Class 8 Maths Worksheet: Compound Interest
The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.
NameDateTime takenScore ___ / 40
- 1.A scooter is worth ₹54400. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
- 2.Find the compound interest on ₹44400 at 25% per year for 2 years, compounded every year (in ₹).
- 3.Find the compound interest on ₹36700 at 10% per year for 1 year, compounded every year (in ₹).
- 4.What amount will ₹35000 grow to in 2 years at 8% per year compound interest (in ₹)?
- 5.What is the difference between the compound interest and the simple interest on ₹51200 at 25% per year for 2 years (in ₹)?
- 6.A town has 2500 people. The population grows by 12% every year. What will the population be after 2 years?
- 7.Find the compound interest on ₹52900 at 12% per year for 1 year, compounded every year (in ₹).
- 8.What is the difference between the compound interest and the simple interest on ₹48300 at 20% per year for 2 years (in ₹)?
- 9.A scooter is worth ₹27200. Its value falls by 25% every year. What will it be worth after 3 years (in ₹)?
- 10.A scooter is worth ₹4200. Its value falls by 4% every year. What will it be worth after 1 year (in ₹)?
- 11.What amount will ₹43300 grow to in 1 year at 10% per year compound interest (in ₹)?
- 12.What is the difference between the compound interest and the simple interest on ₹30000 at 12% per year for 2 years (in ₹)?
- 13.Find the compound interest on ₹41100 at 8% per year for 1 year, compounded every year (in ₹).
- 14.What amount will ₹20500 grow to in 1 year at 4% per year compound interest (in ₹)?
- 15.What is the difference between the compound interest and the simple interest on ₹5000 at 8% per year for 2 years (in ₹)?
- 16.Find the compound interest on ₹12100 at 10% per year for 2 years, compounded every year (in ₹).
- 17.A town has 27200 people. The population grows by 25% every year. What will the population be after 3 years?
- 18.Find the compound interest on ₹14500 at 20% per year for 3 years, compounded every year (in ₹).
- 19.Find the compound interest on ₹60000 at 25% per year for 1 year, compounded every year (in ₹).
- 20.Find the compound interest on ₹16000 at 5% per year for 3 years, compounded every year (in ₹).
- 21.What is the difference between the compound interest and the simple interest on ₹56000 at 15% per year for 2 years (in ₹)?
- 22.A town has 5200 people. The population grows by 25% every year. What will the population be after 2 years?
- 23.Find the compound interest on ₹5500 at 10% per year for 2 years, compounded every year (in ₹).
- 24.A scooter is worth ₹5000. Its value falls by 4% every year. What will it be worth after 2 years (in ₹)?
- 25.What amount will ₹52900 grow to in 1 year at 5% per year compound interest (in ₹)?
- 26.A town has 16400 people. The population grows by 15% every year. What will the population be after 2 years?
- 27.What amount will ₹53300 grow to in 1 year at 12% per year compound interest (in ₹)?
- 28.What amount will ₹54200 grow to in 1 year at 15% per year compound interest (in ₹)?
- 29.A town has 34000 people. The population grows by 20% every year. What will the population be after 3 years?
- 30.A town has 3500 people. The population grows by 12% every year. What will the population be after 1 year?
- 31.Find the compound interest on ₹13000 at 25% per year for 1 year, compounded every year (in ₹).
- 32.What amount will ₹30000 grow to in 2 years at 8% per year compound interest (in ₹)?
- 33.A scooter is worth ₹25000. Its value falls by 8% every year. What will it be worth after 2 years (in ₹)?
- 34.Find the compound interest on ₹45600 at 5% per year for 2 years, compounded every year (in ₹).
- 35.What is the difference between the compound interest and the simple interest on ₹55700 at 20% per year for 2 years (in ₹)?
- 36.A town has 50900 people. The population grows by 10% every year. What will the population be after 2 years?
- 37.What amount will ₹14700 grow to in 1 year at 10% per year compound interest (in ₹)?
- 38.What is the difference between the compound interest and the simple interest on ₹40000 at 4% per year for 2 years (in ₹)?
- 39.A scooter is worth ₹56000. Its value falls by 15% every year. What will it be worth after 3 years (in ₹)?
- 40.A town has 53900 people. The population grows by 12% every year. What will the population be after 1 year?
Answer key
- 49096
- 24975
- 3670
- 40824
- 3200
- 3136
- 6348
- 1932
- 11475
- 4032
- 47630
- 432
- 3288
- 21320
- 32
- 2541
- 53125
- 10556
- 15000
- 2522
- 1260
- 8125
- 1155
- 4608
- 55545
- 21689
- 59696
- 62330
- 58752
- 3920
- 3250
- 34992
- 21160
- 4674
- 2228
- 61589
- 16170
- 64
- 34391
- 60368
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