Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 699 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.Find the compound interest on ₹27100 at 12% per year for 1 year, compounded every year (in ₹).
2. 2.What amount will ₹32000 grow to in 3 years at 5% per year compound interest (in ₹)?
3. 3.What is the difference between the compound interest and the simple interest on ₹20000 at 8% per year for 2 years (in ₹)?
4. 4.What amount will ₹32500 grow to in 2 years at 12% per year compound interest (in ₹)?
5. 5.A scooter is worth ₹56400. Its value falls by 25% every year. What will it be worth after 2 years (in ₹)?
6. 6.What amount will ₹6500 grow to in 1 year at 20% per year compound interest (in ₹)?
7. 7.What amount will ₹4900 grow to in 1 year at 4% per year compound interest (in ₹)?
8. 8.Find the compound interest on ₹28000 at 10% per year for 3 years, compounded every year (in ₹).
9. 9.A scooter is worth ₹27300. Its value falls by 20% every year. What will it be worth after 1 year (in ₹)?
10. 10.Find the compound interest on ₹25300 at 4% per year for 1 year, compounded every year (in ₹).
11. 11.Find the compound interest on ₹30000 at 4% per year for 2 years, compounded every year (in ₹).
12. 12.A town has 21600 people. The population grows by 8% every year. What will the population be after 1 year?
13. 13.A scooter is worth ₹18000. Its value falls by 10% every year. What will it be worth after 3 years (in ₹)?
14. 14.What is the difference between the compound interest and the simple interest on ₹45000 at 12% per year for 2 years (in ₹)?
15. 15.A town has 26000 people. The population grows by 10% every year. What will the population be after 3 years?
16. 16.What is the difference between the compound interest and the simple interest on ₹48000 at 25% per year for 2 years (in ₹)?
17. 17.What amount will ₹51200 grow to in 1 year at 20% per year compound interest (in ₹)?
18. 18.Find the compound interest on ₹52000 at 15% per year for 2 years, compounded every year (in ₹).
19. 19.A scooter is worth ₹4000. Its value falls by 10% every year. What will it be worth after 3 years (in ₹)?
20. 20.What amount will ₹28500 grow to in 1 year at 20% per year compound interest (in ₹)?
21. 21.Find the compound interest on ₹20800 at 25% per year for 3 years, compounded every year (in ₹).
22. 22.What is the difference between the compound interest and the simple interest on ₹60000 at 8% per year for 2 years (in ₹)?
23. 23.What amount will ₹8600 grow to in 1 year at 10% per year compound interest (in ₹)?
24. 24.Find the compound interest on ₹37700 at 5% per year for 1 year, compounded every year (in ₹).
25. 25.Find the compound interest on ₹37000 at 10% per year for 3 years, compounded every year (in ₹).
26. 26.A town has 9900 people. The population grows by 12% every year. What will the population be after 1 year?
27. 27.A town has 17600 people. The population grows by 5% every year. What will the population be after 2 years?
28. 28.What amount will ₹11300 grow to in 1 year at 12% per year compound interest (in ₹)?
29. 29.A town has 38000 people. The population grows by 10% every year. What will the population be after 3 years?
30. 30.What is the difference between the compound interest and the simple interest on ₹24000 at 25% per year for 2 years (in ₹)?
31. 31.What is the difference between the compound interest and the simple interest on ₹5600 at 10% per year for 2 years (in ₹)?
32. 32.What is the difference between the compound interest and the simple interest on ₹37600 at 15% per year for 2 years (in ₹)?
33. 33.A scooter is worth ₹8000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
34. 34.A scooter is worth ₹50000. Its value falls by 12% every year. What will it be worth after 2 years (in ₹)?
35. 35.Find the compound interest on ₹54000 at 5% per year for 2 years, compounded every year (in ₹).
36. 36.What amount will ₹43000 grow to in 1 year at 4% per year compound interest (in ₹)?
37. 37.A town has 11600 people. The population grows by 5% every year. What will the population be after 1 year?
38. 38.Find the compound interest on ₹18400 at 25% per year for 2 years, compounded every year (in ₹).
39. 39.A town has 43200 people. The population grows by 15% every year. What will the population be after 1 year?
40. 40.Find the compound interest on ₹48000 at 25% per year for 3 years, compounded every year (in ₹).

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