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Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 721 · 40 sums
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The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

NameDateTime takenScore ___ / 40
  1. 1.Find the compound interest on ₹15000 at 10% per year for 1 year, compounded every year (in ₹).
  2. 2.Find the compound interest on ₹27600 at 20% per year for 1 year, compounded every year (in ₹).
  3. 3.What is the difference between the compound interest and the simple interest on ₹17500 at 12% per year for 2 years (in ₹)?
  4. 4.A scooter is worth ₹11900. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
  5. 5.A town has 48200 people. The population grows by 15% every year. What will the population be after 1 year?
  6. 6.What is the difference between the compound interest and the simple interest on ₹39600 at 25% per year for 2 years (in ₹)?
  7. 7.What amount will ₹50000 grow to in 2 years at 8% per year compound interest (in ₹)?
  8. 8.A town has 30400 people. The population grows by 25% every year. What will the population be after 3 years?
  9. 9.A town has 32800 people. The population grows by 15% every year. What will the population be after 2 years?
  10. 10.What amount will ₹5000 grow to in 2 years at 8% per year compound interest (in ₹)?
  11. 11.Find the compound interest on ₹23400 at 10% per year for 1 year, compounded every year (in ₹).
  12. 12.What amount will ₹8000 grow to in 3 years at 15% per year compound interest (in ₹)?
  13. 13.Find the compound interest on ₹4000 at 20% per year for 3 years, compounded every year (in ₹).
  14. 14.What amount will ₹32000 grow to in 3 years at 5% per year compound interest (in ₹)?
  15. 15.Find the compound interest on ₹55000 at 12% per year for 2 years, compounded every year (in ₹).
  16. 16.A town has 33300 people. The population grows by 10% every year. What will the population be after 2 years?
  17. 17.What amount will ₹19200 grow to in 3 years at 25% per year compound interest (in ₹)?
  18. 18.Find the compound interest on ₹40000 at 12% per year for 2 years, compounded every year (in ₹).
  19. 19.A scooter is worth ₹13000. Its value falls by 10% every year. What will it be worth after 3 years (in ₹)?
  20. 20.Find the compound interest on ₹57600 at 25% per year for 3 years, compounded every year (in ₹).
  21. 21.A town has 53600 people. The population grows by 5% every year. What will the population be after 2 years?
  22. 22.A town has 25000 people. The population grows by 5% every year. What will the population be after 1 year?
  23. 23.Find the compound interest on ₹46800 at 15% per year for 2 years, compounded every year (in ₹).
  24. 24.What is the difference between the compound interest and the simple interest on ₹10000 at 4% per year for 2 years (in ₹)?
  25. 25.What amount will ₹22100 grow to in 1 year at 10% per year compound interest (in ₹)?
  26. 26.What amount will ₹56000 grow to in 3 years at 5% per year compound interest (in ₹)?
  27. 27.Find the compound interest on ₹5900 at 15% per year for 1 year, compounded every year (in ₹).
  28. 28.A town has 18800 people. The population grows by 12% every year. What will the population be after 1 year?
  29. 29.A town has 44800 people. The population grows by 5% every year. What will the population be after 2 years?
  30. 30.What amount will ₹2000 grow to in 2 years at 5% per year compound interest (in ₹)?
  31. 31.A town has 56700 people. The population grows by 5% every year. What will the population be after 1 year?
  32. 32.What amount will ₹16000 grow to in 3 years at 5% per year compound interest (in ₹)?
  33. 33.A town has 57200 people. The population grows by 10% every year. What will the population be after 2 years?
  34. 34.A scooter is worth ₹57500. Its value falls by 8% every year. What will it be worth after 2 years (in ₹)?
  35. 35.What is the difference between the compound interest and the simple interest on ₹2400 at 15% per year for 2 years (in ₹)?
  36. 36.A town has 9900 people. The population grows by 15% every year. What will the population be after 1 year?
  37. 37.Find the compound interest on ₹16000 at 5% per year for 3 years, compounded every year (in ₹).
  38. 38.Find the compound interest on ₹10000 at 12% per year for 2 years, compounded every year (in ₹).
  39. 39.What amount will ₹43500 grow to in 2 years at 20% per year compound interest (in ₹)?
  40. 40.Find the compound interest on ₹55000 at 4% per year for 2 years, compounded every year (in ₹).

Answer key

  1. 1500
  2. 5520
  3. 252
  4. 11305
  5. 55430
  6. 2475
  7. 58320
  8. 59375
  9. 43378
  10. 5832
  11. 2340
  12. 12167
  13. 2912
  14. 37044
  15. 13992
  16. 40293
  17. 37500
  18. 10176
  19. 9477
  20. 54900
  21. 59094
  22. 26250
  23. 15093
  24. 16
  25. 24310
  26. 64827
  27. 885
  28. 21056
  29. 49392
  30. 2205
  31. 59535
  32. 18522
  33. 69212
  34. 48668
  35. 54
  36. 11385
  37. 2522
  38. 2544
  39. 62640
  40. 4488

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