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Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 740 · 40 sums
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The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

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  1. 1.A town has 40000 people. The population grows by 5% every year. What will the population be after 3 years?
  2. 2.What amount will ₹5200 grow to in 2 years at 15% per year compound interest (in ₹)?
  3. 3.A town has 8900 people. The population grows by 4% every year. What will the population be after 1 year?
  4. 4.What amount will ₹52000 grow to in 3 years at 10% per year compound interest (in ₹)?
  5. 5.Find the compound interest on ₹24000 at 5% per year for 3 years, compounded every year (in ₹).
  6. 6.Find the compound interest on ₹45600 at 5% per year for 1 year, compounded every year (in ₹).
  7. 7.Find the compound interest on ₹3900 at 5% per year for 1 year, compounded every year (in ₹).
  8. 8.What amount will ₹19600 grow to in 1 year at 12% per year compound interest (in ₹)?
  9. 9.A town has 29600 people. The population grows by 25% every year. What will the population be after 2 years?
  10. 10.Find the compound interest on ₹21000 at 10% per year for 3 years, compounded every year (in ₹).
  11. 11.What is the difference between the compound interest and the simple interest on ₹8000 at 5% per year for 2 years (in ₹)?
  12. 12.What amount will ₹11600 grow to in 1 year at 5% per year compound interest (in ₹)?
  13. 13.Find the compound interest on ₹29900 at 25% per year for 1 year, compounded every year (in ₹).
  14. 14.What is the difference between the compound interest and the simple interest on ₹37500 at 12% per year for 2 years (in ₹)?
  15. 15.What is the difference between the compound interest and the simple interest on ₹12600 at 10% per year for 2 years (in ₹)?
  16. 16.Find the compound interest on ₹14800 at 25% per year for 2 years, compounded every year (in ₹).
  17. 17.A scooter is worth ₹27500. Its value falls by 4% every year. What will it be worth after 2 years (in ₹)?
  18. 18.What is the difference between the compound interest and the simple interest on ₹51600 at 5% per year for 2 years (in ₹)?
  19. 19.What is the difference between the compound interest and the simple interest on ₹50700 at 10% per year for 2 years (in ₹)?
  20. 20.A town has 36000 people. The population grows by 20% every year. What will the population be after 2 years?
  21. 21.What amount will ₹7600 grow to in 2 years at 15% per year compound interest (in ₹)?
  22. 22.Find the compound interest on ₹58000 at 5% per year for 2 years, compounded every year (in ₹).
  23. 23.What is the difference between the compound interest and the simple interest on ₹17400 at 20% per year for 2 years (in ₹)?
  24. 24.Find the compound interest on ₹29500 at 4% per year for 1 year, compounded every year (in ₹).
  25. 25.What is the difference between the compound interest and the simple interest on ₹20000 at 8% per year for 2 years (in ₹)?
  26. 26.What is the difference between the compound interest and the simple interest on ₹40000 at 5% per year for 2 years (in ₹)?
  27. 27.Find the compound interest on ₹18400 at 5% per year for 2 years, compounded every year (in ₹).
  28. 28.A town has 46100 people. The population grows by 10% every year. What will the population be after 1 year?
  29. 29.What is the difference between the compound interest and the simple interest on ₹60000 at 12% per year for 2 years (in ₹)?
  30. 30.Find the compound interest on ₹56000 at 5% per year for 3 years, compounded every year (in ₹).
  31. 31.A scooter is worth ₹24900. Its value falls by 20% every year. What will it be worth after 2 years (in ₹)?
  32. 32.A town has 54500 people. The population grows by 10% every year. What will the population be after 2 years?
  33. 33.What amount will ₹2900 grow to in 2 years at 10% per year compound interest (in ₹)?
  34. 34.What amount will ₹1600 grow to in 3 years at 25% per year compound interest (in ₹)?
  35. 35.What amount will ₹32500 grow to in 2 years at 12% per year compound interest (in ₹)?
  36. 36.What amount will ₹45600 grow to in 2 years at 25% per year compound interest (in ₹)?
  37. 37.What is the difference between the compound interest and the simple interest on ₹5000 at 12% per year for 2 years (in ₹)?
  38. 38.Find the compound interest on ₹55000 at 12% per year for 2 years, compounded every year (in ₹).
  39. 39.A town has 26000 people. The population grows by 12% every year. What will the population be after 1 year?
  40. 40.A scooter is worth ₹35100. Its value falls by 15% every year. What will it be worth after 1 year (in ₹)?

Answer key

  1. 46305
  2. 6877
  3. 9256
  4. 69212
  5. 3783
  6. 2280
  7. 195
  8. 21952
  9. 46250
  10. 6951
  11. 20
  12. 12180
  13. 7475
  14. 540
  15. 126
  16. 8325
  17. 25344
  18. 129
  19. 507
  20. 51840
  21. 10051
  22. 5945
  23. 696
  24. 1180
  25. 128
  26. 100
  27. 1886
  28. 50710
  29. 864
  30. 8827
  31. 15936
  32. 65945
  33. 3509
  34. 3125
  35. 40768
  36. 71250
  37. 72
  38. 13992
  39. 29120
  40. 29835

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