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Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 725 · 40 sums
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The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

NameDateTime takenScore ___ / 40
  1. 1.Find the compound interest on ₹40000 at 5% per year for 3 years, compounded every year (in ₹).
  2. 2.A town has 49200 people. The population grows by 5% every year. What will the population be after 2 years?
  3. 3.What is the difference between the compound interest and the simple interest on ₹52500 at 12% per year for 2 years (in ₹)?
  4. 4.Find the compound interest on ₹11800 at 8% per year for 1 year, compounded every year (in ₹).
  5. 5.What is the difference between the compound interest and the simple interest on ₹58000 at 25% per year for 2 years (in ₹)?
  6. 6.What is the difference between the compound interest and the simple interest on ₹32400 at 25% per year for 2 years (in ₹)?
  7. 7.What amount will ₹27500 grow to in 2 years at 8% per year compound interest (in ₹)?
  8. 8.A town has 10400 people. The population grows by 10% every year. What will the population be after 1 year?
  9. 9.A town has 57500 people. The population grows by 8% every year. What will the population be after 2 years?
  10. 10.A town has 4300 people. The population grows by 10% every year. What will the population be after 1 year?
  11. 11.Find the compound interest on ₹36700 at 25% per year for 1 year, compounded every year (in ₹).
  12. 12.What is the difference between the compound interest and the simple interest on ₹6400 at 10% per year for 2 years (in ₹)?
  13. 13.What amount will ₹22000 grow to in 1 year at 5% per year compound interest (in ₹)?
  14. 14.What is the difference between the compound interest and the simple interest on ₹12500 at 4% per year for 2 years (in ₹)?
  15. 15.What amount will ₹24200 grow to in 1 year at 15% per year compound interest (in ₹)?
  16. 16.Find the compound interest on ₹47400 at 10% per year for 2 years, compounded every year (in ₹).
  17. 17.What amount will ₹32000 grow to in 3 years at 5% per year compound interest (in ₹)?
  18. 18.Find the compound interest on ₹58100 at 8% per year for 1 year, compounded every year (in ₹).
  19. 19.A scooter is worth ₹48400. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
  20. 20.Find the compound interest on ₹10000 at 8% per year for 2 years, compounded every year (in ₹).
  21. 21.What amount will ₹44600 grow to in 1 year at 20% per year compound interest (in ₹)?
  22. 22.Find the compound interest on ₹8000 at 15% per year for 3 years, compounded every year (in ₹).
  23. 23.What amount will ₹22400 grow to in 1 year at 25% per year compound interest (in ₹)?
  24. 24.What is the difference between the compound interest and the simple interest on ₹10000 at 4% per year for 2 years (in ₹)?
  25. 25.What is the difference between the compound interest and the simple interest on ₹40000 at 8% per year for 2 years (in ₹)?
  26. 26.What amount will ₹38800 grow to in 1 year at 8% per year compound interest (in ₹)?
  27. 27.What amount will ₹17200 grow to in 2 years at 5% per year compound interest (in ₹)?
  28. 28.What amount will ₹13200 grow to in 1 year at 25% per year compound interest (in ₹)?
  29. 29.What is the difference between the compound interest and the simple interest on ₹52000 at 5% per year for 2 years (in ₹)?
  30. 30.A town has 16000 people. The population grows by 5% every year. What will the population be after 3 years?
  31. 31.A town has 48000 people. The population grows by 5% every year. What will the population be after 3 years?
  32. 32.A scooter is worth ₹50000. Its value falls by 8% every year. What will it be worth after 1 year (in ₹)?
  33. 33.Find the compound interest on ₹19000 at 10% per year for 3 years, compounded every year (in ₹).
  34. 34.Find the compound interest on ₹53100 at 8% per year for 1 year, compounded every year (in ₹).
  35. 35.A town has 30500 people. The population grows by 4% every year. What will the population be after 1 year?
  36. 36.A town has 16900 people. The population grows by 20% every year. What will the population be after 2 years?
  37. 37.Find the compound interest on ₹8000 at 5% per year for 3 years, compounded every year (in ₹).
  38. 38.What amount will ₹35500 grow to in 1 year at 8% per year compound interest (in ₹)?
  39. 39.What amount will ₹2300 grow to in 1 year at 25% per year compound interest (in ₹)?
  40. 40.What is the difference between the compound interest and the simple interest on ₹30000 at 8% per year for 2 years (in ₹)?

Answer key

  1. 6305
  2. 54243
  3. 756
  4. 944
  5. 3625
  6. 2025
  7. 32076
  8. 11440
  9. 67068
  10. 4730
  11. 9175
  12. 64
  13. 23100
  14. 20
  15. 27830
  16. 9954
  17. 37044
  18. 4648
  19. 43681
  20. 1664
  21. 53520
  22. 4167
  23. 28000
  24. 16
  25. 256
  26. 41904
  27. 18963
  28. 16500
  29. 130
  30. 18522
  31. 55566
  32. 46000
  33. 6289
  34. 4248
  35. 31720
  36. 24336
  37. 1261
  38. 38340
  39. 2875
  40. 192

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