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Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 707 · 40 sums
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The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

NameDateTime takenScore ___ / 40
  1. 1.Find the compound interest on ₹7200 at 5% per year for 2 years, compounded every year (in ₹).
  2. 2.What amount will ₹10000 grow to in 2 years at 8% per year compound interest (in ₹)?
  3. 3.A scooter is worth ₹20400. Its value falls by 8% every year. What will it be worth after 1 year (in ₹)?
  4. 4.Find the compound interest on ₹37100 at 10% per year for 2 years, compounded every year (in ₹).
  5. 5.What amount will ₹35400 grow to in 1 year at 5% per year compound interest (in ₹)?
  6. 6.A town has 4000 people. The population grows by 10% every year. What will the population be after 3 years?
  7. 7.A scooter is worth ₹39200. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
  8. 8.What is the difference between the compound interest and the simple interest on ₹52800 at 5% per year for 2 years (in ₹)?
  9. 9.What is the difference between the compound interest and the simple interest on ₹49600 at 15% per year for 2 years (in ₹)?
  10. 10.What is the difference between the compound interest and the simple interest on ₹29300 at 20% per year for 2 years (in ₹)?
  11. 11.What is the difference between the compound interest and the simple interest on ₹46400 at 5% per year for 2 years (in ₹)?
  12. 12.Find the compound interest on ₹6500 at 20% per year for 3 years, compounded every year (in ₹).
  13. 13.A town has 12500 people. The population grows by 8% every year. What will the population be after 2 years?
  14. 14.Find the compound interest on ₹47500 at 4% per year for 2 years, compounded every year (in ₹).
  15. 15.A town has 9600 people. The population grows by 25% every year. What will the population be after 3 years?
  16. 16.Find the compound interest on ₹20200 at 20% per year for 2 years, compounded every year (in ₹).
  17. 17.What amount will ₹59100 grow to in 1 year at 20% per year compound interest (in ₹)?
  18. 18.What amount will ₹42000 grow to in 3 years at 10% per year compound interest (in ₹)?
  19. 19.What amount will ₹54800 grow to in 2 years at 5% per year compound interest (in ₹)?
  20. 20.A scooter is worth ₹28100. Its value falls by 12% every year. What will it be worth after 1 year (in ₹)?
  21. 21.What amount will ₹27200 grow to in 2 years at 5% per year compound interest (in ₹)?
  22. 22.A scooter is worth ₹51800. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
  23. 23.What is the difference between the compound interest and the simple interest on ₹47500 at 8% per year for 2 years (in ₹)?
  24. 24.Find the compound interest on ₹53400 at 15% per year for 1 year, compounded every year (in ₹).
  25. 25.A town has 16000 people. The population grows by 15% every year. What will the population be after 3 years?
  26. 26.Find the compound interest on ₹11000 at 20% per year for 3 years, compounded every year (in ₹).
  27. 27.What is the difference between the compound interest and the simple interest on ₹50800 at 25% per year for 2 years (in ₹)?
  28. 28.What amount will ₹3800 grow to in 1 year at 20% per year compound interest (in ₹)?
  29. 29.Find the compound interest on ₹32000 at 25% per year for 3 years, compounded every year (in ₹).
  30. 30.Find the compound interest on ₹45000 at 20% per year for 3 years, compounded every year (in ₹).
  31. 31.What is the difference between the compound interest and the simple interest on ₹15600 at 10% per year for 2 years (in ₹)?
  32. 32.What is the difference between the compound interest and the simple interest on ₹48400 at 25% per year for 2 years (in ₹)?
  33. 33.What amount will ₹31000 grow to in 3 years at 10% per year compound interest (in ₹)?
  34. 34.Find the compound interest on ₹11800 at 5% per year for 1 year, compounded every year (in ₹).
  35. 35.What amount will ₹16400 grow to in 2 years at 10% per year compound interest (in ₹)?
  36. 36.What amount will ₹21600 grow to in 2 years at 5% per year compound interest (in ₹)?
  37. 37.Find the compound interest on ₹28900 at 10% per year for 2 years, compounded every year (in ₹).
  38. 38.What is the difference between the compound interest and the simple interest on ₹36500 at 10% per year for 2 years (in ₹)?
  39. 39.What amount will ₹2500 grow to in 2 years at 4% per year compound interest (in ₹)?
  40. 40.What is the difference between the compound interest and the simple interest on ₹24000 at 5% per year for 2 years (in ₹)?

Answer key

  1. 738
  2. 11664
  3. 18768
  4. 7791
  5. 37170
  6. 5324
  7. 35378
  8. 132
  9. 1116
  10. 1172
  11. 116
  12. 4732
  13. 14580
  14. 3876
  15. 18750
  16. 8888
  17. 70920
  18. 55902
  19. 60417
  20. 24728
  21. 29988
  22. 49210
  23. 304
  24. 8010
  25. 24334
  26. 8008
  27. 3175
  28. 4560
  29. 30500
  30. 32760
  31. 156
  32. 3025
  33. 41261
  34. 590
  35. 19844
  36. 23814
  37. 6069
  38. 365
  39. 2704
  40. 60

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