Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 744 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.A scooter is worth ₹21100. Its value falls by 10% every year. What will it be worth after 2 years (in ₹)?
2. 2.What is the difference between the compound interest and the simple interest on ₹16800 at 15% per year for 2 years (in ₹)?
3. 3.What is the difference between the compound interest and the simple interest on ₹7500 at 12% per year for 2 years (in ₹)?
4. 4.What amount will ₹23200 grow to in 1 year at 15% per year compound interest (in ₹)?
5. 5.Find the compound interest on ₹47100 at 25% per year for 1 year, compounded every year (in ₹).
6. 6.A town has 55000 people. The population grows by 4% every year. What will the population be after 2 years?
7. 7.What amount will ₹8800 grow to in 2 years at 25% per year compound interest (in ₹)?
8. 8.What is the difference between the compound interest and the simple interest on ₹51200 at 20% per year for 2 years (in ₹)?
9. 9.What is the difference between the compound interest and the simple interest on ₹20000 at 12% per year for 2 years (in ₹)?
10. 10.A scooter is worth ₹9300. Its value falls by 8% every year. What will it be worth after 1 year (in ₹)?
11. 11.What amount will ₹40300 grow to in 1 year at 4% per year compound interest (in ₹)?
12. 12.What amount will ₹6000 grow to in 3 years at 10% per year compound interest (in ₹)?
13. 13.A town has 58800 people. The population grows by 15% every year. What will the population be after 2 years?
14. 14.What amount will ₹9600 grow to in 3 years at 25% per year compound interest (in ₹)?
15. 15.A scooter is worth ₹59100. Its value falls by 25% every year. What will it be worth after 1 year (in ₹)?
16. 16.A town has 58000 people. The population grows by 20% every year. What will the population be after 3 years?
17. 17.A scooter is worth ₹26200. Its value falls by 10% every year. What will it be worth after 2 years (in ₹)?
18. 18.What is the difference between the compound interest and the simple interest on ₹37600 at 5% per year for 2 years (in ₹)?
19. 19.What amount will ₹16000 grow to in 3 years at 5% per year compound interest (in ₹)?
20. 20.Find the compound interest on ₹15800 at 12% per year for 1 year, compounded every year (in ₹).
21. 21.What amount will ₹9800 grow to in 1 year at 4% per year compound interest (in ₹)?
22. 22.What amount will ₹54500 grow to in 1 year at 12% per year compound interest (in ₹)?
23. 23.What amount will ₹10000 grow to in 1 year at 10% per year compound interest (in ₹)?
24. 24.Find the compound interest on ₹57500 at 20% per year for 3 years, compounded every year (in ₹).
25. 25.Find the compound interest on ₹54300 at 12% per year for 1 year, compounded every year (in ₹).
26. 26.Find the compound interest on ₹6700 at 20% per year for 2 years, compounded every year (in ₹).
27. 27.Find the compound interest on ₹14000 at 10% per year for 3 years, compounded every year (in ₹).
28. 28.A town has 35400 people. The population grows by 20% every year. What will the population be after 2 years?
29. 29.What is the difference between the compound interest and the simple interest on ₹58200 at 10% per year for 2 years (in ₹)?
30. 30.What is the difference between the compound interest and the simple interest on ₹45000 at 8% per year for 2 years (in ₹)?
31. 31.Find the compound interest on ₹51900 at 25% per year for 1 year, compounded every year (in ₹).
32. 32.A scooter is worth ₹52500. Its value falls by 8% every year. What will it be worth after 2 years (in ₹)?
33. 33.What amount will ₹16200 grow to in 1 year at 20% per year compound interest (in ₹)?
34. 34.Find the compound interest on ₹46400 at 15% per year for 2 years, compounded every year (in ₹).
35. 35.What is the difference between the compound interest and the simple interest on ₹5000 at 8% per year for 2 years (in ₹)?
36. 36.Find the compound interest on ₹30600 at 12% per year for 1 year, compounded every year (in ₹).
37. 37.A scooter is worth ₹10000. Its value falls by 12% every year. What will it be worth after 2 years (in ₹)?
38. 38.Find the compound interest on ₹28300 at 20% per year for 2 years, compounded every year (in ₹).
39. 39.What is the difference between the compound interest and the simple interest on ₹20000 at 4% per year for 2 years (in ₹)?
40. 40.What is the difference between the compound interest and the simple interest on ₹34400 at 10% per year for 2 years (in ₹)?

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