Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 727 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.Find the compound interest on ₹39600 at 10% per year for 2 years, compounded every year (in ₹).
2. 2.What amount will ₹24300 grow to in 1 year at 10% per year compound interest (in ₹)?
3. 3.A scooter is worth ₹55900. Its value falls by 15% every year. What will it be worth after 1 year (in ₹)?
4. 4.A scooter is worth ₹30300. Its value falls by 12% every year. What will it be worth after 1 year (in ₹)?
5. 5.What is the difference between the compound interest and the simple interest on ₹2500 at 4% per year for 2 years (in ₹)?
6. 6.What amount will ₹32500 grow to in 2 years at 8% per year compound interest (in ₹)?
7. 7.Find the compound interest on ₹28000 at 10% per year for 3 years, compounded every year (in ₹).
8. 8.Find the compound interest on ₹7000 at 10% per year for 3 years, compounded every year (in ₹).
9. 9.A town has 60000 people. The population grows by 12% every year. What will the population be after 2 years?
10. 10.What is the difference between the compound interest and the simple interest on ₹49600 at 5% per year for 2 years (in ₹)?
11. 11.What is the difference between the compound interest and the simple interest on ₹56000 at 25% per year for 2 years (in ₹)?
12. 12.A town has 19300 people. The population grows by 5% every year. What will the population be after 1 year?
13. 13.What amount will ₹17100 grow to in 1 year at 15% per year compound interest (in ₹)?
14. 14.What is the difference between the compound interest and the simple interest on ₹56400 at 15% per year for 2 years (in ₹)?
15. 15.A town has 26400 people. The population grows by 20% every year. What will the population be after 2 years?
16. 16.A scooter is worth ₹38800. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
17. 17.A scooter is worth ₹41700. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
18. 18.Find the compound interest on ₹7500 at 8% per year for 2 years, compounded every year (in ₹).
19. 19.What amount will ₹35700 grow to in 1 year at 10% per year compound interest (in ₹)?
20. 20.What is the difference between the compound interest and the simple interest on ₹10000 at 4% per year for 2 years (in ₹)?
21. 21.A town has 45200 people. The population grows by 10% every year. What will the population be after 1 year?
22. 22.Find the compound interest on ₹47500 at 12% per year for 2 years, compounded every year (in ₹).
23. 23.Find the compound interest on ₹58100 at 10% per year for 1 year, compounded every year (in ₹).
24. 24.Find the compound interest on ₹22500 at 4% per year for 2 years, compounded every year (in ₹).
25. 25.A town has 23600 people. The population grows by 5% every year. What will the population be after 1 year?
26. 26.Find the compound interest on ₹54000 at 10% per year for 3 years, compounded every year (in ₹).
27. 27.What is the difference between the compound interest and the simple interest on ₹43400 at 20% per year for 2 years (in ₹)?
28. 28.A town has 5000 people. The population grows by 10% every year. What will the population be after 1 year?
29. 29.Find the compound interest on ₹23200 at 15% per year for 2 years, compounded every year (in ₹).
30. 30.A town has 12500 people. The population grows by 20% every year. What will the population be after 3 years?
31. 31.A scooter is worth ₹16000. Its value falls by 25% every year. What will it be worth after 1 year (in ₹)?
32. 32.What amount will ₹8000 grow to in 3 years at 15% per year compound interest (in ₹)?
33. 33.What is the difference between the compound interest and the simple interest on ₹52800 at 15% per year for 2 years (in ₹)?
34. 34.What is the difference between the compound interest and the simple interest on ₹20000 at 4% per year for 2 years (in ₹)?
35. 35.Find the compound interest on ₹24000 at 15% per year for 2 years, compounded every year (in ₹).
36. 36.A town has 20000 people. The population grows by 4% every year. What will the population be after 2 years?
37. 37.What amount will ₹53000 grow to in 1 year at 20% per year compound interest (in ₹)?
38. 38.A scooter is worth ₹45000. Its value falls by 12% every year. What will it be worth after 2 years (in ₹)?
39. 39.Find the compound interest on ₹42800 at 5% per year for 2 years, compounded every year (in ₹).
40. 40.A town has 20000 people. The population grows by 12% every year. What will the population be after 2 years?

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