Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 726 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.A town has 12900 people. The population grows by 10% every year. What will the population be after 2 years?
2. 2.A town has 4000 people. The population grows by 8% every year. What will the population be after 1 year?
3. 3.What amount will ₹38400 grow to in 2 years at 25% per year compound interest (in ₹)?
4. 4.Find the compound interest on ₹32000 at 25% per year for 3 years, compounded every year (in ₹).
5. 5.Find the compound interest on ₹46100 at 5% per year for 1 year, compounded every year (in ₹).
6. 6.Find the compound interest on ₹51900 at 8% per year for 1 year, compounded every year (in ₹).
7. 7.A town has 51400 people. The population grows by 12% every year. What will the population be after 1 year?
8. 8.What is the difference between the compound interest and the simple interest on ₹18700 at 20% per year for 2 years (in ₹)?
9. 9.Find the compound interest on ₹55000 at 8% per year for 2 years, compounded every year (in ₹).
10. 10.What is the difference between the compound interest and the simple interest on ₹23600 at 25% per year for 2 years (in ₹)?
11. 11.Find the compound interest on ₹42300 at 10% per year for 1 year, compounded every year (in ₹).
12. 12.What amount will ₹15500 grow to in 3 years at 20% per year compound interest (in ₹)?
13. 13.What is the difference between the compound interest and the simple interest on ₹20400 at 5% per year for 2 years (in ₹)?
14. 14.What amount will ₹10000 grow to in 2 years at 8% per year compound interest (in ₹)?
15. 15.A town has 19400 people. The population grows by 10% every year. What will the population be after 1 year?
16. 16.What amount will ₹16000 grow to in 3 years at 5% per year compound interest (in ₹)?
17. 17.What amount will ₹58800 grow to in 2 years at 15% per year compound interest (in ₹)?
18. 18.Find the compound interest on ₹40000 at 20% per year for 1 year, compounded every year (in ₹).
19. 19.Find the compound interest on ₹21200 at 5% per year for 1 year, compounded every year (in ₹).
20. 20.What is the difference between the compound interest and the simple interest on ₹14400 at 25% per year for 2 years (in ₹)?
21. 21.Find the compound interest on ₹46000 at 15% per year for 2 years, compounded every year (in ₹).
22. 22.What amount will ₹13500 grow to in 1 year at 10% per year compound interest (in ₹)?
23. 23.Find the compound interest on ₹15000 at 12% per year for 2 years, compounded every year (in ₹).
24. 24.What amount will ₹51600 grow to in 2 years at 5% per year compound interest (in ₹)?
25. 25.Find the compound interest on ₹42900 at 12% per year for 1 year, compounded every year (in ₹).
26. 26.What amount will ₹12500 grow to in 2 years at 4% per year compound interest (in ₹)?
27. 27.Find the compound interest on ₹40000 at 15% per year for 3 years, compounded every year (in ₹).
28. 28.What is the difference between the compound interest and the simple interest on ₹26700 at 10% per year for 2 years (in ₹)?
29. 29.What amount will ₹32200 grow to in 1 year at 10% per year compound interest (in ₹)?
30. 30.What is the difference between the compound interest and the simple interest on ₹30000 at 15% per year for 2 years (in ₹)?
31. 31.What is the difference between the compound interest and the simple interest on ₹39300 at 10% per year for 2 years (in ₹)?
32. 32.A scooter is worth ₹57600. Its value falls by 12% every year. What will it be worth after 1 year (in ₹)?
33. 33.Find the compound interest on ₹60000 at 12% per year for 2 years, compounded every year (in ₹).
34. 34.A town has 45200 people. The population grows by 4% every year. What will the population be after 1 year?
35. 35.What is the difference between the compound interest and the simple interest on ₹15500 at 20% per year for 2 years (in ₹)?
36. 36.What amount will ₹28000 grow to in 3 years at 10% per year compound interest (in ₹)?
37. 37.A town has 57500 people. The population grows by 8% every year. What will the population be after 2 years?
38. 38.What is the difference between the compound interest and the simple interest on ₹47200 at 5% per year for 2 years (in ₹)?
39. 39.What is the difference between the compound interest and the simple interest on ₹14800 at 25% per year for 2 years (in ₹)?
40. 40.A scooter is worth ₹22800. Its value falls by 15% every year. What will it be worth after 2 years (in ₹)?

Free maths worksheets lessons, practice and worksheets at talentjr.in/maths-worksheets