Class 8 Maths Worksheet: Compound Interest
The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.
NameDateTime takenScore ___ / 40
- 1.Find the compound interest on ₹40000 at 5% per year for 3 years, compounded every year (in ₹).
- 2.A town has 49200 people. The population grows by 5% every year. What will the population be after 2 years?
- 3.What is the difference between the compound interest and the simple interest on ₹52500 at 12% per year for 2 years (in ₹)?
- 4.Find the compound interest on ₹11800 at 8% per year for 1 year, compounded every year (in ₹).
- 5.What is the difference between the compound interest and the simple interest on ₹58000 at 25% per year for 2 years (in ₹)?
- 6.What is the difference between the compound interest and the simple interest on ₹32400 at 25% per year for 2 years (in ₹)?
- 7.What amount will ₹27500 grow to in 2 years at 8% per year compound interest (in ₹)?
- 8.A town has 10400 people. The population grows by 10% every year. What will the population be after 1 year?
- 9.A town has 57500 people. The population grows by 8% every year. What will the population be after 2 years?
- 10.A town has 4300 people. The population grows by 10% every year. What will the population be after 1 year?
- 11.Find the compound interest on ₹36700 at 25% per year for 1 year, compounded every year (in ₹).
- 12.What is the difference between the compound interest and the simple interest on ₹6400 at 10% per year for 2 years (in ₹)?
- 13.What amount will ₹22000 grow to in 1 year at 5% per year compound interest (in ₹)?
- 14.What is the difference between the compound interest and the simple interest on ₹12500 at 4% per year for 2 years (in ₹)?
- 15.What amount will ₹24200 grow to in 1 year at 15% per year compound interest (in ₹)?
- 16.Find the compound interest on ₹47400 at 10% per year for 2 years, compounded every year (in ₹).
- 17.What amount will ₹32000 grow to in 3 years at 5% per year compound interest (in ₹)?
- 18.Find the compound interest on ₹58100 at 8% per year for 1 year, compounded every year (in ₹).
- 19.A scooter is worth ₹48400. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
- 20.Find the compound interest on ₹10000 at 8% per year for 2 years, compounded every year (in ₹).
- 21.What amount will ₹44600 grow to in 1 year at 20% per year compound interest (in ₹)?
- 22.Find the compound interest on ₹8000 at 15% per year for 3 years, compounded every year (in ₹).
- 23.What amount will ₹22400 grow to in 1 year at 25% per year compound interest (in ₹)?
- 24.What is the difference between the compound interest and the simple interest on ₹10000 at 4% per year for 2 years (in ₹)?
- 25.What is the difference between the compound interest and the simple interest on ₹40000 at 8% per year for 2 years (in ₹)?
- 26.What amount will ₹38800 grow to in 1 year at 8% per year compound interest (in ₹)?
- 27.What amount will ₹17200 grow to in 2 years at 5% per year compound interest (in ₹)?
- 28.What amount will ₹13200 grow to in 1 year at 25% per year compound interest (in ₹)?
- 29.What is the difference between the compound interest and the simple interest on ₹52000 at 5% per year for 2 years (in ₹)?
- 30.A town has 16000 people. The population grows by 5% every year. What will the population be after 3 years?
- 31.A town has 48000 people. The population grows by 5% every year. What will the population be after 3 years?
- 32.A scooter is worth ₹50000. Its value falls by 8% every year. What will it be worth after 1 year (in ₹)?
- 33.Find the compound interest on ₹19000 at 10% per year for 3 years, compounded every year (in ₹).
- 34.Find the compound interest on ₹53100 at 8% per year for 1 year, compounded every year (in ₹).
- 35.A town has 30500 people. The population grows by 4% every year. What will the population be after 1 year?
- 36.A town has 16900 people. The population grows by 20% every year. What will the population be after 2 years?
- 37.Find the compound interest on ₹8000 at 5% per year for 3 years, compounded every year (in ₹).
- 38.What amount will ₹35500 grow to in 1 year at 8% per year compound interest (in ₹)?
- 39.What amount will ₹2300 grow to in 1 year at 25% per year compound interest (in ₹)?
- 40.What is the difference between the compound interest and the simple interest on ₹30000 at 8% per year for 2 years (in ₹)?
Answer key
- 6305
- 54243
- 756
- 944
- 3625
- 2025
- 32076
- 11440
- 67068
- 4730
- 9175
- 64
- 23100
- 20
- 27830
- 9954
- 37044
- 4648
- 43681
- 1664
- 53520
- 4167
- 28000
- 16
- 256
- 41904
- 18963
- 16500
- 130
- 18522
- 55566
- 46000
- 6289
- 4248
- 31720
- 24336
- 1261
- 38340
- 2875
- 192
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