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Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 706 · 40 sums
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The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

NameDateTime takenScore ___ / 40
  1. 1.What amount will ₹48000 grow to in 3 years at 10% per year compound interest (in ₹)?
  2. 2.Find the compound interest on ₹58400 at 4% per year for 1 year, compounded every year (in ₹).
  3. 3.Find the compound interest on ₹11600 at 8% per year for 1 year, compounded every year (in ₹).
  4. 4.A town has 3000 people. The population grows by 20% every year. What will the population be after 3 years?
  5. 5.What is the difference between the compound interest and the simple interest on ₹22500 at 12% per year for 2 years (in ₹)?
  6. 6.What is the difference between the compound interest and the simple interest on ₹51600 at 25% per year for 2 years (in ₹)?
  7. 7.What amount will ₹4800 grow to in 1 year at 12% per year compound interest (in ₹)?
  8. 8.Find the compound interest on ₹26000 at 25% per year for 2 years, compounded every year (in ₹).
  9. 9.What is the difference between the compound interest and the simple interest on ₹53200 at 25% per year for 2 years (in ₹)?
  10. 10.What is the difference between the compound interest and the simple interest on ₹37500 at 12% per year for 2 years (in ₹)?
  11. 11.What is the difference between the compound interest and the simple interest on ₹11200 at 25% per year for 2 years (in ₹)?
  12. 12.Find the compound interest on ₹8000 at 5% per year for 3 years, compounded every year (in ₹).
  13. 13.Find the compound interest on ₹52700 at 5% per year for 1 year, compounded every year (in ₹).
  14. 14.Find the compound interest on ₹29500 at 5% per year for 1 year, compounded every year (in ₹).
  15. 15.Find the compound interest on ₹13400 at 10% per year for 2 years, compounded every year (in ₹).
  16. 16.What is the difference between the compound interest and the simple interest on ₹9600 at 10% per year for 2 years (in ₹)?
  17. 17.What is the difference between the compound interest and the simple interest on ₹27500 at 4% per year for 2 years (in ₹)?
  18. 18.Find the compound interest on ₹3500 at 5% per year for 1 year, compounded every year (in ₹).
  19. 19.Find the compound interest on ₹38300 at 12% per year for 1 year, compounded every year (in ₹).
  20. 20.A town has 12700 people. The population grows by 15% every year. What will the population be after 1 year?
  21. 21.What is the difference between the compound interest and the simple interest on ₹42500 at 4% per year for 2 years (in ₹)?
  22. 22.A scooter is worth ₹24500. Its value falls by 20% every year. What will it be worth after 1 year (in ₹)?
  23. 23.What is the difference between the compound interest and the simple interest on ₹28800 at 15% per year for 2 years (in ₹)?
  24. 24.What is the difference between the compound interest and the simple interest on ₹37600 at 15% per year for 2 years (in ₹)?
  25. 25.Find the compound interest on ₹24400 at 25% per year for 1 year, compounded every year (in ₹).
  26. 26.What amount will ₹11600 grow to in 1 year at 4% per year compound interest (in ₹)?
  27. 27.A town has 59600 people. The population grows by 5% every year. What will the population be after 2 years?
  28. 28.What amount will ₹40000 grow to in 3 years at 25% per year compound interest (in ₹)?
  29. 29.A town has 31000 people. The population grows by 10% every year. What will the population be after 3 years?
  30. 30.What amount will ₹22500 grow to in 2 years at 4% per year compound interest (in ₹)?
  31. 31.What amount will ₹8800 grow to in 2 years at 5% per year compound interest (in ₹)?
  32. 32.Find the compound interest on ₹42200 at 25% per year for 1 year, compounded every year (in ₹).
  33. 33.What amount will ₹20000 grow to in 2 years at 4% per year compound interest (in ₹)?
  34. 34.A scooter is worth ₹56000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
  35. 35.What is the difference between the compound interest and the simple interest on ₹54800 at 25% per year for 2 years (in ₹)?
  36. 36.What amount will ₹32000 grow to in 3 years at 15% per year compound interest (in ₹)?
  37. 37.Find the compound interest on ₹7100 at 25% per year for 1 year, compounded every year (in ₹).
  38. 38.A town has 5000 people. The population grows by 12% every year. What will the population be after 2 years?
  39. 39.Find the compound interest on ₹31700 at 5% per year for 1 year, compounded every year (in ₹).
  40. 40.What amount will ₹43200 grow to in 3 years at 25% per year compound interest (in ₹)?

Answer key

  1. 63888
  2. 2336
  3. 928
  4. 5184
  5. 324
  6. 3225
  7. 5376
  8. 14625
  9. 3325
  10. 540
  11. 700
  12. 1261
  13. 2635
  14. 1475
  15. 2814
  16. 96
  17. 44
  18. 175
  19. 4596
  20. 14605
  21. 68
  22. 19600
  23. 648
  24. 846
  25. 6100
  26. 12064
  27. 65709
  28. 78125
  29. 41261
  30. 24336
  31. 9702
  32. 10550
  33. 21632
  34. 48013
  35. 3425
  36. 48668
  37. 1775
  38. 6272
  39. 1585
  40. 84375

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