will ₹11200 grow to in 2 years at 20% per year compound interest (in ₹)?
- 12.What amount will ₹44800 grow to in 2 years at 5% per year compound interest (in ₹)?
- 13.What is the difference between the compound interest and the simple interest on ₹25000 at 8% per year for 2 years (in ₹)?
- 14.What is the difference between the compound interest and the simple interest on ₹2000 at 25% per year for 2 years (in ₹)?
- 15.Find the compound interest on ₹12700 at 10% per year for 1 year, compounded every year (in ₹).
- 16.Find the compound interest on ₹46900 at 20% per year for 1 year, compounded every year (in ₹).
- 17.A town has 60000 people. The population grows by 4% every year. What will the population be after 2 years?
- 18.What is the difference between the compound interest and the simple interest on ₹5000 at 4% per year for 2 years (in ₹)?
- 19.Find the compound interest on ₹23200 at 25% per year for 2 years, compounded every year (in ₹).
- 20.A town has 51700 people. The population grows by 10% every year. What will the population be after 1 year?
- 21.A scooter is worth ₹46600. Its value falls by 25% every year. What will it be worth after 1 year (in ₹)?
- 22.What is the difference between the compound interest and the simple interest on ₹35000 at 4% per year for 2 years (in ₹)?
- 23.What is the difference between the compound interest and the simple interest on ₹14800 at 15% per year for 2 years (in ₹)?
- 24.What amount will ₹8000 grow to in 3 years at 15% per year compound interest (in ₹)?
- 25.Find the compound interest on ₹32600 at 8% per year for 1 year, compounded every year (in ₹).
- 26.Find the compound interest on ₹59300 at 20% per year for 1 year, compounded every year (in ₹).
- 27.What is the difference between the compound interest and the simple interest on ₹42500 at 4% per year for 2 years (in ₹)?
- 28.A town has 40400 people. The population grows by 8% every year. What will the population be after 1 year?
- 29.A scooter is worth ₹59900. Its value falls by 10% every year. What will it be worth after 2 years (in ₹)?
- 30.What is the difference between the compound interest and the simple interest on ₹32000 at 25% per year for 2 years (in ₹)?
- 31.What is the difference between the compound interest and the simple interest on ₹47500 at 4% per year for 2 years (in ₹)?
- 32.What is the difference between the compound interest and the simple interest on ₹27500 at 10% per year for 2 years (in ₹)?
- 33.Find the compound interest on ₹22800 at 4% per year for 1 year, compounded every year (in ₹).
- 34.What amount will ₹49200 grow to in 1 year at 5% per year compound interest (in ₹)?
- 35.What is the difference between the compound interest and the simple interest on ₹55000 at 12% per year for 2 years (in ₹)?
- 36.Find the compound interest on ₹37200 at 25% per year for 2 years, compounded every year (in ₹).
- 37.A scooter is worth ₹40700. Its value falls by 15% every year. What will it be worth after 1 year (in ₹)?
- 38.What amount will ₹30500 grow to in 1 year at 12% per year compound interest (in ₹)?
- 39.What amount will ₹30000 grow to in 1 year at 5% per year compound interest (in ₹)?
- 40.What amount will ₹16000 grow to in 3 years at 15% per year compound interest (in ₹)?
Answer key
- 2184
- 36875
- 38880
- 46305
- 54080
- 27783
- 8464
- 2204
- 70422
- 8610
- 16128
- 49392
- 160
- 125
- 1270
- 9380
- 64896
- 8
- 13050
- 56870
- 34950
- 56
- 333
- 12167
- 2608
- 11860
- 68
- 43632
- 48519
- 2000
- 76
- 275
- 912
- 51660
- 792
- 20925
- 34595
- 34160
- 31500
- 24334
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