Class 8 Maths Worksheet: Compound Interest
The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.
NameDateTime takenScore ___ / 40
- 1.Find the compound interest on ₹42500 at 8% per year for 2 years, compounded every year (in ₹).
- 2.Find the compound interest on ₹10000 at 20% per year for 3 years, compounded every year (in ₹).
- 3.A town has 22700 people. The population grows by 10% every year. What will the population be after 2 years?
- 4.A scooter is worth ₹48000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
- 5.What is the difference between the compound interest and the simple interest on ₹37500 at 12% per year for 2 years (in ₹)?
- 6.What is the difference between the compound interest and the simple interest on ₹20000 at 5% per year for 2 years (in ₹)?
- 7.Find the compound interest on ₹30400 at 10% per year for 1 year, compounded every year (in ₹).
- 8.A town has 20000 people. The population grows by 20% every year. What will the population be after 2 years?
- 9.What amount will ₹38000 grow to in 2 years at 25% per year compound interest (in ₹)?
- 10.A scooter is worth ₹6900. Its value falls by 10% every year. What will it be worth after 2 years (in ₹)?
- 11.What is the difference between the compound interest and the simple interest on ₹52800 at 15% per year for 2 years (in ₹)?
- 12.A town has 36800 people. The population grows by 25% every year. What will the population be after 2 years?
- 13.A town has 11500 people. The population grows by 10% every year. What will the population be after 2 years?
- 14.Find the compound interest on ₹23200 at 25% per year for 2 years, compounded every year (in ₹).
- 15.A scooter is worth ₹45500. Its value falls by 20% every year. What will it be worth after 2 years (in ₹)?
- 16.What is the difference between the compound interest and the simple interest on ₹40000 at 5% per year for 2 years (in ₹)?
- 17.A scooter is worth ₹41900. Its value falls by 20% every year. What will it be worth after 2 years (in ₹)?
- 18.What is the difference between the compound interest and the simple interest on ₹44400 at 25% per year for 2 years (in ₹)?
- 19.What amount will ₹52500 grow to in 2 years at 4% per year compound interest (in ₹)?
- 20.A town has 51100 people. The population grows by 10% every year. What will the population be after 2 years?
- 21.Find the compound interest on ₹46400 at 5% per year for 1 year, compounded every year (in ₹).
- 22.What is the difference between the compound interest and the simple interest on ₹36300 at 20% per year for 2 years (in ₹)?
- 23.Find the compound interest on ₹31600 at 20% per year for 2 years, compounded every year (in ₹).
- 24.What is the difference between the compound interest and the simple interest on ₹40900 at 10% per year for 2 years (in ₹)?
- 25.Find the compound interest on ₹52500 at 4% per year for 2 years, compounded every year (in ₹).
- 26.What amount will ₹6000 grow to in 1 year at 8% per year compound interest (in ₹)?
- 27.What amount will ₹13900 grow to in 2 years at 20% per year compound interest (in ₹)?
- 28.What is the difference between the compound interest and the simple interest on ₹52500 at 8% per year for 2 years (in ₹)?
- 29.Find the compound interest on ₹59200 at 15% per year for 2 years, compounded every year (in ₹).
- 30.What amount will ₹18000 grow to in 3 years at 10% per year compound interest (in ₹)?
- 31.What amount will ₹14000 grow to in 3 years at 10% per year compound interest (in ₹)?
- 32.Find the compound interest on ₹35000 at 12% per year for 2 years, compounded every year (in ₹).
- 33.A town has 55300 people. The population grows by 8% every year. What will the population be after 1 year?
- 34.What amount will ₹32500 grow to in 2 years at 8% per year compound interest (in ₹)?
- 35.What is the difference between the compound interest and the simple interest on ₹53200 at 10% per year for 2 years (in ₹)?
- 36.What amount will ₹50000 grow to in 2 years at 8% per year compound interest (in ₹)?
- 37.A scooter is worth ₹8500. Its value falls by 20% every year. What will it be worth after 3 years (in ₹)?
- 38.A scooter is worth ₹8600. Its value falls by 15% every year. What will it be worth after 1 year (in ₹)?
- 39.What amount will ₹8000 grow to in 3 years at 5% per year compound interest (in ₹)?
- 40.What is the difference between the compound interest and the simple interest on ₹10400 at 5% per year for 2 years (in ₹)?
Answer key
- 7072
- 7280
- 27467
- 41154
- 540
- 50
- 3040
- 28800
- 59375
- 5589
- 1188
- 57500
- 13915
- 13050
- 29120
- 100
- 26816
- 2775
- 56784
- 61831
- 2320
- 1452
- 13904
- 409
- 4284
- 6480
- 20016
- 336
- 19092
- 23958
- 18634
- 8904
- 59724
- 37908
- 532
- 58320
- 4352
- 7310
- 9261
- 26
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